Math worksheet problem testing understanding of set membership notation.

It looks like you've uploaded a problem involving set membership, but there's some missing information in the image or text. Let's go through what we have and clarify.

We are given:

- $ B = \{b, l, u, e\} $
- $ G = \{g, r, e, n\} $

Then we are asked to fill in one of the symbols $ \in $ (is an element of) or $ \notin $ (is not an element of) for the following:

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a) $ u \ldots B $

We check whether $ u $ is in set $ B $.
Since $ B = \{b, l, u, e\} $, and $ u $ is one of the elements listed, we conclude:

✔ $ u \in B $

So: a) $ u \in B $

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c) $ n \ldots P $

Wait — here’s a problem: The set $ P $ has not been defined anywhere in the question.

We only have sets $ B $ and $ G $ defined.

But $ n $ is an element of $ G $, since $ G = \{g, r, e, n\} $, so $ n \in G $.

But for part c), it says $ n \ldots P $. But P is not defined.

Possibility 1: This might be a typo, and it should be $ n \ldots G $?
Possibility 2: Maybe $ P $ was meant to be $ G $? Or perhaps $ B $?
Possibility 3: There may be a missing definition of $ P $ in the original image.

But based on what's given, we cannot determine $ n \in P $ or $ n \notin P $ unless we know what $ P $ is.

However, looking at the formatting:

> c) n … P
> d)

There’s also a "d)" but no content — likely incomplete.

Let’s assume that "P" is a typo and it was meant to be G, because:
- $ n \in G $, as $ G = \{g, r, e, n\} $
- That would make sense with the pattern

Alternatively, if it's really $ P $, then we cannot solve this without knowing $ P $.

But let's suppose the intended question was:

c) $ n \ldots G $

Then since $ n \in G $, we write:

✔ $ n \in G $

Alternatively, if it was supposed to be $ n \ldots B $, then $ n \notin B $, because $ B = \{b, l, u, e\} $, and $ n $ is not in that set.

But again, the symbol used is P, which is undefined.

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Conclusion:

Given the available information:

- a) $ u \in B $ → ✔
- c) $ n \ldots P $ → ✘ Cannot determine, because $ P $ is not defined.

But if P was a typo and meant to be G, then:

→ $ n \in G $

If P was meant to be B, then:

→ $ n \notin B $

But without clarification, we must point out the ambiguity.

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Final Answer (assuming typo and P = G):

a) $ u \in B $
c) $ n \in G $

But if P is truly a different set not defined, then c) cannot be answered.

Please double-check the original image for any missing definitions (e.g., is $ P $ defined elsewhere?).

Let me know if you can provide more context or clarify what $ P $ is.