Graph showing the solution regions for the inequalities 3x + 7y < 35 and 12x + 7y > -28.
Graph of two linear inequalities: 3x + 7y < 35 and 12x + 7y > -28 on a coordinate plane with grid lines.
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Step-by-step solution for: Graphing systems of inequalities Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Graphing systems of inequalities Worksheets
To solve this system of inequalities, we need to graph each inequality on the coordinate plane and find the region where they overlap. That overlapping region is the solution.
Here are the two inequalities:
1) $3x + 7y < 35$
2) $12x + 7y > -28$
First, let's treat it like an equation to find the boundary line: $3x + 7y = 35$.
We can find the intercepts (where the line crosses the axes) to make graphing easier.
* Find the y-intercept: Set $x = 0$.
$$3(0) + 7y = 35$$
$$7y = 35$$
$$y = 5$$
So, one point is $(0, 5)$.
* Find the x-intercept: Set $y = 0$.
$$3x + 7(0) = 35$$
$$3x = 35$$
$$x = \frac{35}{3} \approx 11.67$$
This point is roughly $(11.67, 0)$. Since the grid only goes to $x=10$, let's pick another integer point to help draw the line accurately within the grid. Let's try $x = 7$:
$$3(7) + 7y = 35$$
$$21 + 7y = 35$$
$$7y = 14$$
$$y = 2$$
So, another good point is $(7, 2)$.
Draw the line: Connect $(0, 5)$ and $(7, 2)$. Because the inequality is strictly less than ($<$), draw a dashed line.
Shade the region: Pick a test point not on the line, like $(0,0)$.
$$3(0) + 7(0) < 35$$
$$0 < 35$$ (True)
Since $(0,0)$ makes the statement true, shade the side of the line that includes $(0,0)$ (below the line).
Treat it as an equation for the boundary: $12x + 7y = -28$.
* Find the y-intercept: Set $x = 0$.
$$12(0) + 7y = -28$$
$$7y = -28$$
$$y = -4$$
So, one point is $(0, -4)$.
* Find the x-intercept: Set $y = 0$.
$$12x + 7(0) = -28$$
$$12x = -28$$
$$x = -\frac{28}{12} = -\frac{7}{3} \approx -2.33$$
Let's find an integer point to make drawing easier. Let's try $x = -7$:
$$12(-7) + 7y = -28$$
$$-84 + 7y = -28$$
$$7y = 56$$
$$y = 8$$
So, another good point is $(-7, 8)$.
Draw the line: Connect $(0, -4)$ and $(-7, 8)$. Because the inequality is strictly greater than ($>$), draw a dashed line.
Shade the region: Pick a test point like $(0,0)$.
$$12(0) + 7(0) > -28$$
$$0 > -28$$ (True)
Since $(0,0)$ makes the statement true, shade the side of the line that includes $(0,0)$ (above/right of the line).
The solution to the system is the area where the shading from Step 1 and Step 2 overlaps.
* From Inequality 1, we shaded below the line passing through $(0,5)$ and $(7,2)$.
* From Inequality 2, we shaded above the line passing through $(0,-4)$ and $(-7,8)$.
The overlapping region is the wedge-shaped area between these two dashed lines that contains the origin $(0,0)$. It is bounded on the top-left by the line $3x+7y=35$ and on the bottom-right by the line $12x+7y=-28$.
Final Answer:
The solution is the region on the graph that satisfies both conditions:
1. Below the dashed line connecting $(0, 5)$ and $(7, 2)$.
2. Above the dashed line connecting $(0, -4)$ and $(-7, 8)$.
This creates an overlapping shaded region containing the origin $(0,0)$.
Here are the two inequalities:
1) $3x + 7y < 35$
2) $12x + 7y > -28$
Step 1: Graph the first inequality ($3x + 7y < 35$)
First, let's treat it like an equation to find the boundary line: $3x + 7y = 35$.
We can find the intercepts (where the line crosses the axes) to make graphing easier.
* Find the y-intercept: Set $x = 0$.
$$3(0) + 7y = 35$$
$$7y = 35$$
$$y = 5$$
So, one point is $(0, 5)$.
* Find the x-intercept: Set $y = 0$.
$$3x + 7(0) = 35$$
$$3x = 35$$
$$x = \frac{35}{3} \approx 11.67$$
This point is roughly $(11.67, 0)$. Since the grid only goes to $x=10$, let's pick another integer point to help draw the line accurately within the grid. Let's try $x = 7$:
$$3(7) + 7y = 35$$
$$21 + 7y = 35$$
$$7y = 14$$
$$y = 2$$
So, another good point is $(7, 2)$.
Draw the line: Connect $(0, 5)$ and $(7, 2)$. Because the inequality is strictly less than ($<$), draw a dashed line.
Shade the region: Pick a test point not on the line, like $(0,0)$.
$$3(0) + 7(0) < 35$$
$$0 < 35$$ (True)
Since $(0,0)$ makes the statement true, shade the side of the line that includes $(0,0)$ (below the line).
Step 2: Graph the second inequality ($12x + 7y > -28$)
Treat it as an equation for the boundary: $12x + 7y = -28$.
* Find the y-intercept: Set $x = 0$.
$$12(0) + 7y = -28$$
$$7y = -28$$
$$y = -4$$
So, one point is $(0, -4)$.
* Find the x-intercept: Set $y = 0$.
$$12x + 7(0) = -28$$
$$12x = -28$$
$$x = -\frac{28}{12} = -\frac{7}{3} \approx -2.33$$
Let's find an integer point to make drawing easier. Let's try $x = -7$:
$$12(-7) + 7y = -28$$
$$-84 + 7y = -28$$
$$7y = 56$$
$$y = 8$$
So, another good point is $(-7, 8)$.
Draw the line: Connect $(0, -4)$ and $(-7, 8)$. Because the inequality is strictly greater than ($>$), draw a dashed line.
Shade the region: Pick a test point like $(0,0)$.
$$12(0) + 7(0) > -28$$
$$0 > -28$$ (True)
Since $(0,0)$ makes the statement true, shade the side of the line that includes $(0,0)$ (above/right of the line).
Step 3: Identify the Solution Region
The solution to the system is the area where the shading from Step 1 and Step 2 overlaps.
* From Inequality 1, we shaded below the line passing through $(0,5)$ and $(7,2)$.
* From Inequality 2, we shaded above the line passing through $(0,-4)$ and $(-7,8)$.
The overlapping region is the wedge-shaped area between these two dashed lines that contains the origin $(0,0)$. It is bounded on the top-left by the line $3x+7y=35$ and on the bottom-right by the line $12x+7y=-28$.
Final Answer:
The solution is the region on the graph that satisfies both conditions:
1. Below the dashed line connecting $(0, 5)$ and $(7, 2)$.
2. Above the dashed line connecting $(0, -4)$ and $(-7, 8)$.
This creates an overlapping shaded region containing the origin $(0,0)$.
Parent Tip: Review the logic above to help your child master the concept of systems inequalities worksheet.