Speed, Velocity, and Acceleration - Worksheet | Distance Learning ... - Free Printable

Let's solve each part of the problem step by step.

---

Q.3: True or False Statements

1. The units for both speed and velocity are metres per second (m/s).
✔ True (T)
→ Both speed and velocity have the same unit: m/s.
- Speed is scalar, velocity is vector — but their units are identical.

2. Speed and velocity do not mean the same thing.
✔ True (T)
→ Speed is a scalar (only magnitude), velocity is a vector (magnitude + direction).
So they are not the same.

3. If the object moves with a high speed then its acceleration is also high.
✘ False (F)
→ Acceleration depends on the change in velocity, not just speed.
An object can move at high constant speed with zero acceleration.

4. If the object moves with a low velocity then the acceleration is also low.
✘ False (F)
→ Low velocity does not imply low acceleration.
Example: A car starting from rest (low velocity) can have high acceleration.

5. If an object is moving with a constant velocity, then it has zero acceleration.
✔ True (T)
→ Constant velocity means no change in speed or direction → acceleration = 0.

---

✔ Answers for Q.3:

1. T
2. T
3. F
4. F
5. T

---

Q.4: Student Traveling from Home to School to Market

From the diagram:

- Home is at 0 m
- Market is at 200 m
- School is at 500 m
- Then student goes from School (500 m) to Market (200 m)

So path is:
Home (0 m) → School (500 m) → Market (200 m)

---

#### Q.4.I. What distance did the student travel?

Distance = total path length traveled (scalar)

- Home to School: 500 m
- School to Market: |500 – 200| = 300 m
→ Total distance = 500 + 300 = 800 m

✔ Answer: d) 800 m

---

#### Q.4.II. What is the displacement of the student?

Displacement = final position – initial position (vector)

- Initial position: Home = 0 m
- Final position: Market = 200 m
- Displacement = 200 m – 0 m = 200 m East

✔ Answer: a) 200 m, East

---

#### Q.4.III. If the student travels for 100 seconds, what is the speed of the student?

Speed = total distance / time
= 800 m / 100 s = 8 m/s

✔ Answer: b) 8 m/s

---

#### Q.4.IV. If the student travels for 100 seconds, what is the velocity of the student?

Velocity = displacement / time
= 200 m East / 100 s = 2 m/s East

✔ Answer: b) 2 m/s, East

---

✔ Final Answers:

Q.3:
1. T
2. T
3. F
4. F
5. T

Q.4:
- Q.4.I → d) 800 m
- Q.4.II → a) 200 m, East
- Q.4.III → b) 8 m/s
- Q.4.IV → b) 2 m/s, East

---

Let me know if you'd like a diagram explanation or further clarification!