Free Printable Solubility Curve Worksheets - Free Printable
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Step-by-step solution for: Free Printable Solubility Curve Worksheets
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Step-by-step solution for: Free Printable Solubility Curve Worksheets
Here's the complete solution to the worksheet “Interpreting Solubility Curve,” with clear explanations for each question.
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1. Define solubility.
> Solubility is the maximum amount of a solute (in grams) that can dissolve in a specific amount of solvent (usually 100 g of water) at a given temperature to form a saturated solution.
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2. Using the solubility curve below, answer the given questions.
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I. What is the solvent in this solubility curve?
> Water (H₂O)
> *Explanation:* The y-axis is labeled “Amount of solute in grams / 100 g H₂O,” which means water is the solvent used for all measurements.
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II. Saturation points are given per how much of the solvent?
> 100 grams of water (H₂O)
> *Explanation:* All values on the y-axis are normalized to “per 100 g H₂O,” so saturation points are given per 100 g of water.
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III. What is the saturation point of NaNO₃ at 10°C, 40°C, & 80°C?
> - 10°C = 80 g
> - 40°C = 105 g
> - 80°C = 145 g
> *Explanation:* Locate NaNO₃’s curve (the red line). At each temperature, go up to the curve and read the corresponding value on the y-axis.
> - At 10°C → ~80 g
> - At 40°C → ~105 g
> - At 80°C → ~145 g
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IV. How much NH₃ can you dissolve in water at 10°C, 30°C, & 90°C?
> - 10°C = 70 g
> - 30°C = 45 g
> - 90°C = 10 g
> *Explanation:* Find the NH₃ curve (blue line, decreasing as temperature increases). Read the y-values at each temperature:
> - At 10°C → ~70 g
> - At 30°C → ~45 g
> - At 90°C → ~10 g
> *(Note: NH₃ is a gas — its solubility decreases with increasing temperature.)*
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V. Which salt is the least soluble in water?
> SO₂ (Sulfur dioxide) — *but note: SO₂ is not a salt, it’s a gas.*
> If we interpret “salt” strictly as ionic compounds (like NaCl, KCl, etc.), then:
> KClO₃ (Potassium chlorate) is the least soluble among true salts.
> *Explanation:* Look for the curve that stays lowest across most temperatures. SO₂’s curve is lowest overall, but it’s not a salt. Among salts (NaCl, KCl, KNO₃, NH₄Cl, KClO₃, NaNO₃), KClO₃ has the lowest solubility, especially at low temperatures (~5 g at 0°C).
> ✔ Final Answer: KClO₃ (if restricting to salts)
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VI. How many grams of potassium chloride can be dissolved in 200 g of water at 80°C?
> 100 grams
> *Explanation:*
> - First, find solubility of KCl at 80°C → from the graph, ~50 g per 100 g H₂O.
> - So for 200 g of water: 50 g × 2 = 100 g
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VII. At 40 °C, how much potassium nitrate will be dissolved in 300 g of water?
> 150 grams
> *Explanation:*
> - From the graph, solubility of KNO₃ at 40°C is ~50 g per 100 g H₂O.
> - For 300 g of water: 50 g × 3 = 150 g
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VIII. Which salt shows the least change in solubility from 0° to 100° C?
> NaCl (Sodium chloride)
> *Explanation:* Look at the slope of each salt’s curve. NaCl’s curve (orange line near bottom) is almost flat — meaning its solubility changes very little with temperature (from ~35 g at 0°C to ~39 g at 100°C). This is the smallest change among all salts shown.
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IX. Which substance shows a decrease in solubility from 0° to 100° C?
> NH₃ (Ammonia), SO₂ (Sulfur dioxide), HCl (Hydrogen chloride)
> *Explanation:* These are gases. Their curves slope downward — solubility decreases as temperature increases.
> - NH₃: from ~90 g at 0°C to ~10 g at 100°C
> - SO₂: from ~25 g at 0°C to ~5 g at 100°C
> - HCl: from ~80 g at 0°C to ~50 g at 100°C
> ✔ All three show decreased solubility with increasing temperature.
> *If only one answer is expected, pick NH₃ — it’s the most prominent example.*
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X. At 30 °C, 90 g of sodium nitrate is dissolved in 100 g water. Is this solution saturated, unsaturated, or supersaturated?
> Supersaturated
> *Explanation:*
> - At 30°C, the solubility of NaNO₃ is ~95 g per 100 g water (from the red curve).
> - Since 90 g < 95 g, the solution is actually unsaturated.
> ❗ Correction: Let’s double-check the graph carefully.
> - At 30°C, NaNO₃ curve is slightly above 90 — around 95 g.
> - So 90 g dissolved in 100 g water at 30°C is less than the saturation point → unsaturated.
> ✔ Correct Answer: Unsaturated
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## 📝 Final Answers Summary:
1. Solubility = max grams of solute that dissolves in 100 g water at a given temp to form saturated solution.
2. I. Water (H₂O)
II. 100 g H₂O
III. 10°C = 80 g; 40°C = 105 g; 80°C = 145 g
IV. 10°C = 70 g; 30°C = 45 g; 90°C = 10 g
V. KClO₃ (among salts)
VI. 100 g
VII. 150 g
VIII. NaCl
IX. NH₃, SO₂, HCl (gases) — or just NH₃ if one needed
X. Unsaturated
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✔ You’re all set! This worksheet covers key concepts: reading curves, scaling solubility, identifying trends, and classifying solutions. Great practice!
---
1. Define solubility.
> Solubility is the maximum amount of a solute (in grams) that can dissolve in a specific amount of solvent (usually 100 g of water) at a given temperature to form a saturated solution.
---
2. Using the solubility curve below, answer the given questions.
---
I. What is the solvent in this solubility curve?
> Water (H₂O)
> *Explanation:* The y-axis is labeled “Amount of solute in grams / 100 g H₂O,” which means water is the solvent used for all measurements.
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II. Saturation points are given per how much of the solvent?
> 100 grams of water (H₂O)
> *Explanation:* All values on the y-axis are normalized to “per 100 g H₂O,” so saturation points are given per 100 g of water.
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III. What is the saturation point of NaNO₃ at 10°C, 40°C, & 80°C?
> - 10°C = 80 g
> - 40°C = 105 g
> - 80°C = 145 g
> *Explanation:* Locate NaNO₃’s curve (the red line). At each temperature, go up to the curve and read the corresponding value on the y-axis.
> - At 10°C → ~80 g
> - At 40°C → ~105 g
> - At 80°C → ~145 g
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IV. How much NH₃ can you dissolve in water at 10°C, 30°C, & 90°C?
> - 10°C = 70 g
> - 30°C = 45 g
> - 90°C = 10 g
> *Explanation:* Find the NH₃ curve (blue line, decreasing as temperature increases). Read the y-values at each temperature:
> - At 10°C → ~70 g
> - At 30°C → ~45 g
> - At 90°C → ~10 g
> *(Note: NH₃ is a gas — its solubility decreases with increasing temperature.)*
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V. Which salt is the least soluble in water?
> SO₂ (Sulfur dioxide) — *but note: SO₂ is not a salt, it’s a gas.*
> If we interpret “salt” strictly as ionic compounds (like NaCl, KCl, etc.), then:
> KClO₃ (Potassium chlorate) is the least soluble among true salts.
> *Explanation:* Look for the curve that stays lowest across most temperatures. SO₂’s curve is lowest overall, but it’s not a salt. Among salts (NaCl, KCl, KNO₃, NH₄Cl, KClO₃, NaNO₃), KClO₃ has the lowest solubility, especially at low temperatures (~5 g at 0°C).
> ✔ Final Answer: KClO₃ (if restricting to salts)
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VI. How many grams of potassium chloride can be dissolved in 200 g of water at 80°C?
> 100 grams
> *Explanation:*
> - First, find solubility of KCl at 80°C → from the graph, ~50 g per 100 g H₂O.
> - So for 200 g of water: 50 g × 2 = 100 g
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VII. At 40 °C, how much potassium nitrate will be dissolved in 300 g of water?
> 150 grams
> *Explanation:*
> - From the graph, solubility of KNO₃ at 40°C is ~50 g per 100 g H₂O.
> - For 300 g of water: 50 g × 3 = 150 g
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VIII. Which salt shows the least change in solubility from 0° to 100° C?
> NaCl (Sodium chloride)
> *Explanation:* Look at the slope of each salt’s curve. NaCl’s curve (orange line near bottom) is almost flat — meaning its solubility changes very little with temperature (from ~35 g at 0°C to ~39 g at 100°C). This is the smallest change among all salts shown.
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IX. Which substance shows a decrease in solubility from 0° to 100° C?
> NH₃ (Ammonia), SO₂ (Sulfur dioxide), HCl (Hydrogen chloride)
> *Explanation:* These are gases. Their curves slope downward — solubility decreases as temperature increases.
> - NH₃: from ~90 g at 0°C to ~10 g at 100°C
> - SO₂: from ~25 g at 0°C to ~5 g at 100°C
> - HCl: from ~80 g at 0°C to ~50 g at 100°C
> ✔ All three show decreased solubility with increasing temperature.
> *If only one answer is expected, pick NH₃ — it’s the most prominent example.*
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X. At 30 °C, 90 g of sodium nitrate is dissolved in 100 g water. Is this solution saturated, unsaturated, or supersaturated?
> Supersaturated
> *Explanation:*
> - At 30°C, the solubility of NaNO₃ is ~95 g per 100 g water (from the red curve).
> - Since 90 g < 95 g, the solution is actually unsaturated.
> ❗ Correction: Let’s double-check the graph carefully.
> - At 30°C, NaNO₃ curve is slightly above 90 — around 95 g.
> - So 90 g dissolved in 100 g water at 30°C is less than the saturation point → unsaturated.
> ✔ Correct Answer: Unsaturated
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## 📝 Final Answers Summary:
1. Solubility = max grams of solute that dissolves in 100 g water at a given temp to form saturated solution.
2. I. Water (H₂O)
II. 100 g H₂O
III. 10°C = 80 g; 40°C = 105 g; 80°C = 145 g
IV. 10°C = 70 g; 30°C = 45 g; 90°C = 10 g
V. KClO₃ (among salts)
VI. 100 g
VII. 150 g
VIII. NaCl
IX. NH₃, SO₂, HCl (gases) — or just NH₃ if one needed
X. Unsaturated
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✔ You’re all set! This worksheet covers key concepts: reading curves, scaling solubility, identifying trends, and classifying solutions. Great practice!
Parent Tip: Review the logic above to help your child master the concept of solubility graph worksheet.
