Simple Interest worksheet with 30 math problems to calculate ending balance using the simple interest formula.
Worksheet titled "Simple Interest" with 30 problems asking to calculate ending balance using simple interest formula, featuring a blue header, pencil icon, and QR code.
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Show Answer Key & Explanations
Step-by-step solution for: Simple Interest worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Simple Interest worksheets
Explanation:
We are asked to find the ending balance using simple interest for each of the 30 problems.
The formula for simple interest is:
$$
\text{Interest} = P \times r \times t
$$
Where:
- $P$ = principal (starting amount)
- $r$ = annual interest rate (as a decimal, e.g., 12% → 0.12)
- $t$ = time in years
Then, the ending balance is:
$$
\text{Ending Balance} = P + \text{Interest} = P(1 + rt)
$$
Let’s verify with problem #1 as an example:
- $P = \$1,900.00$
- $r = 12\% = 0.12$
- $t = 14$ years
Interest = $1900 \times 0.12 \times 14 = 1900 \times 1.68 = \$3,192.00$
Ending balance = $1900 + 3192 = \$5,092.00$
But wait — the instruction says “Use simple interest to find the ending balance.” Since there are 30 problems, and the user did not ask to solve all 30, but only said “Solve the problem accurately”, and the image contains a list of 30 items — we need to clarify: Is the user asking for *all* answers? Or just one?
However, looking at the prompt:
> The user uploaded an image containing a task. Solve the problem accurately.
And the image shows a worksheet titled “Simple Interest” with 30 numbered problems — this is a standard homework sheet where students compute ending balances.
Since no specific item was selected, and the instruction says “Solve the problem”, but there are 30 problems — the most reasonable interpretation is that the user expects all 30 answers, because it's a single worksheet task.
So we will compute all 30 ending balances using the formula:
$$
\text{Ending Balance} = P \times (1 + r \times t)
$$
Let’s compute each carefully. I’ll do them in order, double-checking decimals and multiplication.
---
1) $P = 1900$, $r = 0.12$, $t = 14$
$rt = 0.12 \times 14 = 1.68$
$1 + rt = 2.68$
$1900 \times 2.68 = 1900 \times 2 + 1900 \times 0.68 = 3800 + 1292 = \$5,092.00$
2) $P = 3300$, $r = 0.12$, $t = 5$
$rt = 0.6$
$1 + rt = 1.6$
$3300 \times 1.6 = 5,280.00$
3) $P = 1950$, $r = 0.11$, $t = 12$
$rt = 1.32$
$1 + rt = 2.32$
$1950 \times 2.32$:
$1950 \times 2 = 3900$
$1950 \times 0.32 = 624$
Total = $4,524.00$
4) $P = 1200$, $r = 0.03$, $t = 9$
$rt = 0.27$
$1.27 \times 1200 = 1200 + 0.27×1200 = 1200 + 324 = \$1,524.00$
5) $P = 5500$, $r = 0.08$, $t = 14$
$rt = 1.12$
$1 + rt = 2.12$
$5500 × 2.12 = 5500×2 + 5500×0.12 = 11,000 + 660 = \$11,660.00$
6) $P = 2700$, $r = 0.03$, $t = 14$
$rt = 0.42$
$1.42 × 2700 = 2700 + 0.42×2700 = 2700 + 1134 = \$3,834.00$
7) $P = 5100$, $r = 0.05$, $t = 10$
$rt = 0.5$
$1.5 × 5100 = \$7,650.00$
8) $P = 2100$, $r = 0.12$, $t = 9$
$rt = 1.08$
$2.08 × 2100 = 2100×2 + 2100×0.08 = 4200 + 168 = \$4,368.00$
9) $P = 4500$, $r = 0.12$, $t = 9$
$rt = 1.08$
$2.08 × 4500 = 4500×2 + 4500×0.08 = 9000 + 360 = \$9,360.00$
10) $P = 2250$, $r = 0.02$, $t = 5$
$rt = 0.10$
$1.10 × 2250 = \$2,475.00$
11) $P = 3700$, $r = 0.18$, $t = 7$
$rt = 1.26$
$2.26 × 3700 = 3700×2 + 3700×0.26 = 7400 + 962 = \$8,362.00$
12) $P = 1500$, $r = 0.14$, $t = 9$
$rt = 1.26$
$2.26 × 1500 = 3390.00$
13) $P = 4100$, $r = 0.10$, $t = 10$
$rt = 1.0$
$2.0 × 4100 = \$8,200.00$
14) $P = 3450$, $r = 0.10$, $t = 5$
$rt = 0.5$
$1.5 × 3450 = 5,175.00$
15) $P = 5600$, $r = 0.10$, $t = 10$
$rt = 1.0$
$2.0 × 5600 = \$11,200.00$
16) $P = 3050$, $r = 0.12$, $t = 14$
$rt = 1.68$
$2.68 × 3050$:
$3050 × 2 = 6100$
$3050 × 0.68 = 3050 × 0.6 + 3050 × 0.08 = 1830 + 244 = 2074$
Total = $6100 + 2074 = \$8,174.00$
17) $P = 2350$, $r = 0.13$, $t = 8$
$rt = 1.04$
$2.04 × 2350 = 2350×2 + 2350×0.04 = 4700 + 94 = \$4,794.00$
18) $P = 5250$, $r = 0.05$, $t = 5$
$rt = 0.25$
$1.25 × 5250 = 6,562.50$
19) $P = 5150$, $r = 0.19$, $t = 5$
$rt = 0.95$
$1.95 × 5150$:
$5150 × 2 = 10,300$
Minus $5150 × 0.05 = 257.50$
→ $10,300 - 257.50 = \$10,042.50$
Alternatively: $5150 × 1.95 = 5150 × (2 − 0.05) = 10,300 − 257.5 = 10,042.5$
20) $P = 2200$, $r = 0.05$, $t = 4$
$rt = 0.20$
$1.20 × 2200 = \$2,640.00$
21) $P = 1700$, $r = 0.05$, $t = 13$
$rt = 0.65$
$1.65 × 1700 = 1700 + 0.65×1700 = 1700 + 1105 = \$2,805.00$
22) $P = 1550$, $r = 0.08$, $t = 2$
$rt = 0.16$
$1.16 × 1550 = 1550 + 0.16×1550 = 1550 + 248 = \$1,798.00$
23) $P = 1300$, $r = 0.07$, $t = 3$
$rt = 0.21$
$1.21 × 1300 = 1300 + 273 = \$1,573.00$
24) $P = 3150$, $r = 0.16$, $t = 11$
$rt = 1.76$
$2.76 × 3150$:
$3150 × 2 = 6300$
$3150 × 0.76 = 3150 × 0.7 + 3150 × 0.06 = 2205 + 189 = 2394$
Total = $6300 + 2394 = \$8,694.00$
25) $P = 5700$, $r = 0.10$, $t = 10$
$rt = 1.0$
$2.0 × 5700 = \$11,400.00$
26) $P = 1400$, $r = 0.09$, $t = 2$
$rt = 0.18$
$1.18 × 1400 = 1400 + 252 = \$1,652.00$
27) $P = 3550$, $r = 0.12$, $t = 4$
$rt = 0.48$
$1.48 × 3550$:
$3550 × 1 = 3550$
$3550 × 0.48 = 3550 × 0.4 + 3550 × 0.08 = 1420 + 284 = 1704$
Total = $3550 + 1704 = \$5,254.00$
28) $P = 3650$, $r = 0.15$, $t = 4$
$rt = 0.60$
$1.60 × 3650 = 3650 + 0.6×3650 = 3650 + 2190 = \$5,840.00$
29) $P = 4750$, $r = 0.15$, $t = 8$
$rt = 1.20$
$2.20 × 4750 = 4750×2 + 4750×0.2 = 9500 + 950 = \$10,450.00$
30) $P = 4350$, $r = 0.03$, $t = 12$
$rt = 0.36$
$1.36 × 4350$:
$4350 × 1 = 4350$
$4350 × 0.36 = 4350 × 0.3 + 4350 × 0.06 = 1305 + 261 = 1566$
Total = $4350 + 1566 = \$5,916.00$
Let me now list all final answers clearly, double-checking a few more for errors:
1) \$5,092.00
2) \$5,280.00
3) \$4,524.00
4) \$1,524.00
5) \$11,660.00
6) \$3,834.00
7) \$7,650.00
8) \$4,368.00
9) \$9,360.00
10) \$2,475.00
11) \$8,362.00
12) \$3,390.00
13) \$8,200.00
14) \$5,175.00
15) \$11,200.00
16) \$8,174.00
17) \$4,794.00
18) \$6,562.50
19) \$10,042.50
20) \$2,640.00
21) \$2,805.00
22) \$1,798.00
23) \$1,573.00
24) \$8,694.00
25) \$11,400.00
26) \$1,652.00
27) \$5,254.00
28) \$5,840.00
29) \$10,450.00
30) \$5,916.00
All calculations verified step-by-step. No rounding needed — all are exact to cents.
Final Answer:
1) \$5,092.00
2) \$5,280.00
3) \$4,524.00
4) \$1,524.00
5) \$11,660.00
6) \$3,834.00
7) \$7,650.00
8) \$4,368.00
9) \$9,360.00
10) \$2,475.00
11) \$8,362.00
12) \$3,390.00
13) \$8,200.00
14) \$5,175.00
15) \$11,200.00
16) \$8,174.00
17) \$4,794.00
18) \$6,562.50
19) \$10,042.50
20) \$2,640.00
21) \$2,805.00
22) \$1,798.00
23) \$1,573.00
24) \$8,694.00
25) \$11,400.00
26) \$1,652.00
27) \$5,254.00
28) \$5,840.00
29) \$10,450.00
30) \$5,916.00
We are asked to find the ending balance using simple interest for each of the 30 problems.
The formula for simple interest is:
$$
\text{Interest} = P \times r \times t
$$
Where:
- $P$ = principal (starting amount)
- $r$ = annual interest rate (as a decimal, e.g., 12% → 0.12)
- $t$ = time in years
Then, the ending balance is:
$$
\text{Ending Balance} = P + \text{Interest} = P(1 + rt)
$$
Let’s verify with problem #1 as an example:
- $P = \$1,900.00$
- $r = 12\% = 0.12$
- $t = 14$ years
Interest = $1900 \times 0.12 \times 14 = 1900 \times 1.68 = \$3,192.00$
Ending balance = $1900 + 3192 = \$5,092.00$
But wait — the instruction says “Use simple interest to find the ending balance.” Since there are 30 problems, and the user did not ask to solve all 30, but only said “Solve the problem accurately”, and the image contains a list of 30 items — we need to clarify: Is the user asking for *all* answers? Or just one?
However, looking at the prompt:
> The user uploaded an image containing a task. Solve the problem accurately.
And the image shows a worksheet titled “Simple Interest” with 30 numbered problems — this is a standard homework sheet where students compute ending balances.
Since no specific item was selected, and the instruction says “Solve the problem”, but there are 30 problems — the most reasonable interpretation is that the user expects all 30 answers, because it's a single worksheet task.
So we will compute all 30 ending balances using the formula:
$$
\text{Ending Balance} = P \times (1 + r \times t)
$$
Let’s compute each carefully. I’ll do them in order, double-checking decimals and multiplication.
---
1) $P = 1900$, $r = 0.12$, $t = 14$
$rt = 0.12 \times 14 = 1.68$
$1 + rt = 2.68$
$1900 \times 2.68 = 1900 \times 2 + 1900 \times 0.68 = 3800 + 1292 = \$5,092.00$
2) $P = 3300$, $r = 0.12$, $t = 5$
$rt = 0.6$
$1 + rt = 1.6$
$3300 \times 1.6 = 5,280.00$
3) $P = 1950$, $r = 0.11$, $t = 12$
$rt = 1.32$
$1 + rt = 2.32$
$1950 \times 2.32$:
$1950 \times 2 = 3900$
$1950 \times 0.32 = 624$
Total = $4,524.00$
4) $P = 1200$, $r = 0.03$, $t = 9$
$rt = 0.27$
$1.27 \times 1200 = 1200 + 0.27×1200 = 1200 + 324 = \$1,524.00$
5) $P = 5500$, $r = 0.08$, $t = 14$
$rt = 1.12$
$1 + rt = 2.12$
$5500 × 2.12 = 5500×2 + 5500×0.12 = 11,000 + 660 = \$11,660.00$
6) $P = 2700$, $r = 0.03$, $t = 14$
$rt = 0.42$
$1.42 × 2700 = 2700 + 0.42×2700 = 2700 + 1134 = \$3,834.00$
7) $P = 5100$, $r = 0.05$, $t = 10$
$rt = 0.5$
$1.5 × 5100 = \$7,650.00$
8) $P = 2100$, $r = 0.12$, $t = 9$
$rt = 1.08$
$2.08 × 2100 = 2100×2 + 2100×0.08 = 4200 + 168 = \$4,368.00$
9) $P = 4500$, $r = 0.12$, $t = 9$
$rt = 1.08$
$2.08 × 4500 = 4500×2 + 4500×0.08 = 9000 + 360 = \$9,360.00$
10) $P = 2250$, $r = 0.02$, $t = 5$
$rt = 0.10$
$1.10 × 2250 = \$2,475.00$
11) $P = 3700$, $r = 0.18$, $t = 7$
$rt = 1.26$
$2.26 × 3700 = 3700×2 + 3700×0.26 = 7400 + 962 = \$8,362.00$
12) $P = 1500$, $r = 0.14$, $t = 9$
$rt = 1.26$
$2.26 × 1500 = 3390.00$
13) $P = 4100$, $r = 0.10$, $t = 10$
$rt = 1.0$
$2.0 × 4100 = \$8,200.00$
14) $P = 3450$, $r = 0.10$, $t = 5$
$rt = 0.5$
$1.5 × 3450 = 5,175.00$
15) $P = 5600$, $r = 0.10$, $t = 10$
$rt = 1.0$
$2.0 × 5600 = \$11,200.00$
16) $P = 3050$, $r = 0.12$, $t = 14$
$rt = 1.68$
$2.68 × 3050$:
$3050 × 2 = 6100$
$3050 × 0.68 = 3050 × 0.6 + 3050 × 0.08 = 1830 + 244 = 2074$
Total = $6100 + 2074 = \$8,174.00$
17) $P = 2350$, $r = 0.13$, $t = 8$
$rt = 1.04$
$2.04 × 2350 = 2350×2 + 2350×0.04 = 4700 + 94 = \$4,794.00$
18) $P = 5250$, $r = 0.05$, $t = 5$
$rt = 0.25$
$1.25 × 5250 = 6,562.50$
19) $P = 5150$, $r = 0.19$, $t = 5$
$rt = 0.95$
$1.95 × 5150$:
$5150 × 2 = 10,300$
Minus $5150 × 0.05 = 257.50$
→ $10,300 - 257.50 = \$10,042.50$
Alternatively: $5150 × 1.95 = 5150 × (2 − 0.05) = 10,300 − 257.5 = 10,042.5$
20) $P = 2200$, $r = 0.05$, $t = 4$
$rt = 0.20$
$1.20 × 2200 = \$2,640.00$
21) $P = 1700$, $r = 0.05$, $t = 13$
$rt = 0.65$
$1.65 × 1700 = 1700 + 0.65×1700 = 1700 + 1105 = \$2,805.00$
22) $P = 1550$, $r = 0.08$, $t = 2$
$rt = 0.16$
$1.16 × 1550 = 1550 + 0.16×1550 = 1550 + 248 = \$1,798.00$
23) $P = 1300$, $r = 0.07$, $t = 3$
$rt = 0.21$
$1.21 × 1300 = 1300 + 273 = \$1,573.00$
24) $P = 3150$, $r = 0.16$, $t = 11$
$rt = 1.76$
$2.76 × 3150$:
$3150 × 2 = 6300$
$3150 × 0.76 = 3150 × 0.7 + 3150 × 0.06 = 2205 + 189 = 2394$
Total = $6300 + 2394 = \$8,694.00$
25) $P = 5700$, $r = 0.10$, $t = 10$
$rt = 1.0$
$2.0 × 5700 = \$11,400.00$
26) $P = 1400$, $r = 0.09$, $t = 2$
$rt = 0.18$
$1.18 × 1400 = 1400 + 252 = \$1,652.00$
27) $P = 3550$, $r = 0.12$, $t = 4$
$rt = 0.48$
$1.48 × 3550$:
$3550 × 1 = 3550$
$3550 × 0.48 = 3550 × 0.4 + 3550 × 0.08 = 1420 + 284 = 1704$
Total = $3550 + 1704 = \$5,254.00$
28) $P = 3650$, $r = 0.15$, $t = 4$
$rt = 0.60$
$1.60 × 3650 = 3650 + 0.6×3650 = 3650 + 2190 = \$5,840.00$
29) $P = 4750$, $r = 0.15$, $t = 8$
$rt = 1.20$
$2.20 × 4750 = 4750×2 + 4750×0.2 = 9500 + 950 = \$10,450.00$
30) $P = 4350$, $r = 0.03$, $t = 12$
$rt = 0.36$
$1.36 × 4350$:
$4350 × 1 = 4350$
$4350 × 0.36 = 4350 × 0.3 + 4350 × 0.06 = 1305 + 261 = 1566$
Total = $4350 + 1566 = \$5,916.00$
Let me now list all final answers clearly, double-checking a few more for errors:
1) \$5,092.00
2) \$5,280.00
3) \$4,524.00
4) \$1,524.00
5) \$11,660.00
6) \$3,834.00
7) \$7,650.00
8) \$4,368.00
9) \$9,360.00
10) \$2,475.00
11) \$8,362.00
12) \$3,390.00
13) \$8,200.00
14) \$5,175.00
15) \$11,200.00
16) \$8,174.00
17) \$4,794.00
18) \$6,562.50
19) \$10,042.50
20) \$2,640.00
21) \$2,805.00
22) \$1,798.00
23) \$1,573.00
24) \$8,694.00
25) \$11,400.00
26) \$1,652.00
27) \$5,254.00
28) \$5,840.00
29) \$10,450.00
30) \$5,916.00
All calculations verified step-by-step. No rounding needed — all are exact to cents.
Final Answer:
1) \$5,092.00
2) \$5,280.00
3) \$4,524.00
4) \$1,524.00
5) \$11,660.00
6) \$3,834.00
7) \$7,650.00
8) \$4,368.00
9) \$9,360.00
10) \$2,475.00
11) \$8,362.00
12) \$3,390.00
13) \$8,200.00
14) \$5,175.00
15) \$11,200.00
16) \$8,174.00
17) \$4,794.00
18) \$6,562.50
19) \$10,042.50
20) \$2,640.00
21) \$2,805.00
22) \$1,798.00
23) \$1,573.00
24) \$8,694.00
25) \$11,400.00
26) \$1,652.00
27) \$5,254.00
28) \$5,840.00
29) \$10,450.00
30) \$5,916.00
Parent Tip: Review the logic above to help your child master the concept of simple interest worksheet for grade 7.