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Solving Systems of Equations by Substitution Worksheets - Math Monks - Free Printable

Solving Systems of Equations by Substitution Worksheets - Math Monks

Educational worksheet: Solving Systems of Equations by Substitution Worksheets - Math Monks. Download and print for classroom or home learning activities.

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Let’s solve each system of equations step by step using substitution. We’ll go one problem at a time.

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Problem 1:

x = -y
3x + 4y = -8

Since x is already solved for (x = -y), we can plug that into the second equation:

3(-y) + 4y = -8
→ -3y + 4y = -8
→ y = -8

Now plug y = -8 back into x = -y:
x = -(-8) = 8

Solution: x = 8, y = -8

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Problem 2:

y = -3x + 4
y = -5x - 17

Both equations are solved for y, so set them equal to each other:

-3x + 4 = -5x - 17

Add 5x to both sides:
2x + 4 = -17

Subtract 4 from both sides:
2x = -21

Divide by 2:
x = -10.5 or -21/2

Now plug into either equation to find y. Use first one:
y = -3(-21/2) + 4 = 63/2 + 8/2 = 71/2 = 35.5

Solution: x = -21/2, y = 71/2 (or x = -10.5, y = 35.5)

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Problem 3:

y = -x - 6
y = x - 4

Set them equal:
-x - 6 = x - 4

Add x to both sides:
-6 = 2x - 4

Add 4 to both sides:
-2 = 2x → x = -1

Plug into y = x - 4:
y = -1 - 4 = -5

Solution: x = -1, y = -5

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Problem 4:

2x - 3y = 1
-6x + 9y = -3

Notice: If you multiply the first equation by -3, you get the second equation:

-3*(2x - 3y) = -3*1 → -6x + 9y = -3 → same as second equation!

That means these two equations are actually the same line — infinitely many solutions.

But let’s try solving anyway. Solve first equation for x:

2x = 3y + 1 → x = (3y + 1)/2

Plug into second equation:

-6*((3y+1)/2) + 9y = -3
→ -3*(3y+1) + 9y = -3
→ -9y -3 + 9y = -3
→ -3 = -3 → always true!

So yes — infinite solutions. Any point on the line works.

Solution: Infinitely many solutions (dependent system)

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Problem 5:

7x + 2y = -19
-x + 2y = 21

Solve second equation for x:
-x = 21 - 2y → x = 2y - 21

Plug into first equation:

7(2y - 21) + 2y = -19
→ 14y - 147 + 2y = -19
→ 16y = 128
→ y = 8

Now x = 2(8) - 21 = 16 - 21 = -5

Solution: x = -5, y = 8

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Problem 6:

x = y - 4
-2x + 3y = 6

Plug x = y - 4 into second equation:

-2(y - 4) + 3y = 6
→ -2y + 8 + 3y = 6
→ y + 8 = 6
→ y = -2

Then x = (-2) - 4 = -6

Solution: x = -6, y = -2

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Problem 7:

2y = 2x + 12
y = -2 - 3 → wait, this says y = -5? Let me check.

Actually, looking again: “y = -2 - 3” → that’s just y = -5. Probably a typo in the worksheet? But we’ll take it as written.

So y = -5

Plug into first equation:
2*(-5) = 2x + 12
→ -10 = 2x + 12
→ 2x = -22
→ x = -11

Solution: x = -11, y = -5

*(Note: The second equation seems oddly written — maybe meant to be y = -2x - 3? But as written, it’s y = -5.)*

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Problem 8:

x - 3y = 0 → x = 3y
4x + 8y = 5

Plug x = 3y into second equation:

4*(3y) + 8y = 5
→ 12y + 8y = 5
→ 20y = 5
→ y = 5/20 = 1/4

Then x = 3*(1/4) = 3/4

Solution: x = 3/4, y = 1/4

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Final Answer:

1. x = 8, y = -8
2. x = -21/2, y = 71/2
3. x = -1, y = -5
4. Infinitely many solutions
5. x = -5, y = 8
6. x = -6, y = -2
7. x = -11, y = -5
8. x = 3/4, y = 1/4
Parent Tip: Review the logic above to help your child master the concept of solving systems of linear equations by substitution worksheet.
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