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Worksheet for simplifying linear expressions with algebraic equations and solutions.

Simplifying Linear Expressions worksheet with algebraic equations and problems for practice.

Simplifying Linear Expressions worksheet with algebraic equations and problems for practice.

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Show Answer Key & Explanations Step-by-step solution for: Simplifying Algebraic Expression Worksheets
It looks like you've uploaded a worksheet titled "Simplifying Linear Expressions" with 10 problems involving simplifying algebraic expressions. Since I can't view images directly, I'll help you solve each problem step by step based on the text you provided.

Let me go through each problem and simplify the expressions:

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1. $ 3(2x - 4) + 5(x + 2) $



Step-by-step:
- Distribute:
$$
3(2x) - 3(4) + 5(x) + 5(2) = 6x - 12 + 5x + 10
$$
- Combine like terms:
$$
(6x + 5x) + (-12 + 10) = 11x - 2
$$

Answer: $ \boxed{11x - 2} $

---

2. $ 2(8x + 7) - 3(2x + 1) + 4(2x + 5) $



Step-by-step:
- Distribute:
$$
2(8x) + 2(7) - 3(2x) - 3(1) + 4(2x) + 4(5) = 16x + 14 - 6x - 3 + 8x + 20
$$
- Combine like terms:
$$
(16x - 6x + 8x) + (14 - 3 + 20) = 18x + 31
$$

Answer: $ \boxed{18x + 31} $

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3. $ 5(2x + 6) + 9(2 - 4x) + 15 $



Step-by-step:
- Distribute:
$$
5(2x) + 5(6) + 9(2) - 9(4x) + 15 = 10x + 30 + 18 - 36x + 15
$$
- Combine like terms:
$$
(10x - 36x) + (30 + 18 + 15) = -26x + 63
$$

Answer: $ \boxed{-26x + 63} $

---

4. $ 4(5x + 3) - 7(x + 5) + 3(2x - 3) $



Step-by-step:
- Distribute:
$$
4(5x) + 4(3) - 7(x) - 7(5) + 3(2x) - 3(3) = 20x + 12 - 7x - 35 + 6x - 9
$$
- Combine like terms:
$$
(20x - 7x + 6x) + (12 - 35 - 9) = 19x - 32
$$

Answer: $ \boxed{19x - 32} $

---

5. $ \frac{2}{3}(6x + 2) - 3(x + 2) + 2(3x + 1) $



Step-by-step:
- Distribute:
$$
\frac{2}{3}(6x) + \frac{2}{3}(2) - 3(x) - 3(2) + 2(3x) + 2(1)
= 4x + \frac{4}{3} - 3x - 6 + 6x + 2
$$
- Combine like terms:
$$
(4x - 3x + 6x) + \left(\frac{4}{3} - 6 + 2\right) = 7x + \left(\frac{4}{3} - 4\right)
= 7x + \left(\frac{4}{3} - \frac{12}{3}\right) = 7x - \frac{8}{3}
$$

Answer: $ \boxed{7x - \frac{8}{3}} $

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6. $ \frac{1}{2}(x - 2) + \frac{2}{3}x + \frac{1}{2}(-2x) $



Step-by-step:
- Distribute:
$$
\frac{1}{2}x - 1 + \frac{2}{3}x - x
$$
- Combine like terms:
$$
\left(\frac{1}{2}x + \frac{2}{3}x - x\right) - 1
$$
- Find common denominator for coefficients:
$$
\frac{3}{6}x + \frac{4}{6}x - \frac{6}{6}x = \frac{1}{6}x
$$
- So:
$$
\frac{1}{6}x - 1
$$

Answer: $ \boxed{\frac{1}{6}x - 1} $

---

7. $ 4(3x + 4)(2y - 1) + 2(4xy + 2) $



Wait — this expression has two variables, $x$ and $y$, and includes a product of binomials.

But let's check: Is it $4(3x + 4)(2y - 1)$ or is there a typo?

Assuming it's meant to be simplified as written:

Step-by-step:

First, expand $ (3x + 4)(2y - 1) $:
$$
= 3x(2y) + 3x(-1) + 4(2y) + 4(-1) = 6xy - 3x + 8y - 4
$$

Now multiply by 4:
$$
4(6xy - 3x + 8y - 4) = 24xy - 12x + 32y - 16
$$

Now add $ 2(4xy + 2) = 8xy + 4 $

Add both parts:
$$
(24xy + 8xy) + (-12x) + 32y + (-16 + 4) = 32xy - 12x + 32y - 12
$$

Answer: $ \boxed{32xy - 12x + 32y - 12} $

---

8. $ \frac{1}{2}(x + 2)(2x - 1) + 3(6x + 3) $



Again, two variables? But only $x$. Let's assume it's just $x$.

First, expand $ (x + 2)(2x - 1) $:
$$
= x(2x) + x(-1) + 2(2x) + 2(-1) = 2x^2 - x + 4x - 2 = 2x^2 + 3x - 2
$$

Multiply by $ \frac{1}{2} $:
$$
\frac{1}{2}(2x^2 + 3x - 2) = x^2 + \frac{3}{2}x - 1
$$

Now $ 3(6x + 3) = 18x + 9 $

Add:
$$
x^2 + \frac{3}{2}x - 1 + 18x + 9 = x^2 + \left(\frac{3}{2}x + 18x\right) + 8
= x^2 + \frac{39}{2}x + 8
$$

Answer: $ \boxed{x^2 + \frac{39}{2}x + 8} $

Note: This is quadratic, not linear. If the original problem was supposed to be linear, double-check if there’s a typo.

---

9. $ \frac{3}{4}(6x - 18) + 4(2x - 3) + 2x $



Step-by-step:
- Distribute:
$$
\frac{3}{4}(6x) - \frac{3}{4}(18) + 8x - 12 + 2x
= \frac{18}{4}x - \frac{54}{4} + 8x - 12 + 2x
= \frac{9}{2}x - 13.5 + 8x - 12 + 2x
$$
- Convert to fractions:
$$
\frac{9}{2}x + 8x + 2x = \frac{9}{2}x + \frac{16}{2}x + \frac{4}{2}x = \frac{29}{2}x
$$
- Constants: $-13.5 - 12 = -25.5 = -\frac{51}{2}$

Answer: $ \boxed{\frac{29}{2}x - \frac{51}{2}} $

Or write as: $ \boxed{\frac{29x - 51}{2}} $

---

10. $ 4(2x + 3) - 3(2x - 4) + 3(2x - 5) $



Step-by-step:
- Distribute:
$$
8x + 12 - 6x + 12 + 6x - 15
$$
- Combine like terms:
$$
(8x - 6x + 6x) + (12 + 12 - 15) = 8x + 9
$$

Answer: $ \boxed{8x + 9} $

---

Final Answers Summary:



| Problem | Answer |
|--------|--------|
| 1 | $ 11x - 2 $ |
| 2 | $ 18x + 31 $ |
| 3 | $ -26x + 63 $ |
| 4 | $ 19x - 32 $ |
| 5 | $ 7x - \frac{8}{3} $ |
| 6 | $ \frac{1}{6}x - 1 $ |
| 7 | $ 32xy - 12x + 32y - 12 $ |
| 8 | $ x^2 + \frac{39}{2}x + 8 $ |
| 9 | $ \frac{29}{2}x - \frac{51}{2} $ |
| 10 | $ 8x + 9 $ |

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Let me know if you'd like these rewritten in decimal form or if you want help checking any specific one!
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