Density Worksheet - New York Science Teacher - Free Printable
Educational worksheet: Density Worksheet - New York Science Teacher. Download and print for classroom or home learning activities.
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Step-by-step solution for: Density Worksheet - New York Science Teacher
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Show Answer Key & Explanations
Step-by-step solution for: Density Worksheet - New York Science Teacher
Let’s solve this Density Worksheet step by step.
---
## ✔ STEP 1: Calculate Density for Samples 1–5
The formula for density is:
> Density (d) = Mass (m) / Volume (v)
> Units: g/cm³
We’ll calculate the density for each sample using the given mass and volume.
---
- Mass = 15 g
- Volume = 2 cm³
- Density = 15 / 2 = 7.5 g/cm³
- Mass = 60 g
- Volume = 8 cm³
- Density = 60 / 8 = 7.5 g/cm³
- Mass = 120 g
- Volume = 16 cm³
- Density = 120 / 16 = 7.5 g/cm³
- Mass = 480 g
- Volume = 64 cm³
- Density = 480 / 64 = 7.5 g/cm³
- Mass = 750 g
- Volume = 100 cm³
- Density = 750 / 100 = 7.5 g/cm³
✔ All samples have the same density: 7.5 g/cm³
This makes sense — they are all samples of the *same mineral*: galena. Density is an *intensive property* — it doesn’t change with sample size.
---
## ✔ STEP 2: Fill in the Data Table
| Sample | Size | Mass | Volume | Density (d=m/v) |
|--------|--------|-------|--------|------------------|
| 1 | small | 15 g | 2 cm³ | 7.5 g/cm³ |
| 2 | | 60 g | 8 cm³ | 7.5 g/cm³ |
| 3 | | 120 g | 16 cm³ | 7.5 g/cm³ |
| 4 | | 480 g | 64 cm³ | 7.5 g/cm³ |
| 5 | large | 750 g | 100 cm³| 7.5 g/cm³ |
---
## ✔ STEP 3: Answer the Questions
---
Since density is constant (7.5 g/cm³), we can use:
> Mass = Density × Volume
Mass = 7.5 g/cm³ × 75 cm³ = 562.5 g
*(Note: If you plotted the graph, you’d see a straight line through the origin — so at 75 cm³ on x-axis, y-axis (mass) would be 562.5 g)*
✔ Answer: 562.5 grams
---
Use:
> Volume = Mass / Density
Volume = 300 g / 7.5 g/cm³ = 40 cm³
✔ Answer: 40 cm³
---
The graph will show a straight line passing through the origin (0,0), meaning mass is directly proportional to volume.
This is because density is constant — as volume increases, mass increases at the same rate.
✔ Answer: Mass and volume are directly proportional — as volume increases, mass increases proportionally. The graph is a straight line through the origin.
---
Both have density = 7.5 g/cm³
✔ Answer: They are equal. Density does not depend on sample size.
---
Sample 5: 750 g / 100 cm³ = 7.5 g/cm³
Sample 1: 15 g / 2 cm³ = 7.5 g/cm³
✔ Answer: They are identical. Density is an intensive property and does not change with sample size.
---
None. Density is an intensive property — it depends only on the type of material, not on how much you have.
✔ Answer: Sample size has no effect on density. Density remains constant regardless of sample size for a pure substance.
---
This refers to rearranging the formula d = m/v using algebra or the “density triangle”.
#### 📐 Density Triangle Method:
Draw a triangle and divide it into 3 parts:
```
M
---
D | V
```
Cover the variable you want to solve for:
- Cover M → you get D × V
- Cover D → you get M ÷ V
- Cover V → you get M ÷ D
#### 🔁 Algebraic Rearrangement:
From d = m/v, multiply both sides by v → m = d × v
Divide both sides by d → v = m/d
✔ Answer: You can rearrange the formula d = m/v to solve for any variable:
- To find mass: m = d × v
- To find volume: v = m ÷ d
- You can also use the “density triangle” — cover the variable you want to find, and the remaining two show the operation.
---
## ✔ FINAL SUMMARY
- All samples of galena have density = 7.5 g/cm³
- Mass and volume are directly proportional
- Density is independent of sample size
- You can rearrange d = m/v to solve for mass or volume
---
📌 Bonus Tip: This worksheet teaches a key concept in science — density is a characteristic property of a substance. No matter how big or small the sample, if it’s pure galena, its density will always be ~7.5 g/cm³!
---
✔ All questions answered! Let me know if you’d like help plotting the graph too.
---
## ✔ STEP 1: Calculate Density for Samples 1–5
The formula for density is:
> Density (d) = Mass (m) / Volume (v)
> Units: g/cm³
We’ll calculate the density for each sample using the given mass and volume.
---
Sample 1:
- Mass = 15 g
- Volume = 2 cm³
- Density = 15 / 2 = 7.5 g/cm³
Sample 2:
- Mass = 60 g
- Volume = 8 cm³
- Density = 60 / 8 = 7.5 g/cm³
Sample 3:
- Mass = 120 g
- Volume = 16 cm³
- Density = 120 / 16 = 7.5 g/cm³
Sample 4:
- Mass = 480 g
- Volume = 64 cm³
- Density = 480 / 64 = 7.5 g/cm³
Sample 5:
- Mass = 750 g
- Volume = 100 cm³
- Density = 750 / 100 = 7.5 g/cm³
✔ All samples have the same density: 7.5 g/cm³
This makes sense — they are all samples of the *same mineral*: galena. Density is an *intensive property* — it doesn’t change with sample size.
---
## ✔ STEP 2: Fill in the Data Table
| Sample | Size | Mass | Volume | Density (d=m/v) |
|--------|--------|-------|--------|------------------|
| 1 | small | 15 g | 2 cm³ | 7.5 g/cm³ |
| 2 | | 60 g | 8 cm³ | 7.5 g/cm³ |
| 3 | | 120 g | 16 cm³ | 7.5 g/cm³ |
| 4 | | 480 g | 64 cm³ | 7.5 g/cm³ |
| 5 | large | 750 g | 100 cm³| 7.5 g/cm³ |
---
## ✔ STEP 3: Answer the Questions
---
1. Use the completed graph to determine how much mass a sample of galena would have if its volume was 75 cm³.
Since density is constant (7.5 g/cm³), we can use:
> Mass = Density × Volume
Mass = 7.5 g/cm³ × 75 cm³ = 562.5 g
*(Note: If you plotted the graph, you’d see a straight line through the origin — so at 75 cm³ on x-axis, y-axis (mass) would be 562.5 g)*
✔ Answer: 562.5 grams
---
2. Use the completed graph to determine how much volume a sample of galena would have if its mass was 300 g.
Use:
> Volume = Mass / Density
Volume = 300 g / 7.5 g/cm³ = 40 cm³
✔ Answer: 40 cm³
---
3. Describe the relationship between mass and volume shown by the graph.
The graph will show a straight line passing through the origin (0,0), meaning mass is directly proportional to volume.
This is because density is constant — as volume increases, mass increases at the same rate.
✔ Answer: Mass and volume are directly proportional — as volume increases, mass increases proportionally. The graph is a straight line through the origin.
---
4. How does the density of Sample 2 compare to that of Sample 4?
Both have density = 7.5 g/cm³
✔ Answer: They are equal. Density does not depend on sample size.
---
5. How did the density of the largest sample (5) compare to the smallest sample (1)?
Sample 5: 750 g / 100 cm³ = 7.5 g/cm³
Sample 1: 15 g / 2 cm³ = 7.5 g/cm³
✔ Answer: They are identical. Density is an intensive property and does not change with sample size.
---
6. What is the effect of sample size on the density of a material?
None. Density is an intensive property — it depends only on the type of material, not on how much you have.
✔ Answer: Sample size has no effect on density. Density remains constant regardless of sample size for a pure substance.
---
7. Describe the trick you were taught on how to change around the density formula to solve for different parts of it.
This refers to rearranging the formula d = m/v using algebra or the “density triangle”.
#### 📐 Density Triangle Method:
Draw a triangle and divide it into 3 parts:
```
M
---
D | V
```
Cover the variable you want to solve for:
- Cover M → you get D × V
- Cover D → you get M ÷ V
- Cover V → you get M ÷ D
#### 🔁 Algebraic Rearrangement:
From d = m/v, multiply both sides by v → m = d × v
Divide both sides by d → v = m/d
✔ Answer: You can rearrange the formula d = m/v to solve for any variable:
- To find mass: m = d × v
- To find volume: v = m ÷ d
- You can also use the “density triangle” — cover the variable you want to find, and the remaining two show the operation.
---
## ✔ FINAL SUMMARY
- All samples of galena have density = 7.5 g/cm³
- Mass and volume are directly proportional
- Density is independent of sample size
- You can rearrange d = m/v to solve for mass or volume
---
📌 Bonus Tip: This worksheet teaches a key concept in science — density is a characteristic property of a substance. No matter how big or small the sample, if it’s pure galena, its density will always be ~7.5 g/cm³!
---
✔ All questions answered! Let me know if you’d like help plotting the graph too.
Parent Tip: Review the logic above to help your child master the concept of science teacher worksheet.