Subtraction with Regrouping free online activity - Free Printable

The task involves solving subtraction problems using the "tens and ones" method. Each problem is broken down into tens and ones, and we need to subtract accordingly. Let's solve each problem step by step.

Problem 1: \(71 - 39\)

- Tens: \(7 - 3 = 4\)
- Ones: \(1 - 9\) (since 1 is less than 9, we borrow 1 from the tens place)
- After borrowing, \(11 - 9 = 2\)
- The tens place becomes \(6 - 3 = 3\)
- Result: \(32\)

Problem 2: \(61 - 46\)

- Tens: \(6 - 4 = 2\)
- Ones: \(1 - 6\) (since 1 is less than 6, we borrow 1 from the tens place)
- After borrowing, \(11 - 6 = 5\)
- The tens place becomes \(5 - 4 = 1\)
- Result: \(15\)

Problem 3: \(31 - 18\)

- Tens: \(3 - 1 = 2\)
- Ones: \(1 - 8\) (since 1 is less than 8, we borrow 1 from the tens place)
- After borrowing, \(11 - 8 = 3\)
- The tens place becomes \(2 - 1 = 2\)
- Result: \(13\)

Problem 4: \(51 - 23\)

- Tens: \(5 - 2 = 3\)
- Ones: \(1 - 3\) (since 1 is less than 3, we borrow 1 from the tens place)
- After borrowing, \(11 - 3 = 8\)
- The tens place becomes \(4 - 2 = 2\)
- Result: \(28\)

Problem 5: \(91 - 64\)

- Tens: \(9 - 6 = 3\)
- Ones: \(1 - 4\) (since 1 is less than 4, we borrow 1 from the tens place)
- After borrowing, \(11 - 4 = 7\)
- The tens place becomes \(8 - 6 = 2\)
- Result: \(27\)

Problem 6: \(81 - 32\)

- Tens: \(8 - 3 = 5\)
- Ones: \(1 - 2\) (since 1 is less than 2, we borrow 1 from the tens place)
- After borrowing, \(11 - 2 = 9\)
- The tens place becomes \(7 - 3 = 4\)
- Result: \(49\)

Problem 7: \(41 - 25\)

- Tens: \(4 - 2 = 2\)
- Ones: \(1 - 5\) (since 1 is less than 5, we borrow 1 from the tens place)
- After borrowing, \(11 - 5 = 6\)
- The tens place becomes \(3 - 2 = 1\)
- Result: \(16\)

Problem 8: \(81 - 49\)

- Tens: \(8 - 4 = 4\)
- Ones: \(1 - 9\) (since 1 is less than 9, we borrow 1 from the tens place)
- After borrowing, \(11 - 9 = 2\)
- The tens place becomes \(7 - 4 = 3\)
- Result: \(32\)

Problem 9: \(91 - 47\)

- Tens: \(9 - 4 = 5\)
- Ones: \(1 - 7\) (since 1 is less than 7, we borrow 1 from the tens place)
- After borrowing, \(11 - 7 = 4\)
- The tens place becomes \(8 - 4 = 4\)
- Result: \(44\)

Final Answers:

\[
\boxed{
\begin{array}{ccc}
32 & 15 & 13 \\
28 & 27 & 49 \\
16 & 32 & 44 \\
\end{array}
}
\]