Explanation:
We are rolling two 4-sided dice (tetrahedral dice), and we add their scores. Each die has faces numbered 1 through 4.
First, let’s list all possible outcomes. Since each die has 4 sides, there are:
4 × 4 = 16 total possible outcomes.
These are all the pairs (Die 1, Die 2):
(1,1), (1,2), (1,3), (1,4)
(2,1), (2,2), (2,3), (2,4)
(3,1), (3,2), (3,3), (3,4)
(4,1), (4,2), (4,3), (4,4)
Now compute the sum for each pair:
- Sum = 2: (1,1) → 1 outcome
- Sum = 3: (1,2), (2,1) → 2 outcomes
- Sum = 4: (1,3), (2,2), (3,1) → 3 outcomes
- Sum = 5: (1,4), (2,3), (3,2), (4,1) → 4 outcomes
- Sum = 6: (2,4), (3,3), (4,2) → 3 outcomes
- Sum = 7: (3,4), (4,3) → 2 outcomes
- Sum = 8: (4,4) → 1 outcome
Let’s double-check:
1 + 2 + 3 + 4 + 3 + 2 + 1 = 16
✔
Now, the question asks:
What is the probability of getting 6 or above?
That means sums of 6, 7, or 8.
From above:
- Sum = 6 → 3 outcomes
- Sum = 7 → 2 outcomes
- Sum = 8 → 1 outcome
Total favorable outcomes = 3 + 2 + 1 =
6
Total possible outcomes = 16
So probability = 6 / 16 = simplify by dividing numerator and denominator by 2 →
3 / 8
Let me verify using the table in the problem (even though I’m not describing the image):
The table shows the sums in a grid — rows are Die 2 (1–4), columns are Die 1 (1–4). The values circled in blue are the ones ≥6:
- (2,4) = 6
- (3,3) = 6
- (3,4) = 7
- (4,2) = 6
- (4,3) = 7
- (4,4) = 8
That’s 6 circled entries — matches our count.
So the probability is indeed 6/16 = 3/8.
Final Answer:
3/8
Parent Tip: Review the logic above to help your child master the concept of sample space probability worksheet.
