Volume to Volume Stoichiometry Worksheet Walkthrough - Free Printable

Let's solve the volume-volume stoichiometry problems step by step, based on the balanced chemical equations and the assumption that temperature and pressure are constant, so we can use volume ratios directly (since volume is proportional to moles for gases under constant T and P).

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Problem 1:

Reaction:
$$
\mathrm{N_2 + 3H_2 \rightarrow 2NH_3}
$$

Question: What volume of hydrogen is necessary to react with five liters of nitrogen to produce ammonia?

#### Step-by-step:

From the balanced equation:
- 1 mole of $ \mathrm{N_2} $ reacts with 3 moles of $ \mathrm{H_2} $
- Since volume ratios = mole ratios at constant T and P:
- 1 L of $ \mathrm{N_2} $ requires 3 L of $ \mathrm{H_2} $

Given: 5 L of $ \mathrm{N_2} $

So:
$$
\text{Volume of } \mathrm{H_2} = 5 \, \text{L } \mathrm{N_2} \times \frac{3 \, \text{L } \mathrm{H_2}}{1 \, \text{L } \mathrm{N_2}} = 15 \, \text{L } \mathrm{H_2}
$$

✔ Answer to Problem 1: 15 liters of hydrogen

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Problem 2:

What volume of ammonia is produced in the reaction in Problem 1?

From the same reaction:
$$
\mathrm{N_2 + 3H_2 \rightarrow 2NH_3}
$$

- 1 mole $ \mathrm{N_2} $ produces 2 moles $ \mathrm{NH_3} $
- So, 1 L $ \mathrm{N_2} $ produces 2 L $ \mathrm{NH_3} $

We have 5 L of $ \mathrm{N_2} $:

$$
\text{Volume of } \mathrm{NH_3} = 5 \, \text{L } \mathrm{N_2} \times \frac{2 \, \text{L } \mathrm{NH_3}}{1 \, \text{L } \mathrm{N_2}} = 10 \, \text{L } \mathrm{NH_3}
$$

✔ Answer to Problem 2: 10 liters of ammonia

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Problem 3:

Reaction:
$$
\mathrm{C_3H_8 + 5O_2 \rightarrow 3CO_2 + 4H_2O}
$$

Given: 20 liters of oxygen ($ \mathrm{O_2} $) are consumed.

Question: How many liters of carbon dioxide ($ \mathrm{CO_2} $) are produced?

From the balanced equation:
- 5 moles $ \mathrm{O_2} $ produce 3 moles $ \mathrm{CO_2} $
- So, 5 L $ \mathrm{O_2} $ → 3 L $ \mathrm{CO_2} $

Set up proportion:
$$
\text{Volume of } \mathrm{CO_2} = 20 \, \text{L } \mathrm{O_2} \times \frac{3 \, \text{L } \mathrm{CO_2}}{5 \, \text{L } \mathrm{O_2}} = 12 \, \text{L } \mathrm{CO_2}
$$

✔ Answer to Problem 3: 12 liters of carbon dioxide

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✔ Final Answers:

1. 15 liters of hydrogen
2. 10 liters of ammonia
3. 12 liters of carbon dioxide

Let me know if you'd like these explained further or need help with more problems!