Math worksheet for converting linear equations to function form and graphing them.
Worksheet with three linear equations to convert to function form, complete tables of values, and graph on coordinate planes.
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Show Answer Key & Explanations
Step-by-step solution for: Linear Equations Worksheet - Create a Table of Values and Graph ...
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Show Answer Key & Explanations
Step-by-step solution for: Linear Equations Worksheet - Create a Table of Values and Graph ...
Let's solve each problem step by step.
---
#### Step 1: Write in Function Form
We want to solve for $y$ in terms of $x$:
$$
3x + y = 5
$$
Subtract $3x$ from both sides:
$$
y = -3x + 5
$$
✔ Function Form: $y = -3x + 5$
---
#### Step 2: Create a Table of Values
Use the function $y = -3x + 5$ and plug in values of $x$:
| $x$ | $y = -3x + 5$ | $y$ | $(x, y)$ |
|------|------------------|-------|-----------|
| -2 | $-3(-2) + 5 = 6 + 5 = 11$ | 11 | (-2, 11) |
| -1 | $-3(-1) + 5 = 3 + 5 = 8$ | 8 | (-1, 8) |
| 0 | $-3(0) + 5 = 0 + 5 = 5$ | 5 | (0, 5) |
| 1 | $-3(1) + 5 = -3 + 5 = 2$ | 2 | (1, 2) |
| 2 | $-3(2) + 5 = -6 + 5 = -1$ | -1 | (2, -1) |
✔ Completed table:
| $x$ | $y = -3x + 5$ | $y$ | $(x, y)$ |
|------|------------------|-------|-----------|
| -2 | $-3(-2) + 5$ | 11 | (-2, 11) |
| -1 | $-3(-1) + 5$ | 8 | (-1, 8) |
| 0 | $-3(0) + 5$ | 5 | (0, 5) |
| 1 | $-3(1) + 5$ | 2 | (1, 2) |
| 2 | $-3(2) + 5$ | -1 | (2, -1) |
---
#### Step 3: Graph the Equation
Plot the points:
(-2, 11), (-1, 8), (0, 5), (1, 2), (2, -1)
Then draw a straight line through them. This is a linear graph with slope $-3$ and y-intercept $5$.
> 📌 Note: Since this is text-based, you would plot these on the grid provided.
---
#### Step 1: Write in Function Form
Solve for $y$:
$$
4x + 4y = 8
$$
Divide every term by 4:
$$
x + y = 2
$$
Now solve for $y$:
$$
y = -x + 2
$$
✔ Function Form: $y = -x + 2$
---
#### Step 2: Create a Table of Values
Use $y = -x + 2$:
| $x$ | $y = -x + 2$ | $y$ | $(x, y)$ |
|------|----------------|-------|-----------|
| -2 | $-(-2) + 2 = 2 + 2 = 4$ | 4 | (-2, 4) |
| -1 | $-(-1) + 2 = 1 + 2 = 3$ | 3 | (-1, 3) |
| 0 | $-(0) + 2 = 0 + 2 = 2$ | 2 | (0, 2) |
| 1 | $-(1) + 2 = -1 + 2 = 1$ | 1 | (1, 1) |
| 2 | $-(2) + 2 = -2 + 2 = 0$ | 0 | (2, 0) |
✔ Completed table:
| $x$ | $y = -x + 2$ | $y$ | $(x, y)$ |
|------|----------------|-------|-----------|
| -2 | $-(-2) + 2$ | 4 | (-2, 4) |
| -1 | $-(-1) + 2$ | 3 | (-1, 3) |
| 0 | $-(0) + 2$ | 2 | (0, 2) |
| 1 | $-(1) + 2$ | 1 | (1, 1) |
| 2 | $-(2) + 2$ | 0 | (2, 0) |
---
#### Step 3: Graph the Equation
Plot the points:
(-2, 4), (-1, 3), (0, 2), (1, 1), (2, 0)
Draw a straight line through them. Slope = $-1$, y-intercept = 2.
---
#### Step 1: Write in Function Form
Solve for $y$:
$$
3x - 2y = 6
$$
Subtract $3x$:
$$
-2y = -3x + 6
$$
Divide by $-2$:
$$
y = \frac{3}{2}x - 3
$$
✔ Function Form: $y = \frac{3}{2}x - 3$
---
#### Step 2: Find Coordinates
Use $y = \frac{3}{2}x - 3$
| $x$ | $y = \frac{3}{2}x - 3$ | $y$ | $(x, y)$ |
|------|----------------------------|-------|-----------|
| -4 | $\frac{3}{2}(-4) - 3 = -6 - 3 = -9$ | -9 | (-4, -9) |
| -2 | $\frac{3}{2}(-2) - 3 = -3 - 3 = -6$ | -6 | (-2, -6) |
| 0 | $\frac{3}{2}(0) - 3 = 0 - 3 = -3$ | -3 | (0, -3) |
| 2 | $\frac{3}{2}(2) - 3 = 3 - 3 = 0$ | 0 | (2, 0) |
| 4 | $\frac{3}{2}(4) - 3 = 6 - 3 = 3$ | 3 | (4, 3) |
✔ Completed table:
| $x$ | $y = \frac{3}{2}x - 3$ | $y$ | $(x, y)$ |
|------|----------------------------|-------|-----------|
| -4 | $\frac{3}{2}(-4) - 3$ | -9 | (-4, -9) |
| -2 | $\frac{3}{2}(-2) - 3$ | -6 | (-2, -6) |
| 0 | $\frac{3}{2}(0) - 3$ | -3 | (0, -3) |
| 2 | $\frac{3}{2}(2) - 3$ | 0 | (2, 0) |
| 4 | $\frac{3}{2}(4) - 3$ | 3 | (4, 3) |
---
#### 5)
- Function Form: $y = -3x + 5$
- Table filled as shown above.
#### 6)
- Function Form: $y = -x + 2$
- Table filled as shown above.
#### 7)
- Function Form: $y = \frac{3}{2}x - 3$
- Table filled as shown above.
You can now use the tables to graph problems 5 and 6 on the coordinate planes provided.
Let me know if you'd like help plotting or sketching the graphs!
---
Problem 5: $3x + y = 5$
#### Step 1: Write in Function Form
We want to solve for $y$ in terms of $x$:
$$
3x + y = 5
$$
Subtract $3x$ from both sides:
$$
y = -3x + 5
$$
✔ Function Form: $y = -3x + 5$
---
#### Step 2: Create a Table of Values
Use the function $y = -3x + 5$ and plug in values of $x$:
| $x$ | $y = -3x + 5$ | $y$ | $(x, y)$ |
|------|------------------|-------|-----------|
| -2 | $-3(-2) + 5 = 6 + 5 = 11$ | 11 | (-2, 11) |
| -1 | $-3(-1) + 5 = 3 + 5 = 8$ | 8 | (-1, 8) |
| 0 | $-3(0) + 5 = 0 + 5 = 5$ | 5 | (0, 5) |
| 1 | $-3(1) + 5 = -3 + 5 = 2$ | 2 | (1, 2) |
| 2 | $-3(2) + 5 = -6 + 5 = -1$ | -1 | (2, -1) |
✔ Completed table:
| $x$ | $y = -3x + 5$ | $y$ | $(x, y)$ |
|------|------------------|-------|-----------|
| -2 | $-3(-2) + 5$ | 11 | (-2, 11) |
| -1 | $-3(-1) + 5$ | 8 | (-1, 8) |
| 0 | $-3(0) + 5$ | 5 | (0, 5) |
| 1 | $-3(1) + 5$ | 2 | (1, 2) |
| 2 | $-3(2) + 5$ | -1 | (2, -1) |
---
#### Step 3: Graph the Equation
Plot the points:
(-2, 11), (-1, 8), (0, 5), (1, 2), (2, -1)
Then draw a straight line through them. This is a linear graph with slope $-3$ and y-intercept $5$.
> 📌 Note: Since this is text-based, you would plot these on the grid provided.
---
Problem 6: $4x + 4y = 8$
#### Step 1: Write in Function Form
Solve for $y$:
$$
4x + 4y = 8
$$
Divide every term by 4:
$$
x + y = 2
$$
Now solve for $y$:
$$
y = -x + 2
$$
✔ Function Form: $y = -x + 2$
---
#### Step 2: Create a Table of Values
Use $y = -x + 2$:
| $x$ | $y = -x + 2$ | $y$ | $(x, y)$ |
|------|----------------|-------|-----------|
| -2 | $-(-2) + 2 = 2 + 2 = 4$ | 4 | (-2, 4) |
| -1 | $-(-1) + 2 = 1 + 2 = 3$ | 3 | (-1, 3) |
| 0 | $-(0) + 2 = 0 + 2 = 2$ | 2 | (0, 2) |
| 1 | $-(1) + 2 = -1 + 2 = 1$ | 1 | (1, 1) |
| 2 | $-(2) + 2 = -2 + 2 = 0$ | 0 | (2, 0) |
✔ Completed table:
| $x$ | $y = -x + 2$ | $y$ | $(x, y)$ |
|------|----------------|-------|-----------|
| -2 | $-(-2) + 2$ | 4 | (-2, 4) |
| -1 | $-(-1) + 2$ | 3 | (-1, 3) |
| 0 | $-(0) + 2$ | 2 | (0, 2) |
| 1 | $-(1) + 2$ | 1 | (1, 1) |
| 2 | $-(2) + 2$ | 0 | (2, 0) |
---
#### Step 3: Graph the Equation
Plot the points:
(-2, 4), (-1, 3), (0, 2), (1, 1), (2, 0)
Draw a straight line through them. Slope = $-1$, y-intercept = 2.
---
Problem 7: $3x - 2y = 6$
#### Step 1: Write in Function Form
Solve for $y$:
$$
3x - 2y = 6
$$
Subtract $3x$:
$$
-2y = -3x + 6
$$
Divide by $-2$:
$$
y = \frac{3}{2}x - 3
$$
✔ Function Form: $y = \frac{3}{2}x - 3$
---
#### Step 2: Find Coordinates
Use $y = \frac{3}{2}x - 3$
| $x$ | $y = \frac{3}{2}x - 3$ | $y$ | $(x, y)$ |
|------|----------------------------|-------|-----------|
| -4 | $\frac{3}{2}(-4) - 3 = -6 - 3 = -9$ | -9 | (-4, -9) |
| -2 | $\frac{3}{2}(-2) - 3 = -3 - 3 = -6$ | -6 | (-2, -6) |
| 0 | $\frac{3}{2}(0) - 3 = 0 - 3 = -3$ | -3 | (0, -3) |
| 2 | $\frac{3}{2}(2) - 3 = 3 - 3 = 0$ | 0 | (2, 0) |
| 4 | $\frac{3}{2}(4) - 3 = 6 - 3 = 3$ | 3 | (4, 3) |
✔ Completed table:
| $x$ | $y = \frac{3}{2}x - 3$ | $y$ | $(x, y)$ |
|------|----------------------------|-------|-----------|
| -4 | $\frac{3}{2}(-4) - 3$ | -9 | (-4, -9) |
| -2 | $\frac{3}{2}(-2) - 3$ | -6 | (-2, -6) |
| 0 | $\frac{3}{2}(0) - 3$ | -3 | (0, -3) |
| 2 | $\frac{3}{2}(2) - 3$ | 0 | (2, 0) |
| 4 | $\frac{3}{2}(4) - 3$ | 3 | (4, 3) |
---
✔ Final Answers Summary:
#### 5)
- Function Form: $y = -3x + 5$
- Table filled as shown above.
#### 6)
- Function Form: $y = -x + 2$
- Table filled as shown above.
#### 7)
- Function Form: $y = \frac{3}{2}x - 3$
- Table filled as shown above.
You can now use the tables to graph problems 5 and 6 on the coordinate planes provided.
Let me know if you'd like help plotting or sketching the graphs!
Parent Tip: Review the logic above to help your child master the concept of tables graphs and equations worksheet.