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Simplify complex number expressions and color according to the key.

A worksheet titled "Simplifying Complex Numbers" with math problems involving complex number operations, each problem linked to a color code for coloring.

A worksheet titled "Simplifying Complex Numbers" with math problems involving complex number operations, each problem linked to a color code for coloring.

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Show Answer Key & Explanations Step-by-step solution for: Simplifying Complex Numbers Coloring Activity | Complex numbers ...
It looks like you've uploaded a worksheet titled "Simplifying Complex Numbers", which contains a series of complex number operations (addition, subtraction, multiplication, division, and powers) that need to be simplified. The directions state:

> Simplify the complex expressions. Once the color of your answer shows, color the corresponding part of the coloring sheet.

Since I can't view images directly, I’ll guide you through how to solve these types of problems step-by-step, and then help you simplify each expression if you provide them in text form.

However, since you mentioned an image with tasks, let me walk you through the general method for simplifying complex numbers, and then I can help you solve each problem if you list them or describe what's in the image.

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🔷 What are Complex Numbers?



A complex number is written in the form:
$$
a + bi
$$
where:
- $ a $ and $ b $ are real numbers,
- $ i $ is the imaginary unit, where $ i = \sqrt{-1} $,
- $ i^2 = -1 $

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🔷 Basic Operations



#### 1. Addition/Subtraction
Combine like terms (real parts and imaginary parts separately).

Example:
$$
(3 + 2i) + (1 - 4i) = (3+1) + (2i - 4i) = 4 - 2i
$$

#### 2. Multiplication
Use distributive property (FOIL), and remember $ i^2 = -1 $.

Example:
$$
(2 + 3i)(1 - i) = 2(1) + 2(-i) + 3i(1) + 3i(-i) = 2 - 2i + 3i - 3i^2 = 2 + i + 3 = 5 + i
$$
(since $ -3i^2 = -3(-1) = 3 $)

#### 3. Division
Multiply numerator and denominator by the conjugate of the denominator.

Conjugate of $ a + bi $ is $ a - bi $.

Example:
$$
\frac{2 + 3i}{1 - i} = \frac{(2 + 3i)(1 + i)}{(1 - i)(1 + i)} = \frac{2 + 2i + 3i + 3i^2}{1 - i^2} = \frac{2 + 5i - 3}{1 + 1} = \frac{-1 + 5i}{2} = -\frac{1}{2} + \frac{5}{2}i
$$

#### 4. Powers of $ i $
Remember the cycle:
- $ i^1 = i $
- $ i^2 = -1 $
- $ i^3 = -i $
- $ i^4 = 1 $
- Then it repeats every 4.

So $ i^n $ depends on $ n \mod 4 $

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🔷 Common Problems on Such Sheets



Let’s suppose some typical problems from this worksheet (since I can’t see the image):

#### Example Problems:

1. $ (-2 + 18i) + (12 - 9i) $
→ $ (-2 + 12) + (18i - 9i) = 10 + 9i $

2. $ (-10 + 8i) - (-6 + 5i) $
→ $ -10 + 8i + 6 - 5i = (-4 + 3i) $

3. $ (2 - 5i)(2 + 3i) $
→ Use FOIL:
$ 2(2) + 2(3i) -5i(2) -5i(3i) = 4 + 6i -10i -15i^2 = 4 -4i +15 = 19 -4i $

4. $ (5 - 3i)(5 + 3i) $
→ Difference of squares: $ 25 - (3i)^2 = 25 - (-9) = 34 $

5. $ (-3 - 2i)^2 $
→ $ (-3)^2 + 2(-3)(-2i) + (-2i)^2 = 9 + 12i + 4i^2 = 9 + 12i -4 = 5 + 12i $

6. $ (8 + 2i)^2 $
→ $ 64 + 32i + 4i^2 = 64 + 32i -4 = 60 + 32i $

7. $ (1 - 5i)(2 + 3i) $
→ $ 1(2) + 1(3i) -5i(2) -5i(3i) = 2 + 3i -10i -15i^2 = 2 -7i +15 = 17 -7i $

8. $ \frac{4 + 3i}{2 - i} $
→ Multiply numerator and denominator by conjugate $ 2 + i $:
$$
\frac{(4 + 3i)(2 + i)}{(2 - i)(2 + i)} = \frac{8 + 4i + 6i + 3i^2}{4 - i^2} = \frac{8 + 10i -3}{4 + 1} = \frac{5 + 10i}{5} = 1 + 2i
$$

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How to Proceed



Please type out the problems from the image (or list them), and I will:
- Solve each one step-by-step,
- Give the simplified complex number,
- Tell you which color corresponds to that answer (if the key is provided),
- Help you complete the coloring sheet.

Alternatively, if you can describe the format (e.g., "Problem 1: (–2 + 18i) + (12 – 9i)", etc.), I can solve all of them.

Just reply with the list of problems, and I’ll solve them all!
Parent Tip: Review the logic above to help your child master the concept of simplify imaginary numbers worksheet joke.
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