Addition and subtraction practice worksheet for three-digit numbers without regrouping.

Let’s solve each problem one by one. Remember: no regrouping means we just add or subtract digit by digit from right to left, and we don’t need to borrow or carry over.

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Problem 1: 330 + 623

- Ones: 0 + 3 = 3
- Tens: 3 + 2 = 5
- Hundreds: 3 + 6 = 9
→ 953

Problem 2: 126 + 243

- Ones: 6 + 3 = 9
- Tens: 2 + 4 = 6
- Hundreds: 1 + 2 = 3
→ 369

Problem 3: 373 - 111

- Ones: 3 - 1 = 2
- Tens: 7 - 1 = 6
- Hundreds: 3 - 1 = 2
→ 262

Problem 4: 662 - 331

- Ones: 2 - 1 = 1
- Tens: 6 - 3 = 3
- Hundreds: 6 - 3 = 3
→ 331

Problem 5: 359 - 210

- Ones: 9 - 0 = 9
- Tens: 5 - 1 = 4
- Hundreds: 3 - 2 = 1
→ 149

Problem 6: 412 - 321

- Ones: 2 - 1 = 1
- Tens: 1 - 2 → Wait! Can’t do that without borrowing? But the worksheet says “No Regrouping” — so maybe this is a trick? Let’s check digits again.

Actually, looking at the numbers: 412 - 321

Ones: 2 - 1 = 1 ✔
Tens: 1 - 2 → Not possible without borrowing ✘
But since it’s labeled “No Regrouping”, perhaps there’s an error? Or maybe I misread?

Wait — let me double-check the original image description. The user said “Addition & Subtraction with No Regrouping”. So all problems should be solvable without borrowing or carrying.

Looking at Problem 6: 412 - 321

Tens place: 1 < 2 → needs borrowing → contradicts “no regrouping”

Hmm… but maybe in some curricula, they still call it “no regrouping” if you can do it mentally? Or perhaps it's a mistake?

Wait — let’s look at other problems. Maybe I made a mistake.

Actually, let’s proceed assuming all are designed for no regrouping — meaning every digit in top number is ≥ bottom digit in subtraction.

Check Problem 6 again: 412 - 321

Hundreds: 4 ≥ 3 ✔
Tens: 1 < 2 ✘ → This requires borrowing.

This suggests either:
- There’s a typo in the worksheet
- Or “no regrouping” here means something else?

But let’s check Problem 11: 634 - 235 → ones: 4 < 5 → also needs borrowing.

Wait — this is confusing. Maybe the title is misleading? Or perhaps “no regrouping” refers to not having to carry/borrow across multiple places? But that doesn’t make sense.

Alternatively — maybe the student is expected to recognize which problems actually require regrouping and skip them? But that seems unlikely.

Wait — let’s re-read the instruction: “Addition & Subtraction with No Regrouping” — implying ALL problems on this sheet are meant to be done without regrouping.

So perhaps I misread the numbers?

Let me go back to Problem 6: 412 - 321

If we do it anyway (even though it requires borrowing), answer is 91.

But since the sheet says “no regrouping”, maybe it’s intended that students only do problems where no borrowing is needed — but then why include these?

Alternatively — perhaps “no regrouping” means you don’t have to write down the borrowing/carrying steps — you just compute directly? That might be it.

In many elementary worksheets, “no regrouping” means the digits are arranged so that you don’t NEED to borrow or carry — i.e., for subtraction, each digit in minuend ≥ subtrahend; for addition, each column sum < 10.

Let’s test that theory.

For addition: max per column should be ≤ 9.

Problem 1: 330 + 623 → ones: 0+3=3, tens:3+2=5, hundreds:3+6=9 → all good.

Problem 2: 126+243 → 6+3=9, 2+4=6, 1+2=3 → good.

Problem 7: 666 + 333 → 6+3=9, 6+3=9, 6+3=9 → good.

Problem 8: 340 - 222 → 0<2 → needs borrowing → bad.

Wait — Problem 8: 340 - 222

Ones: 0 - 2 → can't do without borrowing.

This is inconsistent.

Perhaps the title is wrong? Or perhaps “no regrouping” is a misnomer?

Another idea: maybe “no regrouping” means you’re not supposed to use the standard algorithm with carrying/borrowing — but instead use mental math or decompose? But that seems advanced.

Given the context, and since this is likely for young students, I think the most reasonable approach is to assume that despite the title, some problems may require regrouping, but we’ll solve them as normal arithmetic.

Alternatively — let’s look at the actual values and see if any clearly violate “no regrouping”.

Let’s list all subtraction problems and check if any digit in top is less than bottom:

Prob 3: 373 - 111 → 3≥1, 7≥1, 3≥1 → OK
Prob 4: 662 - 331 → 2≥1, 6≥3, 6≥3 → OK
Prob 5: 359 - 210 → 9≥0, 5≥1, 3≥2 → OK
Prob 6: 412 - 321 → 2≥1, 1<2 → NOT OK
Prob 8: 340 - 222 → 0<2 → NOT OK
Prob 9: 106 + 442 → addition, 6+2=8, 0+4=4, 1+4=5 → OK
Prob 10: 717 - 213 → 7≥3, 1≥1, 7≥2 → OK
Prob 11: 634 - 235 → 4<5 → NOT OK
Prob 13: 500 - 200 → 0≥0, 0≥0, 5≥2 → OK
Prob 14: 510 - 320 → 0≥0, 1<2 → NOT OK
Prob 15: 712 + 223 → 2+3=5, 1+2=3, 7+2=9 → OK
Prob 18: 703 - 202 → 3≥2, 0≥0, 7≥2 → OK
Prob 21: 627 - 251 → 7≥1, 2<5 → NOT OK
Prob 22: 852 - 122 → 2≥2, 5≥2, 8≥1 → OK
Prob 23: 162 - 104 → 2<4 → NOT OK
Prob 24: 234 + 523 → 4+3=7, 3+2=5, 2+5=7 → OK
Prob 25: 555 - 333 → 5≥3, 5≥3, 5≥3 → OK

So several subtraction problems require borrowing. This suggests that either:
- The title is incorrect
- Or “no regrouping” means something else in this context

Given that this is a common type of worksheet, and often “no regrouping” is used loosely, I will proceed to solve all problems using standard arithmetic, ignoring the “no regrouping” label for now, because otherwise many problems are unsolvable as stated.

Perhaps the intention is that students practice basic operations without worrying about the regrouping concept yet — but still perform the calculations correctly.

I think that’s the best approach.

So let’s solve all 25 problems accurately.

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Problem 1: 330 + 623 = 953
Problem 2: 126 + 243 = 369
Problem 3: 373 - 111 = 262
Problem 4: 662 - 331 = 331
Problem 5: 359 - 210 = 149
Problem 6: 412 - 321 = 91 (since 412 - 300 = 112, then 112 - 21 = 91)
Problem 7: 666 + 333 = 999
Problem 8: 340 - 222 = 118 (340 - 200 = 140, 140 - 22 = 118)
Problem 9: 106 + 442 = 548
Problem 10: 717 - 213 = 504
Problem 11: 634 - 235 = 399 (634 - 200 = 434, 434 - 35 = 399)
Problem 12: 334 + 100 = 434
Problem 13: 500 - 200 = 300
Problem 14: 510 - 320 = 190
Problem 15: 712 + 223 = 935
Problem 16: 322 + 571 = 893
Problem 17: 259 + 340 = 599
Problem 18: 703 - 202 = 501
Problem 19: 227 + 141 = 368
Problem 20: 354 + 122 = 476
Problem 21: 627 - 251 = 376
Problem 22: 852 - 122 = 730
Problem 23: 162 - 104 = 58
Problem 24: 234 + 523 = 757
Problem 25: 555 - 333 = 222

Now, let me verify a few that were tricky:

Problem 6: 412 - 321
412
-321
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Start from right: 2-1=1
Middle: 1-2 → can't, so borrow: 11-2=9, but then hundreds become 3 (since 4-1=3), then 3-3=0 → so 091 → 91. Correct.

Problem 8: 340 - 222
340
-222
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0-2 → borrow: 10-2=8, tens become 3 (4-1=3), 3-2=1, hundreds 3-2=1 → 118. Correct.

Problem 11: 634 - 235
634
-235
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4-5 → borrow: 14-5=9, tens become 2 (3-1=2), 2-3 → borrow: 12-3=9, hundreds become 5 (6-1=5), 5-2=3 → 399. Correct.

Problem 14: 510 - 320
510
-320
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0-0=0, 1-2 → borrow: 11-2=9, hundreds 4 (5-1=4), 4-3=1 → 190. Correct.

Problem 21: 627 - 251
627
-251
----
7-1=6, 2-5 → borrow: 12-5=7, hundreds 5 (6-1=5), 5-2=3 → 376. Correct.

Problem 23: 162 - 104
162
-104
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2-4 → borrow: 12-4=8, tens 5 (6-1=5), 5-0=5, hundreds 1-1=0 → 58. Correct.

All seem correct.

Final Answer:
1. 953
2. 369
3. 262
4. 331
5. 149
6. 91
7. 999
8. 118
9. 548
10. 504
11. 399
12. 434
13. 300
14. 190
15. 935
16. 893
17. 599
18. 501
19. 368
20. 476
21. 376
22. 730
23. 58
24. 757
25. 222