4-Digit Subtraction Challenges 2: Solve the missing digits in these 4-digit subtraction problems.
4-digit subtraction challenges worksheet with missing digits to solve, featuring 15 subtraction problems for educational practice.
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Show Answer Key & Explanations
Step-by-step solution for: 4 Digit Subtraction Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: 4 Digit Subtraction Worksheets
To solve the missing digits in these 4-digit subtraction problems, we need to carefully analyze each problem step by step. Let's go through each one:
---
\[
\begin{array}{r}
\_819 \\
-15\_6 \\
\hline
44\_ \\
\end{array}
\]
1. Units place: \(9 - 6 = 3\). So, the units digit of the result is 3.
2. Tens place: The result has a 4 in the tens place. Since we borrowed from the hundreds place, the subtraction in the tens place is \(11 - 5 = 6\). So, the missing digit in the minuend is 6.
3. Hundreds place: The result has an 8 in the hundreds place. Since we borrowed from the thousands place, the subtraction in the hundreds place is \(7 - 1 = 6\). So, the missing digit in the minuend is 7.
4. Thousands place: The result has a 4 in the thousands place. Since we borrowed from the thousands place, the subtraction in the thousands place is \(5 - 1 = 4\). So, the missing digit in the minuend is 5.
Thus, the complete subtraction is:
\[
\begin{array}{r}
5819 \\
-1566 \\
\hline
4253 \\
\end{array}
\]
---
\[
\begin{array}{r}
72\_ \\
-263 \\
\hline
\_375 \\
\end{array}
\]
1. Units place: \( \_ - 3 = 5 \). So, the missing digit in the minuend is 8.
2. Tens place: The result has a 7 in the tens place. Since we borrowed from the hundreds place, the subtraction in the tens place is \(12 - 6 = 6\). So, the missing digit in the minuend is 9.
3. Hundreds place: The result has a 3 in the hundreds place. Since we borrowed from the thousands place, the subtraction in the hundreds place is \(6 - 2 = 4\). So, the missing digit in the minuend is 4.
4. Thousands place: The result has a 4 in the thousands place. So, the missing digit in the minuend is 4.
Thus, the complete subtraction is:
\[
\begin{array}{r}
7298 \\
-263 \\
\hline
7035 \\
\end{array}
\]
---
\[
\begin{array}{r}
\_76\_ \\
-351 \\
\hline
134 \\
\end{array}
\]
1. Units place: \( \_ - 1 = 4 \). So, the missing digit in the minuend is 5.
2. Tens place: The result has a 3 in the tens place. Since we borrowed from the hundreds place, the subtraction in the tens place is \(16 - 5 = 11\). So, the missing digit in the minuend is 6.
3. Hundreds place: The result has a 7 in the hundreds place. Since we borrowed from the thousands place, the subtraction in the hundreds place is \(6 - 3 = 3\). So, the missing digit in the minuend is 4.
4. Thousands place: The result has a 1 in the thousands place. So, the missing digit in the minuend is 1.
Thus, the complete subtraction is:
\[
\begin{array}{r}
1765 \\
-351 \\
\hline
1414 \\
\end{array}
\]
---
\[
\begin{array}{r}
63\_2 \\
-358 \\
\hline
\_91\_ \\
\end{array}
\]
1. Units place: \(2 - 8\) requires borrowing, so \(12 - 8 = 4\). So, the missing digit in the result is 4.
2. Tens place: The result has a 1 in the tens place. Since we borrowed from the hundreds place, the subtraction in the tens place is \(2 - 5 = 7\). So, the missing digit in the minuend is 7.
3. Hundreds place: The result has a 9 in the hundreds place. Since we borrowed from the thousands place, the subtraction in the hundreds place is \(5 - 3 = 2\). So, the missing digit in the minuend is 2.
4. Thousands place: The result has a 2 in the thousands place. So, the missing digit in the minuend is 2.
Thus, the complete subtraction is:
\[
\begin{array}{r}
6372 \\
-358 \\
\hline
5914 \\
\end{array}
\]
---
\[
\begin{array}{r}
\_3\_1 \\
-243 \\
\hline
641 \\
\end{array}
\]
1. Units place: \(1 - 3\) requires borrowing, so \(11 - 3 = 8\). So, the missing digit in the minuend is 8.
2. Tens place: The result has a 4 in the tens place. Since we borrowed from the hundreds place, the subtraction in the tens place is \(2 - 4 = 8\). So, the missing digit in the minuend is 8.
3. Hundreds place: The result has a 3 in the hundreds place. Since we borrowed from the thousands place, the subtraction in the hundreds place is \(3 - 2 = 1\). So, the missing digit in the minuend is 1.
4. Thousands place: The result has a 1 in the thousands place. So, the missing digit in the minuend is 1.
Thus, the complete subtraction is:
\[
\begin{array}{r}
1381 \\
-243 \\
\hline
1138 \\
\end{array}
\]
---
\[
\begin{array}{r}
\_13\_ \\
-178 \\
\hline
070 \\
\end{array}
\]
1. Units place: \( \_ - 8 = 0 \). So, the missing digit in the minuend is 8.
2. Tens place: The result has a 7 in the tens place. Since we borrowed from the hundreds place, the subtraction in the tens place is \(13 - 7 = 6\). So, the missing digit in the minuend is 6.
3. Hundreds place: The result has a 1 in the hundreds place. Since we borrowed from the thousands place, the subtraction in the hundreds place is \(1 - 1 = 0\). So, the missing digit in the minuend is 1.
4. Thousands place: The result has a 0 in the thousands place. So, the missing digit in the minuend is 0.
Thus, the complete subtraction is:
\[
\begin{array}{r}
1138 \\
-178 \\
\hline
960 \\
\end{array}
\]
---
\[
\boxed{
\begin{array}{r}
5819 \\
-1566 \\
\hline
4253 \\
\end{array}
\quad
\begin{array}{r}
7298 \\
-263 \\
\hline
7035 \\
\end{array}
\quad
\begin{array}{r}
1765 \\
-351 \\
\hline
1414 \\
\end{array}
\quad
\begin{array}{r}
6372 \\
-358 \\
\hline
5914 \\
\end{array}
\quad
\begin{array}{r}
1381 \\
-243 \\
\hline
1138 \\
\end{array}
\quad
\begin{array}{r}
1138 \\
-178 \\
\hline
960 \\
\end{array}
}
\]
---
Problem 1:
\[
\begin{array}{r}
\_819 \\
-15\_6 \\
\hline
44\_ \\
\end{array}
\]
1. Units place: \(9 - 6 = 3\). So, the units digit of the result is 3.
2. Tens place: The result has a 4 in the tens place. Since we borrowed from the hundreds place, the subtraction in the tens place is \(11 - 5 = 6\). So, the missing digit in the minuend is 6.
3. Hundreds place: The result has an 8 in the hundreds place. Since we borrowed from the thousands place, the subtraction in the hundreds place is \(7 - 1 = 6\). So, the missing digit in the minuend is 7.
4. Thousands place: The result has a 4 in the thousands place. Since we borrowed from the thousands place, the subtraction in the thousands place is \(5 - 1 = 4\). So, the missing digit in the minuend is 5.
Thus, the complete subtraction is:
\[
\begin{array}{r}
5819 \\
-1566 \\
\hline
4253 \\
\end{array}
\]
---
Problem 2:
\[
\begin{array}{r}
72\_ \\
-263 \\
\hline
\_375 \\
\end{array}
\]
1. Units place: \( \_ - 3 = 5 \). So, the missing digit in the minuend is 8.
2. Tens place: The result has a 7 in the tens place. Since we borrowed from the hundreds place, the subtraction in the tens place is \(12 - 6 = 6\). So, the missing digit in the minuend is 9.
3. Hundreds place: The result has a 3 in the hundreds place. Since we borrowed from the thousands place, the subtraction in the hundreds place is \(6 - 2 = 4\). So, the missing digit in the minuend is 4.
4. Thousands place: The result has a 4 in the thousands place. So, the missing digit in the minuend is 4.
Thus, the complete subtraction is:
\[
\begin{array}{r}
7298 \\
-263 \\
\hline
7035 \\
\end{array}
\]
---
Problem 3:
\[
\begin{array}{r}
\_76\_ \\
-351 \\
\hline
134 \\
\end{array}
\]
1. Units place: \( \_ - 1 = 4 \). So, the missing digit in the minuend is 5.
2. Tens place: The result has a 3 in the tens place. Since we borrowed from the hundreds place, the subtraction in the tens place is \(16 - 5 = 11\). So, the missing digit in the minuend is 6.
3. Hundreds place: The result has a 7 in the hundreds place. Since we borrowed from the thousands place, the subtraction in the hundreds place is \(6 - 3 = 3\). So, the missing digit in the minuend is 4.
4. Thousands place: The result has a 1 in the thousands place. So, the missing digit in the minuend is 1.
Thus, the complete subtraction is:
\[
\begin{array}{r}
1765 \\
-351 \\
\hline
1414 \\
\end{array}
\]
---
Problem 4:
\[
\begin{array}{r}
63\_2 \\
-358 \\
\hline
\_91\_ \\
\end{array}
\]
1. Units place: \(2 - 8\) requires borrowing, so \(12 - 8 = 4\). So, the missing digit in the result is 4.
2. Tens place: The result has a 1 in the tens place. Since we borrowed from the hundreds place, the subtraction in the tens place is \(2 - 5 = 7\). So, the missing digit in the minuend is 7.
3. Hundreds place: The result has a 9 in the hundreds place. Since we borrowed from the thousands place, the subtraction in the hundreds place is \(5 - 3 = 2\). So, the missing digit in the minuend is 2.
4. Thousands place: The result has a 2 in the thousands place. So, the missing digit in the minuend is 2.
Thus, the complete subtraction is:
\[
\begin{array}{r}
6372 \\
-358 \\
\hline
5914 \\
\end{array}
\]
---
Problem 5:
\[
\begin{array}{r}
\_3\_1 \\
-243 \\
\hline
641 \\
\end{array}
\]
1. Units place: \(1 - 3\) requires borrowing, so \(11 - 3 = 8\). So, the missing digit in the minuend is 8.
2. Tens place: The result has a 4 in the tens place. Since we borrowed from the hundreds place, the subtraction in the tens place is \(2 - 4 = 8\). So, the missing digit in the minuend is 8.
3. Hundreds place: The result has a 3 in the hundreds place. Since we borrowed from the thousands place, the subtraction in the hundreds place is \(3 - 2 = 1\). So, the missing digit in the minuend is 1.
4. Thousands place: The result has a 1 in the thousands place. So, the missing digit in the minuend is 1.
Thus, the complete subtraction is:
\[
\begin{array}{r}
1381 \\
-243 \\
\hline
1138 \\
\end{array}
\]
---
Problem 6:
\[
\begin{array}{r}
\_13\_ \\
-178 \\
\hline
070 \\
\end{array}
\]
1. Units place: \( \_ - 8 = 0 \). So, the missing digit in the minuend is 8.
2. Tens place: The result has a 7 in the tens place. Since we borrowed from the hundreds place, the subtraction in the tens place is \(13 - 7 = 6\). So, the missing digit in the minuend is 6.
3. Hundreds place: The result has a 1 in the hundreds place. Since we borrowed from the thousands place, the subtraction in the hundreds place is \(1 - 1 = 0\). So, the missing digit in the minuend is 1.
4. Thousands place: The result has a 0 in the thousands place. So, the missing digit in the minuend is 0.
Thus, the complete subtraction is:
\[
\begin{array}{r}
1138 \\
-178 \\
\hline
960 \\
\end{array}
\]
---
Final Answer:
\[
\boxed{
\begin{array}{r}
5819 \\
-1566 \\
\hline
4253 \\
\end{array}
\quad
\begin{array}{r}
7298 \\
-263 \\
\hline
7035 \\
\end{array}
\quad
\begin{array}{r}
1765 \\
-351 \\
\hline
1414 \\
\end{array}
\quad
\begin{array}{r}
6372 \\
-358 \\
\hline
5914 \\
\end{array}
\quad
\begin{array}{r}
1381 \\
-243 \\
\hline
1138 \\
\end{array}
\quad
\begin{array}{r}
1138 \\
-178 \\
\hline
960 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of subtraction worksheet with missing digits.
