Easy Beginner Sudoku Puzzle with numbers partially filled in, ideal for kids and beginners.

Explanation:
We are given a Sudoku puzzle labeled “EASY Beginner Sudoku”. The goal is to fill in the empty cells so that each row, each column, and each of the nine 3×3 boxes contains all digits from 1 to 9 with no repeats.

Let’s solve it step by step using logic — focusing first on cells with only one possible number (called “single candidates”).

I’ll label rows 1–9 (top to bottom) and columns A–I (left to right), so cell (R1,C1) is top-left.

Given grid (with blanks as underscores):

Row 1: 5 _ _ | 4 6 7 | 3 _ 9
Row 2: 9 _ 3 | 8 1 _ | 4 2 7
Row 3: 1 7 4 | 2 _ 3 | _ _ _
Row 4: 2 3 1 | 9 7 6 | 8 5 4
Row 5: 8 5 7 | 1 2 4 | _ 9 _
Row 6: 4 9 6 | 3 _ 8 | 1 7 2
Row 7: _ _ _ | _ 8 9 | 2 6 _
Row 8: 7 8 2 | 6 4 1 | _ _ 5
Row 9: _ 1 _ | _ _ _ | 7 _ 8

Let’s start with easy placements.

Box 1 (rows 1–3, cols 1–3):
Cells:
(1,1)=5, (1,2)=?, (1,3)=?
(2,1)=9, (2,2)=?, (2,3)=3
(3,1)=1, (3,2)=7, (3,3)=4

Numbers present: 1,3,4,5,7,9 → missing: 2,6,8
Empty cells: (1,2), (1,3), (2,2)

- (1,2): Check row 1: has 5,4,6,7,3,9 → missing: 1,2,8
Column 2: has ?, ?, 7, 3, 5, 9, ?, 8, 1 → present: 1,3,5,7,8,9 → missing: 2,4,6
Intersection of row & column missing = {2} (since 2 is only common). So (1,2) = 2 ✔

Now update row 1: 5 2 _ | 4 6 7 | 3 _ 9
Box 1 now has: 5,2,?, 9,?,3, 1,7,4 → missing: 6,8
Empty: (1,3), (2,2)

- (1,3): Row 1 missing now: 1,8 (since 2 placed)
Column 3: values: ?,3,4,1,7,6,?,2,? → present: 1,2,3,4,6,7 → missing: 5,8,9
Common with row missing {1,8} ∩ {5,8,9} = {8} → so (1,3) = 8 ✔

Now box 1 only missing 6, and only cell left is (2,2). So (2,2) = 6.

Update row 2: 9 6 3 | 8 1 _ | 4 2 7
Now row 2 missing only one number: numbers present: 9,6,3,8,1,4,2,7 → missing 5 → so (2,6) = 5 ✔

Row 2 complete: 9 6 3 | 8 1 5 | 4 2 7

Now look at Column 6:
R1C6 = 7
R2C6 = 5
R3C6 = 3
R4C6 = 6
R5C6 = 4
R6C6 = 8
R7C6 = 9
R8C6 = 1
R9C6 = ?
So column 6 has: 7,5,3,6,4,8,9,1 → missing only 2 → R9C6 = 2 ✔

Now row 9: _ 1 _ | _ _ 2 | 7 _ 8
Missing numbers in row 9: digits 1–9 minus {1,2,7,8} = {3,4,5,6,9}

Look at Box 7 (rows 7–9, cols 1–3):
R7: _, _, _
R8: 7,8,2
R9: _,1,_
So present: 1,2,7,8 → missing: 3,4,5,6,9
Empty cells: (7,1), (7,2), (7,3), (9,1), (9,3)

Check Column 1:
R1=5, R2=9, R3=1, R4=2, R5=8, R6=4, R7=?, R8=7, R9=?
Present: 1,2,4,5,7,8,9 → missing: 3,6
So (7,1) and (9,1) ∈ {3,6}

Check Row 7: _ _ _ | _ 8 9 | 2 6 _
Row 7 has: 8,9,2,6 → missing: 1,3,4,5,7
But column 1 restricts (7,1) to {3,6}, and 6 already in row 7 (at col 8), so (7,1) ≠ 6 → must be 3
→ (7,1) = 3 ✔
Then (9,1) = 6 (only remaining in column 1)

Update:
R7: 3 _ _ | _ 8 9 | 2 6 _
R9: 6 1 _ | _ _ 2 | 7 _ 8

Now row 9: 6 1 _ | _ _ 2 | 7 _ 8
Missing: 3,4,5,9 (since 1,2,6,7,8 used)

Look at Column 3:
R1=8, R2=3, R3=4, R4=1, R5=7, R6=6, R7=?, R8=2, R9=?
Present: 1,2,3,4,6,7,8 → missing: 5,9
So (7,3) and (9,3) ∈ {5,9}

Row 7 missing: 1,4,5,7 (since 2,3,6,8,9 placed)
So (7,3) ∈ {5} (since 9 not allowed — row 7 already has 9 at col 6)
→ (7,3) = 5 ✔
Then (9,3) = 9

Update:
R7: 3 _ 5 | _ 8 9 | 2 6 _
R9: 6 1 9 | _ _ 2 | 7 _ 8

Now row 7 missing: 1,4,7
Cells left: (7,2), (7,4), (7,9)

Column 2:
R1=2, R2=6, R3=7, R4=3, R5=5, R6=9, R7=?, R8=8, R9=1
Present: 1,2,3,5,6,7,8,9 → missing only 4
→ So (7,2) = 4 ✔

Row 7 now: 3 4 5 | _ 8 9 | 2 6 _
Missing: 1,7
Cells left: (7,4), (7,9)

Column 4:
R1=4, R2=8, R3=2, R4=9, R5=1, R6=3, R7=?, R8=6, R9=?
Present: 1,2,3,4,6,8,9 → missing: 5,7
So (7,4) ∈ {5,7}, but row 7 missing {1,7}, so only 7 fits → (7,4) = 7 ✔
Then (7,9) = 1

Row 7 complete: 3 4 5 | 7 8 9 | 2 6 1

Now column 9:
R1=9, R2=7, R3=?, R4=4, R5=?, R6=2, R7=1, R8=5, R9=8
Present: 1,2,4,5,7,8,9 → missing: 3,6
So (3,9) and (5,9) ∈ {3,6}

Row 3: 1 7 4 | 2 _ 3 | _ _ _
Used: 1,2,3,4,7 → missing: 5,6,8,9
Cells: (3,5), (3,7), (3,8), (3,9)

Column 5:
R1=6, R2=1, R3=?, R4=7, R5=2, R6=?, R7=8, R8=4, R9=?
Present: 1,2,4,6,7,8 → missing: 3,5,9
So (3,5) ∈ {3,5,9}

But row 3 already has 3 at (3,6), so (3,5) ≠ 3 → {5,9}

Look at Box 2 (rows 1–3, cols 4–6):
R1: 4 6 7
R2: 8 1 5
R3: 2 ? 3
So missing numbers: 9 (only one missing!) because 1–9 minus {1,2,3,4,5,6,7,8} = 9
→ So (3,5) = 9 ✔

Now row 3: 1 7 4 | 2 9 3 | _ _ _
Missing: 5,6,8
Cells: (3,7), (3,8), (3,9)

Column 7:
R1=3, R2=4, R3=?, R4=8, R5=?, R6=1, R7=2, R8=?, R9=7
Present: 1,2,3,4,7,8 → missing: 5,6,9
But row 3 missing {5,6,8}, so intersection = {5,6}

Column 8:
R1=?, R2=2, R3=?, R4=5, R5=9, R6=7, R7=6, R8=?, R9=?
Present: 2,5,6,7,9 → missing: 1,3,4,8
Row 3 needs {5,6,8} → only 8 possible for (3,8)
→ (3,8) = 8 ✔

Now row 3: 1 7 4 | 2 9 3 | _ 8 _
Missing: 5,6
(3,7) and (3,9)

Column 7 missing: 5,6,9; row 3 allows 5 or 6
Column 9 missing: 3,6 — but (3,9) can’t be 3 (row 3 already has 3), so (3,9) = 6
→ Then (3,7) = 5

Row 3 complete: 1 7 4 | 2 9 3 | 5 8 6

Now column 9: we had missing 3,6; now (3,9)=6, so (5,9)=3 ✔

Row 5: 8 5 7 | 1 2 4 | _ 9 3
Missing: 6 (only one left) → (5,7) = 6 ✔

Row 5 complete: 8 5 7 | 1 2 4 | 6 9 3

Now column 7:
R1=3, R2=4, R3=5, R4=8, R5=6, R6=1, R7=2, R8=?, R9=7
Present: 1,2,3,4,5,6,7,8 → missing: 9
→ (8,7) = 9 ✔

Row 8: 7 8 2 | 6 4 1 | 9 _ 5
Missing: 3 (only one) → (8,8) = 3 ✔

Now column 8:
R1=?, R2=2, R3=8, R4=5, R5=9, R6=7, R7=6, R8=3, R9=?
Present: 2,3,5,6,7,8,9 → missing: 1,4
So (1,8) and (9,8) ∈ {1,4}

Row 1: 5 2 8 | 4 6 7 | 3 _ 9
Missing: 1 (only one) → (1,8) = 1 ✔
Then (9,8) = 4

Row 9: 6 1 9 | _ _ 2 | 7 4 8
Missing: 3,5
Cells: (9,4), (9,5)

Column 4:
R1=4, R2=8, R3=2, R4=9, R5=1, R6=3, R7=7, R8=6, R9=?
Present: 1,2,3,4,6,7,8,9 → missing: 5
→ (9,4) = 5 ✔
Then (9,5) = 3

Row 9 complete: 6 1 9 | 5 3 2 | 7 4 8

Now only missing cell is (6,5) — let’s verify:

Row 6: 4 9 6 | 3 _ 8 | 1 7 2
Missing: 5 → (6,5) = 5 ✔

All cells filled. Let’s quickly verify a few boxes:

Box 3 (R1–3, C7–9):
3 1 9
4 2 7
5 8 6 → all 1–9 ✔️

Box 6 (R4–6, C7–9):
8 5 4
6 9 3
1 7 2 → ✔️

Box 9 (R7–9, C7–9):
2 6 1
9 3 5
7 4 8 → ✔️

Everything checks out.

Final Answer:
The completed Sudoku grid is:

5 2 8 | 4 6 7 | 3 1 9
9 6 3 | 8 1 5 | 4 2 7
1 7 4 | 2 9 3 | 5 8 6
2 3 1 | 9 7 6 | 8 5 4
8 5 7 | 1 2 4 | 6 9 3
4 9 6 | 3 5 8 | 1 7 2
3 4 5 | 7 8 9 | 2 6 1
7 8 2 | 6 4 1 | 9 3 5
6 1 9 | 5 3 2 | 7 4 8

Final Answer:
528467319963815427174293586231976854857124693496358172345789261782641935619532748