Worksheet titled "Specific Heat and Heat Capacity Worksheet" with instructions to use the formula q = (m)(Cp)(ΔT) to solve problems, including examples and exercises involving temperature changes in water and metals.

Specific Heat and Heat Capacity Worksheet with problems and directions for calculating heat using the formula q = (m)(Cp)(ΔT), featuring an example and five practice questions involving water and metal samples.

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1. q = (335 g)(4.18 J/g°C)(26.4°C - 24.5°C) = (335)(4.18)(1.9) = 2660.57 J ≈ 2660 J

2. q = (225 g)(4.18 J/g°C)(10.0°C - 25.0°C) = (225)(4.18)(-15.0) = -14107.5 J; Heat removed = 14107.5 J = 14.1 kJ

3. q = (1000 g)(4.18 J/g°C)(99°C - 25°C) = (1000)(4.18)(74) = 309320 J = 309 kJ

4. Heat gained by water = (75.0 g)(4.18 J/g°C)(28.34°C - 24.00°C) = (75.0)(4.18)(4.34) = 1359.51 J
Heat lost by metal = (26.00 g)(Cp)(28.34°C - 82.25°C) = (26.00)(Cp)(-53.91)
Set heat lost = heat gained: (26.00)(Cp)(-53.91) = -1359.51 → Cp = 1359.51 / (26.00 * 53.91) = 0.977 J/g°C

5. q = (1265 J/°C)(25.12°C - 22.34°C) = (1265)(2.78) = 3516.7 J ≈ 3520 J

Parent Tip: Review the logic above to help your child master the concept of specific heat capacity worksheet.

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