Number in sequence 1 to 10 worksheet from Vikram Learning.

It looks like the task is to fill in the missing numbers in a 5×4 grid so that the numbers follow a logical sequence from 1 to 20, with each number appearing once. The title says "Number in sequence 1 to 10," but the numbers go up to 20, so we’ll assume it's a typo and the goal is to fill in the numbers from 1 to 20.

Let’s analyze the given numbers:

```
Row 1: 1 _ _ _
Row 2: _ 7 _ 17
Row 3: 3 _ _ _
Row 4: _ _ 14 _
Row 5: 5 10 _ 20
```

We need to fill in the blanks such that all numbers from 1 to 20 appear exactly once, and likely in a sequential pattern (like counting up). Let’s look for patterns.

---

Step 1: Identify known values

Given numbers:
- 1, 3, 5, 7, 10, 14, 17, 20

So missing numbers are:
2, 4, 6, 8, 9, 11, 12, 13, 15, 16, 18, 19

Now let’s try to deduce the pattern.

---

Step 2: Look at positions

Let’s label rows and columns:

| | Col 1 | Col 2 | Col 3 | Col 4 |
|-------|-------|-------|-------|-------|
| Row 1 | 1 | ? | ? | ? |
| Row 2 | ? | 7 | ? | 17 |
| Row 3 | 3 | ? | ? | ? |
| Row 4 | ? | ? | 14 | ? |
| Row 5 | 5 | 10 | ? | 20 |

Now, observe that:

- Row 1, Col 1 = 1
- Row 2, Col 2 = 7
- Row 3, Col 1 = 3
- Row 4, Col 3 = 14
- Row 5, Col 1 = 5, Col 2 = 10, Col 4 = 20

Let’s check if there's a pattern by column or row.

---

Step 3: Check column patterns

#### Column 1:
- Row 1: 1
- Row 2: ?
- Row 3: 3
- Row 4: ?
- Row 5: 5

So far: 1, ?, 3, ?, 5 → This seems increasing by 2s? But not yet clear.

But 1, 3, 5 — odd numbers! So maybe this column has odd numbers?

If so, then missing numbers in Col 1 could be 7 and 9?

But 7 is already in Col 2, Row 2.

Wait — 7 is used, so can't repeat.

So Col 1: 1, ?, 3, ?, 5

If increasing: 1 → 3 → 5, so maybe 2 and 4 in between? But those are even.

Wait — perhaps not sorted.

Alternatively, think of the entire grid as a number grid from 1 to 20, possibly in row-major order (left to right, top to bottom).

Let’s suppose the grid is filled in order: 1, 2, 3, ..., 20.

Then position (Row, Col) corresponds to:

- (1,1): 1
- (1,2): 2
- (1,3): 3
- (1,4): 4
- (2,1): 5
- (2,2): 6
- (2,3): 7
- (2,4): 8
- (3,1): 9
- (3,2): 10
- (3,3): 11
- (3,4): 12
- (4,1): 13
- (4,2): 14
- (4,3): 15
- (4,4): 16
- (5,1): 17
- (5,2): 18
- (5,3): 19
- (5,4): 20

But wait — our given values don’t match this.

Let’s compare:

From above (if sequential):

- (1,1): 1 ✔
- (2,2): 6 ✘ but given as 7
- (2,4): 8 ✘ but given as 17
- (3,1): 9 ✘ but given as 3
- (4,3): 15 ✘ but given as 14
- (5,1): 17 ✘ but given as 5
- (5,2): 18 ✘ but given as 10
- (5,4): 20 ✔

So not sequential left-to-right.

But maybe it's increasing in some pattern.

Let’s try to see if numbers are placed based on value.

List all positions:

We know:

- 1 → (1,1)
- 3 → (3,1)
- 5 → (5,1)
- 7 → (2,2)
- 10 → (5,2)
- 14 → (4,3)
- 17 → (2,4)
- 20 → (5,4)

So:

- Col 1: 1 (R1), 3 (R3), 5 (R5)
- Col 2: 7 (R2), 10 (R5)
- Col 3: 14 (R4)
- Col 4: 17 (R2), 20 (R5)

Now, notice:

- Col 1: R1=1, R3=3, R5=5 → all odd numbers increasing: 1, 3, 5
- So maybe Col 1 has odd numbers? Then R2 and R4 are missing: 7 and 9?
- But 7 is already in (2,2), so cannot use again.
- So 7 is used in Col 2, so Col 1 cannot have 7.

So Col 1: 1, ?, 3, ?, 5

Maybe not increasing.

Wait — what if the rows are sequences?

Try Row 5: 5, 10, ?, 20 → 5, 10, ?, 20 → maybe doubling? 5 → 10 → 20 → so missing 15?

But 15 would be in (5,3)

So (5,3) = 15?

That makes sense.

Similarly, Row 2: ?, 7, ?, 17 → 7 to 17 is +10 → maybe arithmetic?

Row 4: ?, ?, 14, ? → 14 is in (4,3)

Row 3: 3, ?, ?, ?

Row 1: 1, ?, ?, ?

Let’s suppose the numbers increase by 1 across the grid, but not necessarily row-wise.

Wait — another idea: maybe the grid is arranged so that each column increases by a certain amount.

Let’s look at the diagonals or patterns.

Wait — let’s try to reconstruct using logic.

We know:

- 1 is at (1,1)
- 3 is at (3,1)
- 5 is at (5,1)

So column 1 has: R1=1, R2=?, R3=3, R4=?, R5=5

So R1=1, R3=3, R5=5 → maybe odd numbers in odd rows?

Then R2 and R4 should be 2 and 4?

But 2 and 4 are even.

But let’s suppose:

Col 1: 1, 2, 3, 4, 5 → then R2=2, R4=4

Is that possible?

But then R2=2, but R2,C2=7 → okay.

R4=4, R4,C3=14 → okay.

But then we’d have:

- (1,1): 1
- (2,1): 2
- (3,1): 3
- (4,1): 4
- (5,1): 5

So Col 1 is 1 to 5.

Now Col 2:

- (1,2): ?
- (2,2): 7
- (3,2): ?
- (4,2): ?
- (5,2): 10

So if Col 1 is 1–5, maybe Col 2 is 6–10?

Then:

- (1,2): 6
- (2,2): 7 ✔
- (3,2): 8
- (4,2): 9
- (5,2): 10 ✔

Perfect!

So Col 2: 6, 7, 8, 9, 10

Now Col 3:

- (1,3): ?
- (2,3): ?
- (3,3): ?
- (4,3): 14
- (5,3): ?

If pattern continues, Col 3 might be 11–15?

So:

- (1,3): 11
- (2,3): 12
- (3,3): 13
- (4,3): 14 ✔
- (5,3): 15

Yes!

Now Col 4:

- (1,4): ?
- (2,4): 17
- (3,4): ?
- (4,4): ?
- (5,4): 20

If pattern continues, Col 4 should be 16–20?

So:

- (1,4): 16
- (2,4): 17 ✔
- (3,4): 18
- (4,4): 19
- (5,4): 20 ✔

Perfect!

Now let’s verify all:

Final Grid:

| | Col 1 | Col 2 | Col 3 | Col 4 |
|-------|-------|-------|-------|-------|
| Row 1 | 1 | 6 | 11 | 16 |
| Row 2 | 2 | 7 | 12 | 17 |
| Row 3 | 3 | 8 | 13 | 18 |
| Row 4 | 4 | 9 | 14 | 19 |
| Row 5 | 5 | 10 | 15 | 20 |

Now check if all numbers 1–20 are present:

- 1–5: yes (Col 1)
- 6–10: yes (Col 2)
- 11–15: yes (Col 3)
- 16–20: yes (Col 4)

All unique, no duplicates.

Check given values:

- (1,1): 1 ✔
- (2,2): 7 ✔
- (3,1): 3 ✔
- (4,3): 14 ✔
- (5,1): 5 ✔
- (5,2): 10 ✔
- (2,4): 17 ✔
- (5,4): 20 ✔

All match!

---

✔ Solution:

Fill the grid as follows:

```
Row 1: 1 6 11 16
Row 2: 2 7 12 17
Row 3: 3 8 13 18
Row 4: 4 9 14 19
Row 5: 5 10 15 20
```

Each column increases by 1 from top to bottom, and each column represents a block of 5 consecutive numbers:

- Col 1: 1–5
- Col 2: 6–10
- Col 3: 11–15
- Col 4: 16–20

This is a column-wise sequential arrangement.

---

Final Answer:

The missing numbers are:

- (1,2): 6
- (1,3): 11
- (1,4): 16
- (2,1): 2
- (2,3): 12
- (3,2): 8
- (3,3): 13
- (3,4): 18
- (4,1): 4
- (4,2): 9
- (4,4): 19
- (5,3): 15

✔ All filled correctly!