Surface area of sphere and hemisphere worksheet - Free Printable
Educational worksheet: Surface area of sphere and hemisphere worksheet. Download and print for classroom or home learning activities.
JPG
1000×1291
121.2 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #1203838
⭐
Show Answer Key & Explanations
Step-by-step solution for: Surface area of sphere and hemisphere worksheet
▼
Show Answer Key & Explanations
Step-by-step solution for: Surface area of sphere and hemisphere worksheet
Let’s solve each question one by one, step by step. We’ll use the formula for surface area of a sphere and hemisphere as needed.
---
Q1. Surface area of a sphere of radius 14 cm
Formula:
Surface Area = 4πr²
Take π ≈ 22/7
So,
= 4 × (22/7) × 14 × 14
First, 14 × 14 = 196
Then, 4 × 22/7 × 196
→ 4 × 22 × 28 (because 196 ÷ 7 = 28)
→ 88 × 28 = let’s calculate:
80×28 = 2240, 8×28=224 → total = 2240 + 224 = 2464 cm²
✔ Answer: (c) 2464 cm²
---
Q2. Surface area of a sphere of radius 7 cm
Again, 4πr² = 4 × (22/7) × 7 × 7
The 7 in denominator cancels with one 7 → becomes 4 × 22 × 7
= 88 × 7 = 616 cm²
✔ Answer: (b) 616 cm²
---
Q3. Hollow sphere radius 2.8 m — find area available to motorcyclist
This is inner surface area of hollow sphere → same as surface area of sphere.
Radius = 2.8 m
Area = 4πr² = 4 × (22/7) × 2.8 × 2.8
First, 2.8 × 2.8 = 7.84
Now, 4 × 22/7 × 7.84
→ Let’s simplify: 7.84 ÷ 7 = 1.12
So, 4 × 22 × 1.12 = 88 × 1.12
Calculate 88 × 1.12:
88 × 1 = 88
88 × 0.12 = 10.56
Total = 88 + 10.56 = 98.56 m²
✔ Answer: (a) 98.56 m²
---
Q4. Hemispherical balloon radius increases from 6 cm to 12 cm — ratio of surface areas
For a hemisphere, curved surface area = 2πr² (we assume they mean curved surface area since it's a balloon being inflated)
Initial CSA = 2π(6)² = 2π×36
Final CSA = 2π(12)² = 2π×144
Ratio = (2π×36) : (2π×144) = 36 : 144 = 1 : 4
✔ Answer: (a) 1 : 4
---
Q5. Total surface area of sphere is 154 cm² — find diameter
Surface area = 4πr² = 154
So, 4 × (22/7) × r² = 154
→ (88/7) × r² = 154
Multiply both sides by 7: 88 × r² = 1078
→ r² = 1078 ÷ 88 = 12.25
→ r = √12.25 = 3.5 cm
Diameter = 2 × 3.5 = 7 cm
✔ Answer: (c) 7 cm
---
Q6. Radius doubled — ratio of old surface area to new
Old SA = 4πr²
New SA = 4π(2r)² = 4π×4r² = 16πr²
Ratio old : new = 4πr² : 16πr² = 1 : 4
But note: question says “ratio of the surface area of the old is to new spheres” → so old:new = 1:4
✔ Answer: (d) 1:4
---
Q7. Hemispherical bowl radius 3.5 cm — curved surface area
Curved surface area of hemisphere = 2πr²
= 2 × (22/7) × 3.5 × 3.5
3.5 × 3.5 = 12.25
2 × 22/7 × 12.25 = (44/7) × 12.25
12.25 ÷ 7 = 1.75
So, 44 × 1.75 = ?
44 × 1 = 44
44 × 0.75 = 33
Total = 44 + 33 = 77 cm²
Wait — but options have decimals. Let me recalculate precisely:
Actually, 3.5 = 7/2
So, r² = (7/2)² = 49/4
CSA = 2 × (22/7) × (49/4) = (44/7) × (49/4) = (44 × 49) / (7 × 4)
Simplify: 49 ÷ 7 = 7 → (44 × 7) / 4 = 308 / 4 = 77 cm²
But option (a) is 77 cm² — why are there decimal options? Maybe they used π = 3.14?
Try with π = 3.14:
CSA = 2 × 3.14 × (3.5)² = 2 × 3.14 × 12.25
= 6.28 × 12.25
Calculate:
6 × 12.25 = 73.5
0.28 × 12.25 = let’s see: 0.2×12.25=2.45, 0.08×12.25=0.98 → total 3.43
So 73.5 + 3.43 = 76.93 ≈ 77.0? Still close to 77.
But option (b) is 77.21 — maybe they used more precise π?
Wait — perhaps I made a mistake. Let me check again with exact fractions.
We had: 2 × (22/7) × (7/2)² = 2 × (22/7) × (49/4) = (2 × 22 × 49) / (7 × 4)
= (2156) / (28) = divide numerator and denominator by 28:
2156 ÷ 28: 28×77 = 2156 → exactly 77.
So answer should be 77 cm²
But looking at options: (a) 77 cm² — that’s correct.
Why are others there? Maybe trick? But mathematically, it’s 77.
✔ Answer: (a) 77 cm²
*(Note: If the problem meant total surface area including base, it would be 3πr² = 3×22/7×12.25 = 115.5, which isn’t an option. So definitely curved surface area.)*
---
Q8. Shot-put metallic sphere radius 4.9 cm — find area
Surface area = 4πr² = 4 × (22/7) × 4.9 × 4.9
First, 4.9 × 4.9 = 24.01
Now, 4 × 22/7 × 24.01 = (88/7) × 24.01
24.01 ÷ 7 = 3.43
Then 88 × 3.43
Calculate:
80 × 3.43 = 274.4
8 × 3.43 = 27.44
Total = 274.4 + 27.44 = 301.84 cm²
✔ Answer: (c) 301.84 cm²
---
Q9. Coconut radius 7 cm — cover with golden paper, cost Rs 7 per cm² — total cost?
First, surface area of sphere = 4πr² = 4 × (22/7) × 7 × 7 = 4 × 22 × 7 = 616 cm²
Cost = 616 × 7 = ?
600 × 7 = 4200
16 × 7 = 112
Total = 4200 + 112 = Rs 4312
✔ Answer: (b) Rs. 4312
---
Final Answers:
Q1: (c)
Q2: (b)
Q3: (a)
Q4: (a)
Q5: (c)
Q6: (d)
Q7: (a)
Q8: (c)
Q9: (b)
──────────────────────────────────────
Final Answer:
Q1: (c) 2464 cm²
Q2: (b) 616 cm²
Q3: (a) 98.56 m²
Q4: (a) 1 : 4
Q5: (c) 7 cm
Q6: (d) 1:4
Q7: (a) 77 cm²
Q8: (c) 301.84 cm²
Q9: (b) Rs. 4312
---
Q1. Surface area of a sphere of radius 14 cm
Formula:
Surface Area = 4πr²
Take π ≈ 22/7
So,
= 4 × (22/7) × 14 × 14
First, 14 × 14 = 196
Then, 4 × 22/7 × 196
→ 4 × 22 × 28 (because 196 ÷ 7 = 28)
→ 88 × 28 = let’s calculate:
80×28 = 2240, 8×28=224 → total = 2240 + 224 = 2464 cm²
✔ Answer: (c) 2464 cm²
---
Q2. Surface area of a sphere of radius 7 cm
Again, 4πr² = 4 × (22/7) × 7 × 7
The 7 in denominator cancels with one 7 → becomes 4 × 22 × 7
= 88 × 7 = 616 cm²
✔ Answer: (b) 616 cm²
---
Q3. Hollow sphere radius 2.8 m — find area available to motorcyclist
This is inner surface area of hollow sphere → same as surface area of sphere.
Radius = 2.8 m
Area = 4πr² = 4 × (22/7) × 2.8 × 2.8
First, 2.8 × 2.8 = 7.84
Now, 4 × 22/7 × 7.84
→ Let’s simplify: 7.84 ÷ 7 = 1.12
So, 4 × 22 × 1.12 = 88 × 1.12
Calculate 88 × 1.12:
88 × 1 = 88
88 × 0.12 = 10.56
Total = 88 + 10.56 = 98.56 m²
✔ Answer: (a) 98.56 m²
---
Q4. Hemispherical balloon radius increases from 6 cm to 12 cm — ratio of surface areas
For a hemisphere, curved surface area = 2πr² (we assume they mean curved surface area since it's a balloon being inflated)
Initial CSA = 2π(6)² = 2π×36
Final CSA = 2π(12)² = 2π×144
Ratio = (2π×36) : (2π×144) = 36 : 144 = 1 : 4
✔ Answer: (a) 1 : 4
---
Q5. Total surface area of sphere is 154 cm² — find diameter
Surface area = 4πr² = 154
So, 4 × (22/7) × r² = 154
→ (88/7) × r² = 154
Multiply both sides by 7: 88 × r² = 1078
→ r² = 1078 ÷ 88 = 12.25
→ r = √12.25 = 3.5 cm
Diameter = 2 × 3.5 = 7 cm
✔ Answer: (c) 7 cm
---
Q6. Radius doubled — ratio of old surface area to new
Old SA = 4πr²
New SA = 4π(2r)² = 4π×4r² = 16πr²
Ratio old : new = 4πr² : 16πr² = 1 : 4
But note: question says “ratio of the surface area of the old is to new spheres” → so old:new = 1:4
✔ Answer: (d) 1:4
---
Q7. Hemispherical bowl radius 3.5 cm — curved surface area
Curved surface area of hemisphere = 2πr²
= 2 × (22/7) × 3.5 × 3.5
3.5 × 3.5 = 12.25
2 × 22/7 × 12.25 = (44/7) × 12.25
12.25 ÷ 7 = 1.75
So, 44 × 1.75 = ?
44 × 1 = 44
44 × 0.75 = 33
Total = 44 + 33 = 77 cm²
Wait — but options have decimals. Let me recalculate precisely:
Actually, 3.5 = 7/2
So, r² = (7/2)² = 49/4
CSA = 2 × (22/7) × (49/4) = (44/7) × (49/4) = (44 × 49) / (7 × 4)
Simplify: 49 ÷ 7 = 7 → (44 × 7) / 4 = 308 / 4 = 77 cm²
But option (a) is 77 cm² — why are there decimal options? Maybe they used π = 3.14?
Try with π = 3.14:
CSA = 2 × 3.14 × (3.5)² = 2 × 3.14 × 12.25
= 6.28 × 12.25
Calculate:
6 × 12.25 = 73.5
0.28 × 12.25 = let’s see: 0.2×12.25=2.45, 0.08×12.25=0.98 → total 3.43
So 73.5 + 3.43 = 76.93 ≈ 77.0? Still close to 77.
But option (b) is 77.21 — maybe they used more precise π?
Wait — perhaps I made a mistake. Let me check again with exact fractions.
We had: 2 × (22/7) × (7/2)² = 2 × (22/7) × (49/4) = (2 × 22 × 49) / (7 × 4)
= (2156) / (28) = divide numerator and denominator by 28:
2156 ÷ 28: 28×77 = 2156 → exactly 77.
So answer should be 77 cm²
But looking at options: (a) 77 cm² — that’s correct.
Why are others there? Maybe trick? But mathematically, it’s 77.
✔ Answer: (a) 77 cm²
*(Note: If the problem meant total surface area including base, it would be 3πr² = 3×22/7×12.25 = 115.5, which isn’t an option. So definitely curved surface area.)*
---
Q8. Shot-put metallic sphere radius 4.9 cm — find area
Surface area = 4πr² = 4 × (22/7) × 4.9 × 4.9
First, 4.9 × 4.9 = 24.01
Now, 4 × 22/7 × 24.01 = (88/7) × 24.01
24.01 ÷ 7 = 3.43
Then 88 × 3.43
Calculate:
80 × 3.43 = 274.4
8 × 3.43 = 27.44
Total = 274.4 + 27.44 = 301.84 cm²
✔ Answer: (c) 301.84 cm²
---
Q9. Coconut radius 7 cm — cover with golden paper, cost Rs 7 per cm² — total cost?
First, surface area of sphere = 4πr² = 4 × (22/7) × 7 × 7 = 4 × 22 × 7 = 616 cm²
Cost = 616 × 7 = ?
600 × 7 = 4200
16 × 7 = 112
Total = 4200 + 112 = Rs 4312
✔ Answer: (b) Rs. 4312
---
Final Answers:
Q1: (c)
Q2: (b)
Q3: (a)
Q4: (a)
Q5: (c)
Q6: (d)
Q7: (a)
Q8: (c)
Q9: (b)
──────────────────────────────────────
Final Answer:
Q1: (c) 2464 cm²
Q2: (b) 616 cm²
Q3: (a) 98.56 m²
Q4: (a) 1 : 4
Q5: (c) 7 cm
Q6: (d) 1:4
Q7: (a) 77 cm²
Q8: (c) 301.84 cm²
Q9: (b) Rs. 4312
Parent Tip: Review the logic above to help your child master the concept of surface area of a sphere worksheet.