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Free Printable Solubility Worksheets - Free Printable

Free Printable Solubility Worksheets

Educational worksheet: Free Printable Solubility Worksheets. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Free Printable Solubility Worksheets
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Let's go through each question step by step and solve the problems with clear explanations.

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1. Match the following. Write the correct letter in the blank provided.



| Term | Match |
|------|-------|
| 1. Solute ______ | B. The part that dissolves into the solution |
| 2. Solvent ______ | E. The part that dissolves something |
| 3. Dissolve ______ | D. When something is seen to disappear inside the solvent |
| 4. Stirring ______ | C. Increase solubility by moving molecules faster |
| 5. Concentration ______ | A. Tells you how much solvent is dissolved in the solution |

> ✔ Explanation:
> - Solute = substance being dissolved (e.g., sugar in water).
> - Solvent = substance doing the dissolving (e.g., water).
> - Dissolve = when a solute disappears into the solvent.
> - Stirring helps speed up dissolution by increasing contact between particles.
> - Concentration refers to how much solute is in a given amount of solvent — not how much solvent is dissolved (that’s backwards). But here, option A says “how much solvent is dissolved” which is incorrect. Wait — let's double-check.

Wait! There's an error in option A:

> A. Tells you how much solvent is dissolved in the solution → This is wrong.
> Concentration tells you how much solute is dissolved in the solvent.

But since this is the only choice left for "concentration", and all others are correctly matched, there might be a typo in the options.

Actually, option A should say: *"Tells you how much solute is dissolved in the solution"*, not solvent.

So likely, it's a mistake in the worksheet. But based on what's given:

- Concentration → A, even though it's incorrectly worded.
However, logically, concentration measures solute per solvent, so A is wrong.

Let’s re-evaluate:

- A: "Tells you how much solvent is dissolved..." → ✘ Incorrect
- B: "The part that dissolves into the solution" → Solute ✔
- C: "Increase solubility..." → Stirring ✔
- D: "When something is seen to disappear..." → Dissolve ✔
- E: "The part that dissolves something" → Solvent ✔

So:
- 1. Solute → B
- 2. Solvent → E
- 3. Dissolve → D
- 4. Stirring → C
- 5. Concentration → ???

No option correctly defines concentration. But A is the closest if it were corrected. Since it says “how much solvent is dissolved”, that’s incorrect.

But perhaps it’s meant to say “how much solute is dissolved”. Assuming a typo, we’ll assign:

> 5. Concentration → A (with note that it's poorly worded)

✔ Final Answers:
1. B
2. E
3. D
4. C
5. A *(with caveat)*

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2. Determine if the following statements are true or false.



a. Solubility increases if you stir a solute into a solution.
→ False
Stirring speeds up dissolution rate, but does not change the solubility (maximum amount that can dissolve). Solubility is a property dependent on temperature, pressure, etc.

b. All solutes have the same solubility in a given solvent.
→ False
Different solutes have different solubilities in the same solvent. For example, sugar vs salt in water.

c. There is a limit on the amount of solute that can dissolve in a given solvent.
→ True
This is the definition of saturation.

d. You can dissolve additional solutes in an unsaturated solution.
→ True
An unsaturated solution can still dissolve more solute.

✔ Answers:
a. False
b. False
c. True
d. True

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3. Give three ways to make sugar dissolve faster.



Three methods to increase the rate of dissolution:
1. Stirring – increases contact between sugar and water.
2. Heating (using warm/hot water) – increases kinetic energy, helping molecules move faster.
3. Using smaller particles (powdered sugar) – more surface area exposed.

✔ Answer: Stirring, heating, using smaller particles

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4. Which one will dissolve faster? Circle the correct answer.



a. Powdered sugar or granulated sugar?
→ Powdered sugar (smaller particles → more surface area)

b. In hot water or in cold water?
→ Hot water (higher temperature increases molecular motion)

c. Stirred or not stirred?
→ Stirred (increases mixing)

d. Large particles or small particles?
→ Small particles (more surface area)

✔ Answers:
a. Powdered sugar
b. In hot water
c. Stirred
d. Small particles

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5. 65 g of sugar is dissolved in 750 ml of water. What is the concentration of the solution?



We need to calculate concentration, usually expressed as g/mL or g/100 mL.

Given:
- Mass of solute = 65 g
- Volume of solvent = 750 mL

Assuming volume of solution ≈ 750 mL (since sugar doesn’t significantly change volume), then:

$$
\text{Concentration} = \frac{65\ \text{g}}{750\ \text{mL}} = 0.0867\ \text{g/mL}
$$

Or better, express per 100 mL:

$$
\frac{65}{750} \times 100 = 8.67\ \text{g per 100 mL}
$$

✔ Answer: 8.67 g/100 mL (or 0.0867 g/mL)

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6. Which is more concentrated: 34 g of salt in 100 mL of water or 100 g of salt in 1500 mL of water?



Calculate concentration for both:

Option 1:
34 g / 100 mL = 0.34 g/mL

Option 2:
100 g / 1500 mL = 0.0667 g/mL

Compare:
- 0.34 > 0.0667

✔ So, 34 g in 100 mL is more concentrated.

Answer: 34 g of salt in 100 mL of water

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7. If the solubility of salt in water was determined to be 0.5 g/mL, would a solution with 50 g of salt in 150 mL of water be considered saturated?



First, find maximum salt that can dissolve in 150 mL:

Solubility = 0.5 g/mL
So max solute = 0.5 × 150 = 75 g

But only 50 g is added → less than 75 g

So, it is unsaturated.

✔ Answer: No, it is not saturated because 50 g < 75 g (maximum possible).

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✔ Final Answers Summary:



#### 1. Matching
1. B
2. E
3. D
4. C
5. A *(Note: Option A is misworded; should say "solute" not "solvent")*

#### 2. True/False
a. False
b. False
c. True
d. True

#### 3. Ways to dissolve sugar faster
- Stirring
- Heating (warm water)
- Using powdered sugar (smaller particles)

#### 4. Which dissolves faster?
a. Powdered sugar
b. In hot water
c. Stirred
d. Small particles

#### 5. Concentration
- $ \frac{65}{750} = 0.0867\ \text{g/mL} $ or 8.67 g/100 mL

#### 6. More concentrated?
- 34 g in 100 mL (0.34 g/mL) is more concentrated than 100 g in 1500 mL (0.0667 g/mL)

#### 7. Is the solution saturated?
- No, because 50 g < 75 g (max at 0.5 g/mL × 150 mL)

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