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Mid-Year Review math worksheet with six problems for students to solve and write answers in provided boxes.

Mid-Year Review worksheet for Part 1, featuring six math problems involving number writing, digit value, pattern completion, addition, multiplication, and symbol substitution, with blank boxes for answers.

Mid-Year Review worksheet for Part 1, featuring six math problems involving number writing, digit value, pattern completion, addition, multiplication, and symbol substitution, with blank boxes for answers.

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Show Answer Key & Explanations Step-by-step solution for: Singapore Math: Grade 3 Primary Mathematics Intensive Practice 3A ...
Let’s solve each problem one by one, step by step.

---

1. Write 5065 in words.

Break it down:
- 5000 = five thousand
- 60 = sixty
- 5 = five

So, 5065 = five thousand and sixty-five

*(Note: In some regions, “and” is used before the tens/ones; in others, it’s omitted. But for school math, including “and” is common and acceptable.)*

Final answer for #1: five thousand and sixty-five

---

2. In the numeral 8916, what does the digit ‘9’ stand for?

Look at place values from right to left:
- 6 → ones
- 1 → tens
- 9 → hundreds
- 8 → thousands

So, the 9 is in the hundreds place → it stands for 900

Final answer for #2: 900

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3. Fill in the missing number in the pattern below.

Pattern:
2685, 2695, ______, 2715

Find the difference between first two numbers:
2695 - 2685 = 10

Check next jump:
If we add 10 to 2695 → 2695 + 10 = 2705

Then check if adding 10 again gives 2715:
2705 + 10 = 2715

So the missing number is 2705

Final answer for #3: 2705

---

4. What must you add to 5621 to get 8000?

We need to find:
? + 5621 = 8000

So subtract:
8000 - 5621 = ?

Do the subtraction:

```
8000
- 5621
------
```

Start from right:
- 0 - 1 → can’t do, borrow → 10 - 1 = 9 (but previous digit becomes 9 after borrowing)
Actually, better to break it:

8000 - 5621 = (8000 - 5000) - 621 = 3000 - 621

Now 3000 - 621:

3000 - 600 = 2400
2400 - 21 = 2379

Or directly:

```
8000
- 5621
-------
2379
```

Final answer for #4: 2379

---

5. The quotient of 512 and 8 is the same as □ × □. What is the missing number in each box if both are the same number?

First, find quotient of 512 ÷ 8:

512 ÷ 8 = ?

8 × 60 = 480
512 - 480 = 32
8 × 4 = 32
So 60 + 4 = 64

So 512 ÷ 8 = 64

Now, we want: □ × □ = 64, and both boxes have the same number.

That means: ? × ? = 64 → so ?² = 64 → ? = √64 = 8

Because 8 × 8 = 64

Final answer for #5: 8

---

**6. △ + ◇ + ⬠ = 10,000
If △ = 3992 and ⬠ = 2047, find the value of ◇.**

Plug in known values:

3992 + ◇ + 2047 = 10000

Add 3992 + 2047:

3992 + 2000 = 5992
5992 + 47 = 6039

So:

6039 + ◇ = 10000

Subtract:

◇ = 10000 - 6039

Calculate:

10000 - 6000 = 4000
But we subtracted 39 too many? Wait — actually:

Better:

10000 - 6039

= (10000 - 6000) - 39 = 4000 - 39 = 3961

Double-check:

3992 + 3961 + 2047 = ?

First, 3992 + 2047 = 6039 (as before)
6039 + 3961 = ?

6000 + 3900 = 9900
39 + 61 = 100
Total = 9900 + 100 = 10000

Final answer for #6: 3961

---

Final Answer:
1. five thousand and sixty-five
2. 900
3. 2705
4. 2379
5. 8
6. 3961
Parent Tip: Review the logic above to help your child master the concept of singapore math 3rd grade.
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