I'll work through each question step by step, solving the genetics problems carefully.
Questions 1-5: Monohybrid Cross with Pea Plants
Looking at the diagram:
- P₁ generation: Short pea plant × Tall pea plant
- F₁ generation: All tall pea plants
- F₂ generation: 3 tall : 1 short
Question 1: The single trait being considered is
plant height (tall vs. short).
Question 2: In the F₁ generation, all plants are tall. In the F₂ generation, there's a mix of both tall and short plants (3 tall to 1 short ratio).
Question 3: Mendel called the observed trait in F₁ the
dominant trait, and the trait that seemed to disappear was called the
recessive trait.
Question 4:
- Phenotype of F₁: All tall plants
- Genotype of F₁: All heterozygous (Tt) - they have one allele from each parent
Question 5: The trait for shortness seems to "skip a generation" because it's recessive. In the F₁ generation, all plants have one dominant allele (T) which masks the recessive allele (t). The short trait only appears in F₂ when an offspring receives two recessive alleles (tt) - one from each heterozygous parent.
---
Question 6: Dogs - Wire-haired (W) dominant over smooth hair (w)
Cross: Homozygous wire-haired male (WW) × Female with smooth hair (ww)
Let me create the Punnett square:
| | W | W |
|---|---|---|
| w | Ww | Ww |
| w | Ww | Ww |
Genotypes: All Ww (100% heterozygous)
Phenotypes: All wire-haired (100%)
Ratio: 100% wire-haired or 4:0 or 1:0
---
Question 7: Rabbits - Short hair (L) dominant over long hair (l)
Cross: Two heterozygous rabbits (Ll × Ll)
Let me create the Punnett square:
| | L | l |
|---|---|---|
| L | LL | Ll |
| l | Ll | ll |
Genotypes:
- 1 LL : 2 Ll : 1 ll
- Or: 25% LL, 50% Ll, 25% ll
Phenotypes:
- Short hair (LL and Ll): 3 out of 4 = 75%
- Long hair (ll): 1 out of 4 = 25%
- Ratio: 3 short hair : 1 long hair
Final Answer:
1. Plant height (tall vs. short)
2. F₁: all tall; F₂: mixture of tall and short (3:1 ratio)
3. Dominant and recessive
4. Phenotype: all tall; Genotype: Tt (heterozygous)
5. Because shortness is recessive and requires two recessive alleles (tt), which only occurs in F₂ when both parents contribute the recessive allele
6. Genotypes: all Ww; Phenotypes: all wire-haired; Ratio: 100% wire-haired (or 4:0)
7. Genotypes: 1 LL : 2 Ll : 1 ll; Phenotypes: 3 short hair : 1 long hair
Parent Tip: Review the logic above to help your child master the concept of test cross worksheet.