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Class VII Set Theory Practice Worksheet with questions on identifying sets and set notation.

Practice worksheet on set theory for Class VII, featuring questions on identifying sets, set notation, and set operations.

Practice worksheet on set theory for Class VII, featuring questions on identifying sets, set notation, and set operations.

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Let's solve the Practice Worksheet on Set Theory step by step, with explanations.

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Question 1: Which of the following are sets? Justify your answer.



A set is a well-defined collection of distinct objects. For something to be a set, its elements must be clearly defined and identifiable (i.e., we should be able to determine whether an object belongs to the collection or not).

Let’s analyze each:

(a) The collection of all the days in a week beginning with the letter 'T'.

- Days starting with 'T': Tuesday, Thursday.
- This is a well-defined collection.
Yes, it is a set.

(b) The collection of all difficult questions in the chapter on sets.

- "Difficult" is subjective — what one person finds difficult, another might not.
- Not well-defined.
Not a set.

(c) The collection of girls in your class.

- Assuming we know who is in the class, this collection is clear and definite.
Yes, it is a set.

(d) The collection of all rivers in India.

- Although large, the rivers in India can be identified and listed.
- Well-defined.
Yes, it is a set.

(e) The collection of all active teachers in the school.

- "Active" may be ambiguous — does it mean currently teaching, employed, or working full-time?
- Could be interpreted differently.
- However, if we assume "active" means currently employed teachers, then it's well-defined.
Yes, it is a set, assuming a clear definition of "active".

(f) The collection of all integers more than -3.

- Integers greater than -3: -2, -1, 0, 1, 2, ...
- This is clearly defined.
Yes, it is a set.

(g) The collection of all beautiful flowers in the park.

- "Beautiful" is subjective.
- Not well-defined.
Not a set.

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Answers for Question 1:


| Item | Is it a set? | Justification |
|------|--------------|-------------|
| (a) | Yes | Clearly defined: Tuesday, Thursday |
| (b) | No | "Difficult" is subjective |
| (c) | Yes | Specific group: girls in class |
| (d) | Yes | Rivers in India are identifiable |
| (e) | Yes | If "active" is clearly defined |
| (f) | Yes | All integers > -3 are well-defined |
| (g) | No | "Beautiful" is subjective |

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Question 2:



Given sets:

- A = {3, 5, 7, 9}
- B = {2, 4, 6, 8, 10}
- C = {12, 14, 18, 20, 24}
- D = {21, 26, 31, 36}

#### (a) State whether true or false:

We check membership (element ∈ or ∉):

(i) 13 ∈ C
C = {12, 14, 18, 20, 24} → 13 is not in C
False

(ii) 4 ∈ A
A = {3, 5, 7, 9} → 4 is not in A
False

(iii) 9 ∈ A
A contains 9 → yes
True

(iv) 24 ∈ C
C contains 24 → yes
True

(v) 5 ∈ D
D = {21, 26, 31, 36} → 5 not in D
False

(vi) 36 ∈ D
D contains 36 → yes
True

(vii) 20 ∈ C
C contains 20 → yes
True

(viii) 9 ∈ A
Already checked → yes
True

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#### (b) Fill in the blanks:

We need to use ∈ (belongs to), ∉ (does not belong to), ⊆ (subset), ⊈ (not subset), etc.

(i) 3 ∈ ___
3 is in A → so: 3 ∈ A

(ii) 4 ___ B
4 is in B → so: 4 ∈ B

(iii) 26 ___ C
26 is not in C → so: 26 ∉ C

(iv) B ___ ___
We need to find which set B is a subset of, or relationship.

But let's look at the options:
B = {2, 4, 6, 8, 10}
C = {12, 14, 18, 20, 24} → no overlap
D = {21, 26, 31, 36} → no overlap
A = {3,5,7,9} → no overlap

So B is not a subset of any of the others.

But perhaps the question is asking: Is B a subset of any other set?

No. But maybe it's asking about element?

Wait — likely typo or formatting issue.

Looking again: (iv) B ___ ___

Possibility: It might be asking for B ⊆ ? or B ∈ ?

But B is a set, not an element.

None of the given sets contain B as an element.

So B is not a subset of any of the others, nor is it an element.

But perhaps it's a typo — maybe it's asking B ⊆ ? — but none of the sets contain elements from B.

Alternatively, perhaps it's asking B ⊈ C, or B ⊈ D, etc.

But let's see pattern.

Wait — maybe it's asking for B ⊆ ? — but no such relation holds.

Alternatively, could it be that B ⊆ C? No — 2 ∉ C.

So likely, B is not a subset of any of the others.

But the blank is two underscores — probably expects a symbol and a set.

Let’s re-express:

(iv) B ___ ___

Most likely: B ⊈ C or B ⊈ D — but we don’t know which.

Wait — perhaps it's asking: B ⊆ ? — but none.

Alternatively, maybe it's B ⊂ ? — still no.

But let's think: Maybe it's asking for B ⊆ A? No.

Perhaps there's a mistake.

Wait — perhaps the intended question is: B ⊆ ? — but none of the sets include elements of B.

So perhaps the correct answer is B ⊈ C, B ⊈ D, etc.

But since only one blank, maybe it's B ⊈ C?

But let's go back.

Wait — looking at the format:

(b) Fill in the blanks:

(i) 3 ∈ ___
(ii) 4 ___ B
(iii) 26 ___ C
(iv) B ___ ___
(v) 5 ___ A
(vi) 6 ___ C
(vii) 21 ___ D
(viii) 16 ___ B

Now, (iv) has two blanks, others have one.

So likely: B ⊈ C or B ⊈ D — but which?

But B and C have no common elements.

So B ∩ C = ∅, so B is not a subset of C.

Similarly, B is not a subset of D.

But maybe it's asking: B ⊆ ? — no.

Alternatively, could it be B ⊆ {even numbers}? But not among the options.

Wait — perhaps the intended answer is: B ⊈ C — because B and C are disjoint.

But let's check if B ⊆ C? No.

So B ⊈ C — this is true.

But why C? Why not D?

Maybe the question is: B ⊈ C — so fill in: B ⊈ C

But the blank is two spaces: B ___ ___

So likely: B ⊈ C

Similarly, others:

(v) 5 ___ A
5 is in A → 5 ∈ A

(vi) 6 ___ C
6 is not in C → 6 ∉ C

(vii) 21 ___ D
21 is in D → 21 ∈ D

(viii) 16 ___ B
16 is not in B → 16 ∉ B

Now back to (iv): B ___ ___

Since B is not a subset of C, and C is a set here, and B is not contained in C, we write:

B ⊈ C

So the blank is: B ⊈ C

But is that the only possibility? Let's see if B is a subset of any other?

B = {2,4,6,8,10}
A = {3,5,7,9} → no
C = {12,14,18,20,24} → no
D = {21,26,31,36} → no

So B is not a subset of any of the given sets.

But perhaps the question is asking: B ⊆ ? — but no.

Alternatively, maybe it's asking: B ⊆ B — but that would be trivial.

But since B is not listed as a member of any set, we can't say B ∈ anything.

So likely, (iv) B ⊈ C — meaning B is not a subset of C.

Alternatively, maybe it's a typo and should be B ⊆ ?, but without options, we assume B ⊈ C is intended.

But let's consider: Is there any chance B is a subset of C? No.

So B ⊈ C is true.

Hence:

(iv) B ⊈ C

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Final Answers for Question 2:



#### (a) True or False:

| Statement | Answer |
|---------|--------|
| (i) 13 ∈ C | False |
| (ii) 4 ∈ A | False |
| (iii) 9 ∈ A | True |
| (iv) 24 ∈ C | True |
| (v) 5 ∈ D | False |
| (vi) 36 ∈ D | True |
| (vii) 20 ∈ C | True |
| (viii) 9 ∈ A | True |

#### (b) Fill in the blanks:

| Statement | Answer |
|---------|--------|
| (i) 3 ∈ ___ | A |
| (ii) 4 ___ B | ∈ |
| (iii) 26 ___ C | ∉ |
| (iv) B ___ ___ | ⊈ C |
| (v) 5 ___ A | ∈ |
| (vi) 6 ___ C | ∉ |
| (vii) 21 ___ D | ∈ |
| (viii) 16 ___ B | ∉ |

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Summary:



Q1: Only (b) and (g) are not sets due to subjectivity.

Q2(a): As above.

Q2(b): As filled.

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