- Calculate the moles of H2SO4: 500.0 g / 98.08 g/mol = 5.098 mol.
- From the balanced equation, 1 mol H2SO4 reacts with 2 mol NaOH.
- Moles of NaOH needed = 2 × 5.098 mol = 10.196 mol ≈ 10.19 mol.
- Calculate the moles of NCl3: 125 g / 120.36 g/mol = 1.0385 mol.
- From the balanced equation, 1 mol NCl3 produces 1 mol NH3.
- Moles of NH3 produced = 1.0385 mol.
- Mass of NH3 = 1.0385 mol × 17.03 g/mol = 17.68 g ≈ 17.7 g.
- Calculate moles of C3H8: 25.0 g / 44.10 g/mol = 0.5669 mol.
- Calculate moles of O2: 75.0 g / 32.00 g/mol = 2.3438 mol.
- From the equation, 1 mol C3H8 requires 5 mol O2 → 0.5669 mol C3H8 requires 2.8345 mol O2.
- Since only 2.3438 mol O2 is available, O2 is limiting.
- From the equation, 5 mol O2 produce 3 mol CO2 → 2.3438 mol O2 produce (3/5) × 2.3438 = 1.4063 mol CO2.
- Mass of CO2 = 1.4063 mol × 44.01 g/mol = 61.89 g ≈ 61.9 g.
- Calculate moles of CS2: 152 g / 76.14 g/mol = 1.9963 mol.
- Calculate moles of O2: 48.0 g / 32.00 g/mol = 1.5000 mol.
- From the equation, 1 mol CS2 requires 3 mol O2 → 1.9963 mol CS2 requires 5.9889 mol O2.
- Since only 1.5000 mol O2 is available, O2 is limiting.
- From the equation, 3 mol O2 produce 2 mol SO2 → 1.5000 mol O2 produce (2/3) × 1.5000 = 1.0000 mol SO2.
- Mass of SO2 = 1.0000 mol × 64.07 g/mol = 64.07 g ≈ 64.1 g.
Parent Tip: Review the logic above to help your child master the concept of stoichiometry worksheet 4.
