Solving Exponential and Log Equations - Free Printable
Educational worksheet: Solving Exponential and Log Equations. Download and print for classroom or home learning activities.
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Step-by-step solution for: Solving Exponential and Log Equations
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Show Answer Key & Explanations
Step-by-step solution for: Solving Exponential and Log Equations
Let's solve each of the exponential and logarithmic equations step by step. We'll isolate the exponential expression, then use logarithms (natural log or common log) to solve for $ x $. All answers will be rounded to 2 decimal places.
---
Step 1: Add 49 to both sides:
$$
2^{8x - 16} = 67 + 49 = 116
$$
Step 2: Take the natural logarithm (ln) of both sides:
$$
\ln(2^{8x - 16}) = \ln(116)
$$
Step 3: Use log rule: $ \ln(a^b) = b\ln(a) $
$$
(8x - 16)\ln(2) = \ln(116)
$$
Step 4: Solve for $ x $:
$$
8x - 16 = \frac{\ln(116)}{\ln(2)} \approx \frac{5.447}{0.6931} \approx 7.86
$$
$$
8x = 7.86 + 16 = 23.86
$$
$$
x = \frac{23.86}{8} \approx 2.98
$$
✔ Answer: $ x \approx 2.98 $
---
Step 1: Add 83 to both sides:
$$
4^{3x + 21} = 85
$$
Step 2: Write 4 as $ 2^2 $, so $ 4^{3x+21} = (2^2)^{3x+21} = 2^{2(3x+21)} = 2^{6x + 42} $
Alternatively, take ln directly:
$$
\ln(4^{3x + 21}) = \ln(85)
$$
$$
(3x + 21)\ln(4) = \ln(85)
$$
Note: $ \ln(4) = \ln(2^2) = 2\ln(2) \approx 2(0.6931) = 1.3862 $
$$
3x + 21 = \frac{\ln(85)}{\ln(4)} \approx \frac{4.4427}{1.3862} \approx 3.207
$$
$$
3x = 3.207 - 21 = -17.793
$$
$$
x = \frac{-17.793}{3} \approx -5.93
$$
✔ Answer: $ x \approx -5.93 $
---
Step 1: Subtract 33:
$$
7^{5x - 65} = 87
$$
Step 2: Take ln:
$$
\ln(7^{5x - 65}) = \ln(87)
$$
$$
(5x - 65)\ln(7) = \ln(87)
$$
$ \ln(7) \approx 1.9459 $, $ \ln(87) \approx 4.4659 $
$$
5x - 65 = \frac{4.4659}{1.9459} \approx 2.30
$$
$$
5x = 2.30 + 65 = 67.30
$$
$$
x = \frac{67.30}{5} = 13.46
$$
✔ Answer: $ x \approx 13.46 $
---
Step 1: Add 47:
$$
9^{2x - 38} = 170
$$
Step 2: Take ln:
$$
\ln(9^{2x - 38}) = \ln(170)
$$
$$
(2x - 38)\ln(9) = \ln(170)
$$
$ \ln(9) = \ln(3^2) = 2\ln(3) \approx 2(1.0986) = 2.1972 $
$ \ln(170) \approx 5.1356 $
$$
2x - 38 = \frac{5.1356}{2.1972} \approx 2.337
$$
$$
2x = 2.337 + 38 = 40.337
$$
$$
x = \frac{40.337}{2} \approx 20.17
$$
✔ Answer: $ x \approx 20.17 $
---
Step 1: Subtract 46:
$$
8^{3x + 39} = 86
$$
Step 2: Take ln:
$$
\ln(8^{3x + 39}) = \ln(86)
$$
$$
(3x + 39)\ln(8) = \ln(86)
$$
$ \ln(8) = \ln(2^3) = 3\ln(2) \approx 3(0.6931) = 2.0794 $
$ \ln(86) \approx 4.4543 $
$$
3x + 39 = \frac{4.4543}{2.0794} \approx 2.142
$$
$$
3x = 2.142 - 39 = -36.858
$$
$$
x = \frac{-36.858}{3} \approx -12.29
$$
✔ Answer: $ x \approx -12.29 $
---
Step 1: Add 37:
$$
2^{-x - 14} = 24
$$
Step 2: Take ln:
$$
\ln(2^{-x - 14}) = \ln(24)
$$
$$
(-x - 14)\ln(2) = \ln(24)
$$
$ \ln(2) \approx 0.6931 $, $ \ln(24) \approx 3.1781 $
$$
-x - 14 = \frac{3.1781}{0.6931} \approx 4.585
$$
$$
-x = 4.585 + 14 = 18.585
$$
$$
x = -18.585 \approx -18.59
$$
✔ Answer: $ x \approx -18.59 $
---
Step 1: Add 12:
$$
e^{4x + 9} = 31
$$
Step 2: Take natural log (ln):
$$
\ln(e^{4x + 9}) = \ln(31)
$$
$$
4x + 9 = \ln(31) \approx 3.4339
$$
$$
4x = 3.4339 - 9 = -5.5661
$$
$$
x = \frac{-5.5661}{4} \approx -1.39
$$
✔ Answer: $ x \approx -1.39 $
---
Step 1: Subtract 56:
$$
e^{x - 15} = 32
$$
Step 2: Take ln:
$$
\ln(e^{x - 15}) = \ln(32)
$$
$$
x - 15 = \ln(32) \approx 3.4657
$$
$$
x = 3.4657 + 15 = 18.4657 \approx 18.47
$$
✔ Answer: $ x \approx 18.47 $
---
Step 1: Add 21:
$$
2e^{3x - 11} = 58
$$
Step 2: Divide by 2:
$$
e^{3x - 11} = 29
$$
Step 3: Take ln:
$$
\ln(e^{3x - 11}) = \ln(29)
$$
$$
3x - 11 = \ln(29) \approx 3.3673
$$
$$
3x = 3.3673 + 11 = 14.3673
$$
$$
x = \frac{14.3673}{3} \approx 4.79
$$
✔ Answer: $ x \approx 4.79 $
---
Step 1: Add 34:
$$
3e^{6x - 54} = 117
$$
Step 2: Divide by 3:
$$
e^{6x - 54} = 39
$$
Step 3: Take ln:
$$
\ln(e^{6x - 54}) = \ln(39)
$$
$$
6x - 54 = \ln(39) \approx 3.6636
$$
$$
6x = 3.6636 + 54 = 57.6636
$$
$$
x = \frac{57.6636}{6} \approx 9.61
$$
✔ Answer: $ x \approx 9.61 $
---
1. $ x \approx 2.98 $
2. $ x \approx -5.93 $
3. $ x \approx 13.46 $
4. $ x \approx 20.17 $
5. $ x \approx -12.29 $
6. $ x \approx -18.59 $
7. $ x \approx -1.39 $
8. $ x \approx 18.47 $
9. $ x \approx 4.79 $
10. $ x \approx 9.61 $
Let me know if you'd like a summary table or visual steps!
---
1. $ 2^{8x - 16} - 49 = 67 $
Step 1: Add 49 to both sides:
$$
2^{8x - 16} = 67 + 49 = 116
$$
Step 2: Take the natural logarithm (ln) of both sides:
$$
\ln(2^{8x - 16}) = \ln(116)
$$
Step 3: Use log rule: $ \ln(a^b) = b\ln(a) $
$$
(8x - 16)\ln(2) = \ln(116)
$$
Step 4: Solve for $ x $:
$$
8x - 16 = \frac{\ln(116)}{\ln(2)} \approx \frac{5.447}{0.6931} \approx 7.86
$$
$$
8x = 7.86 + 16 = 23.86
$$
$$
x = \frac{23.86}{8} \approx 2.98
$$
✔ Answer: $ x \approx 2.98 $
---
2. $ 4^{3x + 21} - 83 = 2 $
Step 1: Add 83 to both sides:
$$
4^{3x + 21} = 85
$$
Step 2: Write 4 as $ 2^2 $, so $ 4^{3x+21} = (2^2)^{3x+21} = 2^{2(3x+21)} = 2^{6x + 42} $
Alternatively, take ln directly:
$$
\ln(4^{3x + 21}) = \ln(85)
$$
$$
(3x + 21)\ln(4) = \ln(85)
$$
Note: $ \ln(4) = \ln(2^2) = 2\ln(2) \approx 2(0.6931) = 1.3862 $
$$
3x + 21 = \frac{\ln(85)}{\ln(4)} \approx \frac{4.4427}{1.3862} \approx 3.207
$$
$$
3x = 3.207 - 21 = -17.793
$$
$$
x = \frac{-17.793}{3} \approx -5.93
$$
✔ Answer: $ x \approx -5.93 $
---
3. $ 7^{5x - 65} + 33 = 120 $
Step 1: Subtract 33:
$$
7^{5x - 65} = 87
$$
Step 2: Take ln:
$$
\ln(7^{5x - 65}) = \ln(87)
$$
$$
(5x - 65)\ln(7) = \ln(87)
$$
$ \ln(7) \approx 1.9459 $, $ \ln(87) \approx 4.4659 $
$$
5x - 65 = \frac{4.4659}{1.9459} \approx 2.30
$$
$$
5x = 2.30 + 65 = 67.30
$$
$$
x = \frac{67.30}{5} = 13.46
$$
✔ Answer: $ x \approx 13.46 $
---
4. $ 9^{2x - 38} - 47 = 123 $
Step 1: Add 47:
$$
9^{2x - 38} = 170
$$
Step 2: Take ln:
$$
\ln(9^{2x - 38}) = \ln(170)
$$
$$
(2x - 38)\ln(9) = \ln(170)
$$
$ \ln(9) = \ln(3^2) = 2\ln(3) \approx 2(1.0986) = 2.1972 $
$ \ln(170) \approx 5.1356 $
$$
2x - 38 = \frac{5.1356}{2.1972} \approx 2.337
$$
$$
2x = 2.337 + 38 = 40.337
$$
$$
x = \frac{40.337}{2} \approx 20.17
$$
✔ Answer: $ x \approx 20.17 $
---
5. $ 8^{3x + 39} + 46 = 132 $
Step 1: Subtract 46:
$$
8^{3x + 39} = 86
$$
Step 2: Take ln:
$$
\ln(8^{3x + 39}) = \ln(86)
$$
$$
(3x + 39)\ln(8) = \ln(86)
$$
$ \ln(8) = \ln(2^3) = 3\ln(2) \approx 3(0.6931) = 2.0794 $
$ \ln(86) \approx 4.4543 $
$$
3x + 39 = \frac{4.4543}{2.0794} \approx 2.142
$$
$$
3x = 2.142 - 39 = -36.858
$$
$$
x = \frac{-36.858}{3} \approx -12.29
$$
✔ Answer: $ x \approx -12.29 $
---
6. $ 2^{-x - 14} - 37 = -13 $
Step 1: Add 37:
$$
2^{-x - 14} = 24
$$
Step 2: Take ln:
$$
\ln(2^{-x - 14}) = \ln(24)
$$
$$
(-x - 14)\ln(2) = \ln(24)
$$
$ \ln(2) \approx 0.6931 $, $ \ln(24) \approx 3.1781 $
$$
-x - 14 = \frac{3.1781}{0.6931} \approx 4.585
$$
$$
-x = 4.585 + 14 = 18.585
$$
$$
x = -18.585 \approx -18.59
$$
✔ Answer: $ x \approx -18.59 $
---
7. $ e^{4x + 9} - 12 = 19 $
Step 1: Add 12:
$$
e^{4x + 9} = 31
$$
Step 2: Take natural log (ln):
$$
\ln(e^{4x + 9}) = \ln(31)
$$
$$
4x + 9 = \ln(31) \approx 3.4339
$$
$$
4x = 3.4339 - 9 = -5.5661
$$
$$
x = \frac{-5.5661}{4} \approx -1.39
$$
✔ Answer: $ x \approx -1.39 $
---
8. $ e^{x - 15} + 56 = 88 $
Step 1: Subtract 56:
$$
e^{x - 15} = 32
$$
Step 2: Take ln:
$$
\ln(e^{x - 15}) = \ln(32)
$$
$$
x - 15 = \ln(32) \approx 3.4657
$$
$$
x = 3.4657 + 15 = 18.4657 \approx 18.47
$$
✔ Answer: $ x \approx 18.47 $
---
9. $ 2e^{3x - 11} - 21 = 37 $
Step 1: Add 21:
$$
2e^{3x - 11} = 58
$$
Step 2: Divide by 2:
$$
e^{3x - 11} = 29
$$
Step 3: Take ln:
$$
\ln(e^{3x - 11}) = \ln(29)
$$
$$
3x - 11 = \ln(29) \approx 3.3673
$$
$$
3x = 3.3673 + 11 = 14.3673
$$
$$
x = \frac{14.3673}{3} \approx 4.79
$$
✔ Answer: $ x \approx 4.79 $
---
10. $ 3e^{6x - 54} - 34 = 83 $
Step 1: Add 34:
$$
3e^{6x - 54} = 117
$$
Step 2: Divide by 3:
$$
e^{6x - 54} = 39
$$
Step 3: Take ln:
$$
\ln(e^{6x - 54}) = \ln(39)
$$
$$
6x - 54 = \ln(39) \approx 3.6636
$$
$$
6x = 3.6636 + 54 = 57.6636
$$
$$
x = \frac{57.6636}{6} \approx 9.61
$$
✔ Answer: $ x \approx 9.61 $
---
✔ Final Answers (Rounded to 2 Decimal Places):
1. $ x \approx 2.98 $
2. $ x \approx -5.93 $
3. $ x \approx 13.46 $
4. $ x \approx 20.17 $
5. $ x \approx -12.29 $
6. $ x \approx -18.59 $
7. $ x \approx -1.39 $
8. $ x \approx 18.47 $
9. $ x \approx 4.79 $
10. $ x \approx 9.61 $
Let me know if you'd like a summary table or visual steps!
Parent Tip: Review the logic above to help your child master the concept of solving exponential and logarithmic functions worksheet answers.