1. Given: AD = 3, DC = 6, CE = 2, EB = 4
Prove: ΔABC ~ ΔDEC
Statement | Reason
---|---
1) AD = 3, DC = 6, CE = 2, EB = 4 | Given
2) AD + DC = AC | Segment Addition Postulate
3) AC = 9 | Substitution (3 + 6 = 9)
4) CE + EB = CB | Segment Addition Postulate
5) CB = 6 | Substitution (2 + 4 = 6)
6) AC / DC = 9 / 6 = 3 / 2 | Division
7) BC / EC = 6 / 2 = 3 / 2 | Division
8) AC / DC = BC / EC | Transitive Property (both equal 3/2)
9) ∠C ≅ ∠C | Reflexive Property of Congruence
10) ΔABC ~ ΔDEC | SAS Similarity Postulate (two sides proportional and included angle congruent)
2. Given: ΔABC ~ ΔDEC
Prove: ∠ABC ≅ ∠DEC
Statement | Reason
1) ΔABC ~ ΔDEC | Given
2) ∠ABC ≅ ∠DEC | Corresponding Angles of Similar Triangles are Congruent
Parent Tip: Review the logic above to help your child master the concept of similar triangles proofs worksheet.