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Step-by-step solution for: Scale Drawing Worksheet With Answers Pdf - Fill Online, Printable ...
Here is the complete solution to the Scale Drawings of Geometric Figures – Independent Practice Worksheet.
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> Logan made a treasure hunt map. The treasure is 25 cm away from his location. If each 1 cm on the scale drawing equals 5 meters, how far is the treasure?
✔ Solution:
- Scale: 1 cm = 5 meters
- Distance on map: 25 cm
So actual distance = 25 cm × 5 m/cm = 125 meters
🔹 Answer: 125 meters
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> Jordan made a wooden square box. All sides of the wooden box are 6 cm. He wants to increase the length of all sides by 1.6 cm. What is the perimeter and area of the new box?
✔ Solution:
- Original side = 6 cm
- New side = 6 cm + 1.6 cm = 7.6 cm
→ Perimeter of square = 4 × side = 4 × 7.6 = 30.4 cm
→ Area of square = side² = (7.6)² = 57.76 cm²
🔹 Answer: Perimeter = 30.4 cm, Area = 57.76 cm²
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> Abigail redecorates her house. A scale drawing of her house can be seen below. If each 6 cm on the scale drawing equals 12 ft, what are the actual dimensions of Abigail’s house?
✔ Solution:
From the diagram:
- Length on drawing = 18 cm
- Width on drawing = 12 cm
Scale: 6 cm = 12 ft → So 1 cm = 2 ft
→ Actual length = 18 cm × 2 ft/cm = 36 ft
→ Actual width = 12 cm × 2 ft/cm = 24 ft
🔹 Answer: 36 ft by 24 ft
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> Olivia goes to Egypt and sees a model of a triangle shaped pyramid. She enlarged it using a scale factor of 1.2. What is the perimeter and area of the new triangle pyramid?
✔ Solution:
From the diagram:
- Base = 8 cm
- Height = 6 cm
- Two equal sides = 5 cm each (since it’s an isosceles triangle)
→ Original perimeter = 5 + 5 + 8 = 18 cm
→ Original area = (base × height) / 2 = (8 × 6) / 2 = 24 cm²
With scale factor = 1.2:
→ New perimeter = original perimeter × scale factor = 18 × 1.2 = 21.6 cm
→ New area = original area × (scale factor)² = 24 × (1.2)² = 24 × 1.44 = 34.56 cm²
🔹 Answer: Perimeter = 21.6 cm, Area = 34.56 cm²
*(Note: Even though it says “pyramid”, the diagram shows a triangle — so we treat it as a 2D triangle for perimeter and area calculations.)*
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> At Carter’s birthday party, his mom made a cake in a rectangular shape. The length of cake is 8 cm and width of cake is 6 cm. If she wants to add 1 cm of cream around the cake, what will be the perimeter and area of the rectangle?
✔ Solution:
Adding 1 cm of cream around the cake means adding 1 cm to each side → total addition of 2 cm to both length and width.
→ New length = 8 + 2 = 10 cm
→ New width = 6 + 2 = 8 cm
→ Perimeter = 2 × (length + width) = 2 × (10 + 8) = 36 cm
→ Area = length × width = 10 × 8 = 80 cm²
🔹 Answer: Perimeter = 36 cm, Area = 80 cm²
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> Max makes a scale drawing of distance between Salt Lake City and Arizona. The length between Salt Lake City and Arizona is 21 cm. If each 7 cm on the scale drawing equals 250 kilometers, how far apart are the Salt Lake City and Arizona?
✔ Solution:
- Scale: 7 cm = 250 km
→ So 1 cm = 250 ÷ 7 ≈ 35.714 km
→ Actual distance = 21 cm × (250 km / 7 cm) = (21 ÷ 7) × 250 = 3 × 250 = 750 km
🔹 Answer: 750 kilometers
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## ✔ Final Answers Summary:
1. 125 meters
2. Perimeter = 30.4 cm, Area = 57.76 cm²
3. 36 ft by 24 ft
4. Perimeter = 21.6 cm, Area = 34.56 cm²
5. Perimeter = 36 cm, Area = 80 cm²
6. 750 kilometers
Let me know if you’d like visual diagrams or step-by-step drawings for any problem!
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Problem 1: Logan’s Treasure Hunt
> Logan made a treasure hunt map. The treasure is 25 cm away from his location. If each 1 cm on the scale drawing equals 5 meters, how far is the treasure?
✔ Solution:
- Scale: 1 cm = 5 meters
- Distance on map: 25 cm
So actual distance = 25 cm × 5 m/cm = 125 meters
🔹 Answer: 125 meters
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Problem 2: Jordan’s Wooden Square Box
> Jordan made a wooden square box. All sides of the wooden box are 6 cm. He wants to increase the length of all sides by 1.6 cm. What is the perimeter and area of the new box?
✔ Solution:
- Original side = 6 cm
- New side = 6 cm + 1.6 cm = 7.6 cm
→ Perimeter of square = 4 × side = 4 × 7.6 = 30.4 cm
→ Area of square = side² = (7.6)² = 57.76 cm²
🔹 Answer: Perimeter = 30.4 cm, Area = 57.76 cm²
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Problem 3: Abigail’s House Redecoration
> Abigail redecorates her house. A scale drawing of her house can be seen below. If each 6 cm on the scale drawing equals 12 ft, what are the actual dimensions of Abigail’s house?
✔ Solution:
From the diagram:
- Length on drawing = 18 cm
- Width on drawing = 12 cm
Scale: 6 cm = 12 ft → So 1 cm = 2 ft
→ Actual length = 18 cm × 2 ft/cm = 36 ft
→ Actual width = 12 cm × 2 ft/cm = 24 ft
🔹 Answer: 36 ft by 24 ft
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Problem 4: Olivia’s Egyptian Pyramid
> Olivia goes to Egypt and sees a model of a triangle shaped pyramid. She enlarged it using a scale factor of 1.2. What is the perimeter and area of the new triangle pyramid?
✔ Solution:
From the diagram:
- Base = 8 cm
- Height = 6 cm
- Two equal sides = 5 cm each (since it’s an isosceles triangle)
→ Original perimeter = 5 + 5 + 8 = 18 cm
→ Original area = (base × height) / 2 = (8 × 6) / 2 = 24 cm²
With scale factor = 1.2:
→ New perimeter = original perimeter × scale factor = 18 × 1.2 = 21.6 cm
→ New area = original area × (scale factor)² = 24 × (1.2)² = 24 × 1.44 = 34.56 cm²
🔹 Answer: Perimeter = 21.6 cm, Area = 34.56 cm²
*(Note: Even though it says “pyramid”, the diagram shows a triangle — so we treat it as a 2D triangle for perimeter and area calculations.)*
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Problem 5: Carter’s Birthday Cake
> At Carter’s birthday party, his mom made a cake in a rectangular shape. The length of cake is 8 cm and width of cake is 6 cm. If she wants to add 1 cm of cream around the cake, what will be the perimeter and area of the rectangle?
✔ Solution:
Adding 1 cm of cream around the cake means adding 1 cm to each side → total addition of 2 cm to both length and width.
→ New length = 8 + 2 = 10 cm
→ New width = 6 + 2 = 8 cm
→ Perimeter = 2 × (length + width) = 2 × (10 + 8) = 36 cm
→ Area = length × width = 10 × 8 = 80 cm²
🔹 Answer: Perimeter = 36 cm, Area = 80 cm²
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Problem 6: Salt Lake City and Arizona Map
> Max makes a scale drawing of distance between Salt Lake City and Arizona. The length between Salt Lake City and Arizona is 21 cm. If each 7 cm on the scale drawing equals 250 kilometers, how far apart are the Salt Lake City and Arizona?
✔ Solution:
- Scale: 7 cm = 250 km
→ So 1 cm = 250 ÷ 7 ≈ 35.714 km
→ Actual distance = 21 cm × (250 km / 7 cm) = (21 ÷ 7) × 250 = 3 × 250 = 750 km
🔹 Answer: 750 kilometers
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## ✔ Final Answers Summary:
1. 125 meters
2. Perimeter = 30.4 cm, Area = 57.76 cm²
3. 36 ft by 24 ft
4. Perimeter = 21.6 cm, Area = 34.56 cm²
5. Perimeter = 36 cm, Area = 80 cm²
6. 750 kilometers
Let me know if you’d like visual diagrams or step-by-step drawings for any problem!
Parent Tip: Review the logic above to help your child master the concept of scale problems worksheet.