Grade 3 Roman Numerals Worksheet: Addition and Subtraction Practice

Let’s solve each problem step by step. We’ll convert Roman numerals to regular numbers, do the math, then convert back if needed — but since all answers are sums or differences, we can just compute them as regular numbers and write the final answer in Roman numerals only if required. But looking at the worksheet, it says “Find the sum” — so we’re adding or subtracting Roman numerals and writing the result as a number (probably still in Roman numerals? Wait — actually, let’s check: the problems are written with Roman numerals, but the instruction doesn’t specify output format. However, in Grade 3 worksheets like this, they usually expect the answer in Roman numerals too. But wait — looking again: the problems are like “XXI – VI =”, and students are expected to compute and write the answer — likely in Roman numerals. BUT — actually, many such worksheets accept Arabic numerals for simplicity at this level. Hmm.

Wait — let me think: The title is “Addition and Subtraction with Roman Numerals”, and it’s Grade 3. Typically, at this level, students learn to convert Roman numerals to Arabic, do the math, and sometimes convert back. But since the problems are presented in Roman numerals and no specific instruction says “write answer in Roman numerals”, and given that converting back might be advanced for some Grade 3 students, I suspect the expected answer is in Arabic numerals. However, to be safe, let’s look at common practice: In most K-5 worksheets titled like this, especially from k5learning.com (as seen in footer), they often expect the answer in Roman numerals. But actually — checking similar worksheets online — many have students write the answer in Roman numerals. Let me verify with one example:

Problem 1: XXI – VI
XXI = 21, VI = 6 → 21 - 6 = 15 → XV

But if the student writes “15”, is that acceptable? Probably not — because the whole point is practicing Roman numerals. So I will assume the answer should be in Roman numerals.

However — wait! Looking at the worksheet again: It says “Find the sum.” — but some are subtractions. That’s odd. Maybe it’s a generic term. Anyway, let’s proceed by computing each as Arabic numbers, then convert the result to Roman numerals.

I’ll go one by one.

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1. XXI – VI

XXI = 20 + 1 = 21
VI = 5 + 1 = 6
21 - 6 = 15 → XV

✔ Answer: XV

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2. II + XXXVI

II = 2
XXXVI = 30 + 6 = 36
2 + 36 = 38 → XXXVIII

✔ Answer: XXXVIII

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3. XXXII – XVII + XVIII

First, XXXII = 32
XVII = 17
XVIII = 18

So: 32 - 17 = 15; then 15 + 18 = 33 → XXXIII

✔ Answer: XXXIII

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4. XXIV – IX

XXIV = 24
IX = 9
24 - 9 = 15 → XV

✔ Answer: XV

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5. XLIV – XIV

XLIV = 44 (XL=40, IV=4)
XIV = 14
44 - 14 = 30 → XXX

✔ Answer: XXX

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6. XXXIX + II

XXXIX = 39 (XXX=30, IX=9)
II = 2
39 + 2 = 41 → XLI

✔ Answer: XLI

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7. XXI – XI + XXI

XXI = 21
XI = 11
So: 21 - 11 = 10; then 10 + 21 = 31 → XXXI

✔ Answer: XXXI

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8. VII + XXIV – VII

VII = 7
XXIV = 24
So: 7 + 24 = 31; then 31 - 7 = 24 → XXIV

Notice: +VII and -VII cancel out → left with XXIV

✔ Answer: XXIV

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9. IX + XXX + V

IX = 9
XXX = 30
V = 5
9 + 30 = 39; 39 + 5 = 44 → XLIV

✔ Answer: XLIV

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10. XXIV – XV + XXIII

XXIV = 24
XV = 15
XXIII = 23

24 - 15 = 9; 9 + 23 = 32 → XXXII

✔ Answer: XXXII

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11. XVI – XIV

XVI = 16
XIV = 14
16 - 14 = 2 → II

✔ Answer: II

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12. XLVI – XLII

XLVI = 46 (XL=40, VI=6)
XLII = 42 (XL=40, II=2)
46 - 42 = 4 → IV

✔ Answer: IV

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13. I + XXX – XVII

I = 1
XXX = 30
XVII = 17

1 + 30 = 31; 31 - 17 = 14 → XIV

✔ Answer: XIV

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Now, let’s list all answers in order:

1. XV
2. XXXVIII
3. XXXIII
4. XV
5. XXX
6. XLI
7. XXXI
8. XXIV
9. XLIV
10. XXXII
11. II
12. IV
13. XIV

Wait — the worksheet has 14 problems? Let me count the original:

Looking back:

It shows:

1. XXI – VI =
2. II + XXXVI =
3. XXXII – XVII + XVIII =
4. XXIV – IX =
5. XLIV – XIV =
6. XXXIX + II =
7. XXI – XI + XXI =
8. VII + XXIV – VII =
9. IX + XXX + V =
10. XXIV – XV + XXIII =
11. XVI – XIV =
12. XLVI – XLII =
13. I + XXX – XVII =

That’s 13 problems. But in the image layout, it's two columns: left column has 1,3,5,7,9,11,13 → 7 problems; right column has 2,4,6,8,10,12 → 6 problems? Wait, no — let me recount based on numbering:

In the image description, it lists:

Left side:
1. XXI – VI =
3. II + XXXVI = ← wait, that can't be — probably misnumbered in my reading.

Actually, looking at the user’s text representation:

They wrote:

"1. XXI – VI =
2. XXXIX – XII =
3. II + XXXVI =
4. XXIV – IX =
5. XXXII – XVII + XVIII =
6. XLVIII – XIV =
7. XLIV – XIV =
8. XXXII – XXVI =
9. XXXIX + II =
10. VII + XXIV – VII =
11. XXI – XI + XXI =
12. XXIV – XV + XXIII =
13. IX + XXX + V =
14. XVI – XIV =
15. XLVI – XLII =
16. I + XXX – XVII ="

Oh! I see — in the initial problem statement, the user included more than what I first thought. Let me re-read the user’s input.

User said:

“Find the sum:

1. XXI – VI =
2. XXXIX – XII =
3. II + XXXVI =
4. XXIV – IX =
5. XXXII – XVII + XVIII =
6. XLVIII – XIV =
7. XLIV – XIV =
8. XXXII – XXVI =
9. XXXIX + II =
10. VII + XXIV – VII =
11. XXI – XI + XXI =
12. XXIV – XV + XXIII =
13. IX + XXX + V =
14. XVI – XIV =
15. XLVI – XLII =
16. I + XXX – XVII =”

Ah! There are 16 problems. I missed some earlier. My apologies. Let me correct and solve all 16 properly.

I’ll redo all 16 carefully.

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1. XXI – VI

XXI = 21, VI = 6 → 21 - 6 = 15 → XV

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2. XXXIX – XII

XXXIX = 39, XII = 12 → 39 - 12 = 27 → XXVII

(20 + 7 = XXVII)

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3. II + XXXVI

II = 2, XXXVI = 36 → 2 + 36 = 38 → XXXVIII

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4. XXIV – IX

XXIV = 24, IX = 9 → 24 - 9 = 15 → XV

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5. XXXII – XVII + XVIII

XXXII = 32, XVII = 17, XVIII = 18
32 - 17 = 15; 15 + 18 = 33 → XXXIII

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6. XLVIII – XIV

XLVIII = 48 (XL=40, VIII=8), XIV = 14 → 48 - 14 = 34 → XXXIV

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7. XLIV – XIV

XLIV = 44, XIV = 14 → 44 - 14 = 30 → XXX

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8. XXXII – XXVI

XXXII = 32, XXVI = 26 → 32 - 26 = 6 → VI

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9. XXXIX + II

XXXIX = 39, II = 2 → 39 + 2 = 41 → XLI

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10. VII + XXIV – VII

VII = 7, XXIV = 24 → 7 + 24 = 31; 31 - 7 = 24 → XXIV

Or notice: +VII and -VII cancel → left with XXIV

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11. XXI – XI + XXI

XXI = 21, XI = 11 → 21 - 11 = 10; 10 + 21 = 31 → XXXI

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12. XXIV – XV + XXIII

XXIV = 24, XV = 15, XXIII = 23
24 - 15 = 9; 9 + 23 = 32 → XXXII

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13. IX + XXX + V

IX = 9, XXX = 30, V = 5 → 9+30=39; 39+5=44 → XLIV

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14. XVI – XIV

XVI = 16, XIV = 14 → 16 - 14 = 2 → II

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15. XLVI – XLII

XLVI = 46, XLII = 42 → 46 - 42 = 4 → IV

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16. I + XXX – XVII

I = 1, XXX = 30, XVII = 17 → 1+30=31; 31-17=14 → XIV

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Now, compiling all 16 answers in order:

1. XV
2. XXVII
3. XXXVIII
4. XV
5. XXXIII
6. XXXIV
7. XXX
8. VI
9. XLI
10. XXIV
11. XXXI
12. XXXII
13. XLIV
14. II
15. IV
16. XIV

Double-checking a few tricky ones:

Problem 2: XXXIX – XII = 39 - 12 = 27 → XXVII ✔️
Problem 6: XLVIII – XIV = 48 - 14 = 34 → XXXIV ✔️
Problem 8: XXXII – XXVI = 32 - 26 = 6 → VI ✔️
Problem 16: I + XXX – XVII = 1 + 30 - 17 = 14 → XIV ✔️

All seem correct.

Final Answer:
1. XV
2. XXVII
3. XXXVIII
4. XV
5. XXXIII
6. XXXIV
7. XXX
8. VI
9. XLI
10. XXIV
11. XXXI
12. XXXII
13. XLIV
14. II
15. IV
16. XIV