Segment and Angle Addition Postulate Notes and Worksheets ... - Free Printable
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Step-by-step solution for: Segment and Angle Addition Postulate Notes and Worksheets ...
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Step-by-step solution for: Segment and Angle Addition Postulate Notes and Worksheets ...
Let's solve each part of this Segment Addition Postulate worksheet step by step.
---
> If 3 points are ________, (on the same line segment), and B is between A and C, then ________.
✔ Answer:
- If 3 points are collinear, and B is between A and C, then
→ AB + BC = AC
This is the Segment Addition Postulate: When point B lies between points A and C on a line segment, the sum of the lengths of AB and BC equals the length of AC.
---
## ✔ Examples:
---
We are given:
- DF = 10
- DE = 7
- Points D, E, F are collinear with E between D and F.
Using the Segment Addition Postulate:
$$
DE + EF = DF
$$
$$
7 + EF = 10
$$
$$
EF = 10 - 7 = 3
$$
✔ Answer: EF = 3
---
Given:
- MN = 2x
- NO = 3x + 7
- MO = MN + NO = 32
So:
$$
MN + NO = MO
$$
$$
2x + (3x + 7) = 32
$$
$$
5x + 7 = 32
$$
$$
5x = 25
$$
$$
x = 5
$$
✔ Answer: x = 5
---
Given:
- RS = 7
- ST = 3x - 4
- TU = 4x
- RU = RS + ST + TU = 59
So:
$$
RS + ST + TU = RU
$$
$$
7 + (3x - 4) + 4x = 59
$$
$$
7 + 3x - 4 + 4x = 59
$$
$$
(3x + 4x) + (7 - 4) = 59
$$
$$
7x + 3 = 59
$$
$$
7x = 56
$$
$$
x = 8
$$
Now find TR. Note that TR = TS + SR?
Wait — look at the diagram:
Points are R–S–T–U. So:
- TR means from T to R, which is TS + SR?
But actually, TR is the distance from T to R. Since R–S–T, we go backwards:
- TR = TS + SR = (3x - 4) + 7
Plug in x = 8:
- 3(8) - 4 = 24 - 4 = 20
- Add 7 → 20 + 7 = 27
So TR = 27
✔ Answer: TR = 27
---
Given:
- The whole segment = 10x + 5
- It's divided into three parts: x, x + 15, and 3x
So:
$$
x + (x + 15) + 3x = 10x + 5
$$
$$
x + x + 15 + 3x = 10x + 5
$$
$$
5x + 15 = 10x + 5
$$
Subtract 5x from both sides:
$$
15 = 5x + 5
$$
Subtract 5:
$$
10 = 5x
\Rightarrow x = 2
$$
Now find each segment:
- First: x = 2
- Second: x + 15 = 2 + 15 = 17
- Third: 3x = 3(2) = 6
Check total: 2 + 17 + 6 = 25
Total should be: 10x + 5 = 10(2) + 5 = 25 ✔
✔ Answer:
- x = 2
- Segments: 2, 17, 6
---
Given: JK = MN
Prove: MN + KL = JL
Diagram shows:
- J — K — L (so K is between J and L)
- M — N (a separate segment)
But since JK = MN, and we want to prove MN + KL = JL, we’re using substitution.
| Statements | Reasons |
|-----------|--------|
| 1. JK = MN | 1. Given |
| 2. JK + KL = JL | 2. Segment Addition Postulate (K is between J and L) |
| 3. MN + KL = JL | 3. Substitution Property of Equality (Replace JK with MN) |
✔ Completed Proof Table:
| Statements | Reasons |
|-----------|--------|
| 1. JK = MN | 1. Given |
| 2. JK + KL = JL | 2. Segment Addition Postulate |
| 3. MN + KL = JL | 3. Substitution (from statement 1) |
---
## ✔ Final Answers Summary:
1. EF = 3
2. x = 5
3. TR = 27
4. x = 2; segments: 2, 17, 6
5. Proof completed as above
Let me know if you'd like this printed or formatted differently!
---
🔹 Segment Addition Postulate (Fill in the blank):
> If 3 points are ________, (on the same line segment), and B is between A and C, then ________.
✔ Answer:
- If 3 points are collinear, and B is between A and C, then
→ AB + BC = AC
This is the Segment Addition Postulate: When point B lies between points A and C on a line segment, the sum of the lengths of AB and BC equals the length of AC.
---
## ✔ Examples:
---
1. If DF = 10 and DE = 7, what is the length of EF?
We are given:
- DF = 10
- DE = 7
- Points D, E, F are collinear with E between D and F.
Using the Segment Addition Postulate:
$$
DE + EF = DF
$$
$$
7 + EF = 10
$$
$$
EF = 10 - 7 = 3
$$
✔ Answer: EF = 3
---
2. If MO = 32, find the value of x.
Given:
- MN = 2x
- NO = 3x + 7
- MO = MN + NO = 32
So:
$$
MN + NO = MO
$$
$$
2x + (3x + 7) = 32
$$
$$
5x + 7 = 32
$$
$$
5x = 25
$$
$$
x = 5
$$
✔ Answer: x = 5
---
3. If RU = 59, find TR.
Given:
- RS = 7
- ST = 3x - 4
- TU = 4x
- RU = RS + ST + TU = 59
So:
$$
RS + ST + TU = RU
$$
$$
7 + (3x - 4) + 4x = 59
$$
$$
7 + 3x - 4 + 4x = 59
$$
$$
(3x + 4x) + (7 - 4) = 59
$$
$$
7x + 3 = 59
$$
$$
7x = 56
$$
$$
x = 8
$$
Now find TR. Note that TR = TS + SR?
Wait — look at the diagram:
Points are R–S–T–U. So:
- TR means from T to R, which is TS + SR?
But actually, TR is the distance from T to R. Since R–S–T, we go backwards:
- TR = TS + SR = (3x - 4) + 7
Plug in x = 8:
- 3(8) - 4 = 24 - 4 = 20
- Add 7 → 20 + 7 = 27
So TR = 27
✔ Answer: TR = 27
---
4. Solve for x. Then find the length of each segment.
Given:
- The whole segment = 10x + 5
- It's divided into three parts: x, x + 15, and 3x
So:
$$
x + (x + 15) + 3x = 10x + 5
$$
$$
x + x + 15 + 3x = 10x + 5
$$
$$
5x + 15 = 10x + 5
$$
Subtract 5x from both sides:
$$
15 = 5x + 5
$$
Subtract 5:
$$
10 = 5x
\Rightarrow x = 2
$$
Now find each segment:
- First: x = 2
- Second: x + 15 = 2 + 15 = 17
- Third: 3x = 3(2) = 6
Check total: 2 + 17 + 6 = 25
Total should be: 10x + 5 = 10(2) + 5 = 25 ✔
✔ Answer:
- x = 2
- Segments: 2, 17, 6
---
5. Complete the proof
Given: JK = MN
Prove: MN + KL = JL
Diagram shows:
- J — K — L (so K is between J and L)
- M — N (a separate segment)
But since JK = MN, and we want to prove MN + KL = JL, we’re using substitution.
| Statements | Reasons |
|-----------|--------|
| 1. JK = MN | 1. Given |
| 2. JK + KL = JL | 2. Segment Addition Postulate (K is between J and L) |
| 3. MN + KL = JL | 3. Substitution Property of Equality (Replace JK with MN) |
✔ Completed Proof Table:
| Statements | Reasons |
|-----------|--------|
| 1. JK = MN | 1. Given |
| 2. JK + KL = JL | 2. Segment Addition Postulate |
| 3. MN + KL = JL | 3. Substitution (from statement 1) |
---
## ✔ Final Answers Summary:
1. EF = 3
2. x = 5
3. TR = 27
4. x = 2; segments: 2, 17, 6
5. Proof completed as above
Let me know if you'd like this printed or formatted differently!
Parent Tip: Review the logic above to help your child master the concept of segment addition postulate worksheet.