Volume, Surface Area Rectangular Prisms Worksheet - Free Printable
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Step-by-step solution for: Volume, Surface Area Rectangular Prisms Worksheet
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Show Answer Key & Explanations
Step-by-step solution for: Volume, Surface Area Rectangular Prisms Worksheet
To solve the problem of finding the surface area for each shape, we need to use the appropriate formulas for prisms and cylinders. Let's go through each shape step by step.
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Dimensions:
- Length (\( l \)) = 6 ft
- Width (\( w \)) = 4 ft
- Height (\( h \)) = 12 ft
Formula for Surface Area of a Rectangular Prism:
\[ \text{Surface Area} = 2(lw + lh + wh) \]
Calculation:
\[ \text{Surface Area} = 2(6 \cdot 4 + 6 \cdot 12 + 4 \cdot 12) \]
\[ = 2(24 + 72 + 48) \]
\[ = 2(144) \]
\[ = 288 \, \text{ft}^2 \]
Answer:
\[ \boxed{288 \, \text{ft}^2} \]
---
Dimensions:
- Base (\( b \)) = 6 yd
- Height of triangle (\( h_{\text{triangle}} \)) = 5 yd
- Slant height (\( s \)) = 7 yd
- Prism height (\( H \)) = 3 yd
Formula for Surface Area of a Triangular Prism:
\[ \text{Surface Area} = \text{Base Area} \times 2 + \text{Perimeter of Base} \times \text{Height of Prism} \]
Step 1: Calculate the Base Area of the Triangle:
\[ \text{Base Area} = \frac{1}{2} \times b \times h_{\text{triangle}} \]
\[ = \frac{1}{2} \times 6 \times 5 \]
\[ = 15 \, \text{yd}^2 \]
Step 2: Calculate the Perimeter of the Base Triangle:
The base is an isosceles triangle with sides \( b = 6 \, \text{yd} \), \( s = 7 \, \text{yd} \), and \( s = 7 \, \text{yd} \).
\[ \text{Perimeter} = 6 + 7 + 7 = 20 \, \text{yd} \]
Step 3: Calculate the Lateral Surface Area:
\[ \text{Lateral Surface Area} = \text{Perimeter of Base} \times \text{Height of Prism} \]
\[ = 20 \times 3 \]
\[ = 60 \, \text{yd}^2 \]
Step 4: Total Surface Area:
\[ \text{Surface Area} = 2 \times \text{Base Area} + \text{Lateral Surface Area} \]
\[ = 2 \times 15 + 60 \]
\[ = 30 + 60 \]
\[ = 90 \, \text{yd}^2 \]
Answer:
\[ \boxed{90 \, \text{yd}^2} \]
---
Dimensions:
- Length (\( l \)) = 8 in
- Width (\( w \)) = 6 in
- Height (\( h \)) = 13 in
Formula for Surface Area of a Rectangular Prism:
\[ \text{Surface Area} = 2(lw + lh + wh) \]
Calculation:
\[ \text{Surface Area} = 2(8 \cdot 6 + 8 \cdot 13 + 6 \cdot 13) \]
\[ = 2(48 + 104 + 78) \]
\[ = 2(230) \]
\[ = 460 \, \text{in}^2 \]
Answer:
\[ \boxed{460 \, \text{in}^2} \]
---
Dimensions:
- Bases of trapezoid (\( b_1 \)) = 12 in, (\( b_2 \)) = 9 in
- Height of trapezoid (\( h_{\text{trapezoid}} \)) = 8 in
- Slant height (\( s \)) = 15 in
- Prism height (\( H \)) = 6 in
Formula for Surface Area of a Trapezoidal Prism:
\[ \text{Surface Area} = 2 \times \text{Area of Trapezoid} + \text{Perimeter of Trapezoid} \times \text{Height of Prism} \]
Step 1: Calculate the Area of the Trapezoid:
\[ \text{Area of Trapezoid} = \frac{1}{2} \times (b_1 + b_2) \times h_{\text{trapezoid}} \]
\[ = \frac{1}{2} \times (12 + 9) \times 8 \]
\[ = \frac{1}{2} \times 21 \times 8 \]
\[ = 84 \, \text{in}^2 \]
Step 2: Calculate the Perimeter of the Trapezoid:
The perimeter includes the two bases and the two slant heights.
\[ \text{Perimeter} = b_1 + b_2 + 2s \]
\[ = 12 + 9 + 2 \times 15 \]
\[ = 12 + 9 + 30 \]
\[ = 51 \, \text{in} \]
Step 3: Calculate the Lateral Surface Area:
\[ \text{Lateral Surface Area} = \text{Perimeter of Trapezoid} \times \text{Height of Prism} \]
\[ = 51 \times 6 \]
\[ = 306 \, \text{in}^2 \]
Step 4: Total Surface Area:
\[ \text{Surface Area} = 2 \times \text{Area of Trapezoid} + \text{Lateral Surface Area} \]
\[ = 2 \times 84 + 306 \]
\[ = 168 + 306 \]
\[ = 474 \, \text{in}^2 \]
Answer:
\[ \boxed{474 \, \text{in}^2} \]
---
Dimensions:
- Length (\( l \)) = 9 ft
- Width (\( w \)) = 5 ft
- Height (\( h \)) = 36 ft
Formula for Surface Area of a Rectangular Prism:
\[ \text{Surface Area} = 2(lw + lh + wh) \]
Calculation:
\[ \text{Surface Area} = 2(9 \cdot 5 + 9 \cdot 36 + 5 \cdot 36) \]
\[ = 2(45 + 324 + 180) \]
\[ = 2(549) \]
\[ = 1098 \, \text{ft}^2 \]
Answer:
\[ \boxed{1098 \, \text{ft}^2} \]
---
Dimensions:
- Radius (\( r \)) = 10 m
- Height (\( h \)) = 14 m
Formula for Surface Area of a Cylinder:
\[ \text{Surface Area} = 2\pi r^2 + 2\pi rh \]
Step 1: Calculate the Area of the Two Bases:
\[ \text{Area of Bases} = 2\pi r^2 \]
\[ = 2\pi (10)^2 \]
\[ = 2\pi \times 100 \]
\[ = 200\pi \, \text{m}^2 \]
Step 2: Calculate the Lateral Surface Area:
\[ \text{Lateral Surface Area} = 2\pi rh \]
\[ = 2\pi (10)(14) \]
\[ = 2\pi \times 140 \]
\[ = 280\pi \, \text{m}^2 \]
Step 3: Total Surface Area:
\[ \text{Surface Area} = 200\pi + 280\pi \]
\[ = 480\pi \, \text{m}^2 \]
Answer:
\[ \boxed{480\pi \, \text{m}^2} \]
---
Dimensions:
- Radius (\( r \)) = 3 cm
- Height (\( h \)) = 11 cm
Formula for Surface Area of a Cylinder:
\[ \text{Surface Area} = 2\pi r^2 + 2\pi rh \]
Step 1: Calculate the Area of the Two Bases:
\[ \text{Area of Bases} = 2\pi r^2 \]
\[ = 2\pi (3)^2 \]
\[ = 2\pi \times 9 \]
\[ = 18\pi \, \text{cm}^2 \]
Step 2: Calculate the Lateral Surface Area:
\[ \text{Lateral Surface Area} = 2\pi rh \]
\[ = 2\pi (3)(11) \]
\[ = 2\pi \times 33 \]
\[ = 66\pi \, \text{cm}^2 \]
Step 3: Total Surface Area:
\[ \text{Surface Area} = 18\pi + 66\pi \]
\[ = 84\pi \, \text{cm}^2 \]
Answer:
\[ \boxed{84\pi \, \text{cm}^2} \]
---
Dimensions:
- Length (\( l \)) = 7 ft
- Width (\( w \)) = 4 ft
- Height (\( h \)) = 14 ft
Formula for Surface Area of a Rectangular Prism:
\[ \text{Surface Area} = 2(lw + lh + wh) \]
Calculation:
\[ \text{Surface Area} = 2(7 \cdot 4 + 7 \cdot 14 + 4 \cdot 14) \]
\[ = 2(28 + 98 + 56) \]
\[ = 2(182) \]
\[ = 364 \, \text{ft}^2 \]
Answer:
\[ \boxed{364 \, \text{ft}^2} \]
---
Dimensions:
- Base (\( b \)) = 10 ft
- Height of triangle (\( h_{\text{triangle}} \)) = 12 ft
- Slant height (\( s \)) = 13 ft
- Prism height (\( H \)) = 17 ft
Formula for Surface Area of a Triangular Prism:
\[ \text{Surface Area} = \text{Base Area} \times 2 + \text{Perimeter of Base} \times \text{Height of Prism} \]
Step 1: Calculate the Base Area of the Triangle:
\[ \text{Base Area} = \frac{1}{2} \times b \times h_{\text{triangle}} \]
\[ = \frac{1}{2} \times 10 \times 12 \]
\[ = 60 \, \text{ft}^2 \]
Step 2: Calculate the Perimeter of the Base Triangle:
The base is a right triangle with sides \( b = 10 \, \text{ft} \), \( h_{\text{triangle}} = 12 \, \text{ft} \), and hypotenuse \( s = 13 \, \text{ft} \).
\[ \text{Perimeter} = 10 + 12 + 13 = 35 \, \text{ft} \]
Step 3: Calculate the Lateral Surface Area:
\[ \text{Lateral Surface Area} = \text{Perimeter of Base} \times \text{Height of Prism} \]
\[ = 35 \times 17 \]
\[ = 595 \, \text{ft}^2 \]
Step 4: Total Surface Area:
\[ \text{Surface Area} = 2 \times \text{Base Area} + \text{Lateral Surface Area} \]
\[ = 2 \times 60 + 595 \]
\[ = 120 + 595 \]
\[ = 715 \, \text{ft}^2 \]
Answer:
\[ \boxed{715 \, \text{ft}^2} \]
---
1. \( \boxed{288 \, \text{ft}^2} \)
2. \( \boxed{90 \, \text{yd}^2} \)
3. \( \boxed{460 \, \text{in}^2} \)
4. \( \boxed{474 \, \text{in}^2} \)
5. \( \boxed{1098 \, \text{ft}^2} \)
6. \( \boxed{480\pi \, \text{m}^2} \)
7. \( \boxed{84\pi \, \text{cm}^2} \)
8. \( \boxed{364 \, \text{ft}^2} \)
9. \( \boxed{715 \, \text{ft}^2} \)
---
1. Rectangular Prism
Dimensions:
- Length (\( l \)) = 6 ft
- Width (\( w \)) = 4 ft
- Height (\( h \)) = 12 ft
Formula for Surface Area of a Rectangular Prism:
\[ \text{Surface Area} = 2(lw + lh + wh) \]
Calculation:
\[ \text{Surface Area} = 2(6 \cdot 4 + 6 \cdot 12 + 4 \cdot 12) \]
\[ = 2(24 + 72 + 48) \]
\[ = 2(144) \]
\[ = 288 \, \text{ft}^2 \]
Answer:
\[ \boxed{288 \, \text{ft}^2} \]
---
2. Triangular Prism
Dimensions:
- Base (\( b \)) = 6 yd
- Height of triangle (\( h_{\text{triangle}} \)) = 5 yd
- Slant height (\( s \)) = 7 yd
- Prism height (\( H \)) = 3 yd
Formula for Surface Area of a Triangular Prism:
\[ \text{Surface Area} = \text{Base Area} \times 2 + \text{Perimeter of Base} \times \text{Height of Prism} \]
Step 1: Calculate the Base Area of the Triangle:
\[ \text{Base Area} = \frac{1}{2} \times b \times h_{\text{triangle}} \]
\[ = \frac{1}{2} \times 6 \times 5 \]
\[ = 15 \, \text{yd}^2 \]
Step 2: Calculate the Perimeter of the Base Triangle:
The base is an isosceles triangle with sides \( b = 6 \, \text{yd} \), \( s = 7 \, \text{yd} \), and \( s = 7 \, \text{yd} \).
\[ \text{Perimeter} = 6 + 7 + 7 = 20 \, \text{yd} \]
Step 3: Calculate the Lateral Surface Area:
\[ \text{Lateral Surface Area} = \text{Perimeter of Base} \times \text{Height of Prism} \]
\[ = 20 \times 3 \]
\[ = 60 \, \text{yd}^2 \]
Step 4: Total Surface Area:
\[ \text{Surface Area} = 2 \times \text{Base Area} + \text{Lateral Surface Area} \]
\[ = 2 \times 15 + 60 \]
\[ = 30 + 60 \]
\[ = 90 \, \text{yd}^2 \]
Answer:
\[ \boxed{90 \, \text{yd}^2} \]
---
3. Rectangular Prism
Dimensions:
- Length (\( l \)) = 8 in
- Width (\( w \)) = 6 in
- Height (\( h \)) = 13 in
Formula for Surface Area of a Rectangular Prism:
\[ \text{Surface Area} = 2(lw + lh + wh) \]
Calculation:
\[ \text{Surface Area} = 2(8 \cdot 6 + 8 \cdot 13 + 6 \cdot 13) \]
\[ = 2(48 + 104 + 78) \]
\[ = 2(230) \]
\[ = 460 \, \text{in}^2 \]
Answer:
\[ \boxed{460 \, \text{in}^2} \]
---
4. Trapezoidal Prism
Dimensions:
- Bases of trapezoid (\( b_1 \)) = 12 in, (\( b_2 \)) = 9 in
- Height of trapezoid (\( h_{\text{trapezoid}} \)) = 8 in
- Slant height (\( s \)) = 15 in
- Prism height (\( H \)) = 6 in
Formula for Surface Area of a Trapezoidal Prism:
\[ \text{Surface Area} = 2 \times \text{Area of Trapezoid} + \text{Perimeter of Trapezoid} \times \text{Height of Prism} \]
Step 1: Calculate the Area of the Trapezoid:
\[ \text{Area of Trapezoid} = \frac{1}{2} \times (b_1 + b_2) \times h_{\text{trapezoid}} \]
\[ = \frac{1}{2} \times (12 + 9) \times 8 \]
\[ = \frac{1}{2} \times 21 \times 8 \]
\[ = 84 \, \text{in}^2 \]
Step 2: Calculate the Perimeter of the Trapezoid:
The perimeter includes the two bases and the two slant heights.
\[ \text{Perimeter} = b_1 + b_2 + 2s \]
\[ = 12 + 9 + 2 \times 15 \]
\[ = 12 + 9 + 30 \]
\[ = 51 \, \text{in} \]
Step 3: Calculate the Lateral Surface Area:
\[ \text{Lateral Surface Area} = \text{Perimeter of Trapezoid} \times \text{Height of Prism} \]
\[ = 51 \times 6 \]
\[ = 306 \, \text{in}^2 \]
Step 4: Total Surface Area:
\[ \text{Surface Area} = 2 \times \text{Area of Trapezoid} + \text{Lateral Surface Area} \]
\[ = 2 \times 84 + 306 \]
\[ = 168 + 306 \]
\[ = 474 \, \text{in}^2 \]
Answer:
\[ \boxed{474 \, \text{in}^2} \]
---
5. Rectangular Prism
Dimensions:
- Length (\( l \)) = 9 ft
- Width (\( w \)) = 5 ft
- Height (\( h \)) = 36 ft
Formula for Surface Area of a Rectangular Prism:
\[ \text{Surface Area} = 2(lw + lh + wh) \]
Calculation:
\[ \text{Surface Area} = 2(9 \cdot 5 + 9 \cdot 36 + 5 \cdot 36) \]
\[ = 2(45 + 324 + 180) \]
\[ = 2(549) \]
\[ = 1098 \, \text{ft}^2 \]
Answer:
\[ \boxed{1098 \, \text{ft}^2} \]
---
6. Cylinder
Dimensions:
- Radius (\( r \)) = 10 m
- Height (\( h \)) = 14 m
Formula for Surface Area of a Cylinder:
\[ \text{Surface Area} = 2\pi r^2 + 2\pi rh \]
Step 1: Calculate the Area of the Two Bases:
\[ \text{Area of Bases} = 2\pi r^2 \]
\[ = 2\pi (10)^2 \]
\[ = 2\pi \times 100 \]
\[ = 200\pi \, \text{m}^2 \]
Step 2: Calculate the Lateral Surface Area:
\[ \text{Lateral Surface Area} = 2\pi rh \]
\[ = 2\pi (10)(14) \]
\[ = 2\pi \times 140 \]
\[ = 280\pi \, \text{m}^2 \]
Step 3: Total Surface Area:
\[ \text{Surface Area} = 200\pi + 280\pi \]
\[ = 480\pi \, \text{m}^2 \]
Answer:
\[ \boxed{480\pi \, \text{m}^2} \]
---
7. Cylinder
Dimensions:
- Radius (\( r \)) = 3 cm
- Height (\( h \)) = 11 cm
Formula for Surface Area of a Cylinder:
\[ \text{Surface Area} = 2\pi r^2 + 2\pi rh \]
Step 1: Calculate the Area of the Two Bases:
\[ \text{Area of Bases} = 2\pi r^2 \]
\[ = 2\pi (3)^2 \]
\[ = 2\pi \times 9 \]
\[ = 18\pi \, \text{cm}^2 \]
Step 2: Calculate the Lateral Surface Area:
\[ \text{Lateral Surface Area} = 2\pi rh \]
\[ = 2\pi (3)(11) \]
\[ = 2\pi \times 33 \]
\[ = 66\pi \, \text{cm}^2 \]
Step 3: Total Surface Area:
\[ \text{Surface Area} = 18\pi + 66\pi \]
\[ = 84\pi \, \text{cm}^2 \]
Answer:
\[ \boxed{84\pi \, \text{cm}^2} \]
---
8. Rectangular Prism
Dimensions:
- Length (\( l \)) = 7 ft
- Width (\( w \)) = 4 ft
- Height (\( h \)) = 14 ft
Formula for Surface Area of a Rectangular Prism:
\[ \text{Surface Area} = 2(lw + lh + wh) \]
Calculation:
\[ \text{Surface Area} = 2(7 \cdot 4 + 7 \cdot 14 + 4 \cdot 14) \]
\[ = 2(28 + 98 + 56) \]
\[ = 2(182) \]
\[ = 364 \, \text{ft}^2 \]
Answer:
\[ \boxed{364 \, \text{ft}^2} \]
---
9. Triangular Prism
Dimensions:
- Base (\( b \)) = 10 ft
- Height of triangle (\( h_{\text{triangle}} \)) = 12 ft
- Slant height (\( s \)) = 13 ft
- Prism height (\( H \)) = 17 ft
Formula for Surface Area of a Triangular Prism:
\[ \text{Surface Area} = \text{Base Area} \times 2 + \text{Perimeter of Base} \times \text{Height of Prism} \]
Step 1: Calculate the Base Area of the Triangle:
\[ \text{Base Area} = \frac{1}{2} \times b \times h_{\text{triangle}} \]
\[ = \frac{1}{2} \times 10 \times 12 \]
\[ = 60 \, \text{ft}^2 \]
Step 2: Calculate the Perimeter of the Base Triangle:
The base is a right triangle with sides \( b = 10 \, \text{ft} \), \( h_{\text{triangle}} = 12 \, \text{ft} \), and hypotenuse \( s = 13 \, \text{ft} \).
\[ \text{Perimeter} = 10 + 12 + 13 = 35 \, \text{ft} \]
Step 3: Calculate the Lateral Surface Area:
\[ \text{Lateral Surface Area} = \text{Perimeter of Base} \times \text{Height of Prism} \]
\[ = 35 \times 17 \]
\[ = 595 \, \text{ft}^2 \]
Step 4: Total Surface Area:
\[ \text{Surface Area} = 2 \times \text{Base Area} + \text{Lateral Surface Area} \]
\[ = 2 \times 60 + 595 \]
\[ = 120 + 595 \]
\[ = 715 \, \text{ft}^2 \]
Answer:
\[ \boxed{715 \, \text{ft}^2} \]
---
Final Answers:
1. \( \boxed{288 \, \text{ft}^2} \)
2. \( \boxed{90 \, \text{yd}^2} \)
3. \( \boxed{460 \, \text{in}^2} \)
4. \( \boxed{474 \, \text{in}^2} \)
5. \( \boxed{1098 \, \text{ft}^2} \)
6. \( \boxed{480\pi \, \text{m}^2} \)
7. \( \boxed{84\pi \, \text{cm}^2} \)
8. \( \boxed{364 \, \text{ft}^2} \)
9. \( \boxed{715 \, \text{ft}^2} \)
Parent Tip: Review the logic above to help your child master the concept of surface area and volume worksheets.