Worksheet for calculating the perimeter of various polygons by adding side lengths.

To solve the problem of finding the perimeter of each polygon, we need to add up the lengths of all the sides of each shape. Let's go through each shape step by step.

Shape (a): Triangle

- Sides: 6 cm, 8 cm, 10 cm
- Perimeter = \( 6 + 8 + 10 = 24 \) cm

Shape (b): Rhombus

- All sides are equal: 9 m
- Perimeter = \( 9 + 9 + 9 + 9 = 36 \) m

Shape (c): Pentagon

- Sides: 7 in, 7 in, 8 in, 8 in, 8 in
- Perimeter = \( 7 + 7 + 8 + 8 + 8 = 38 \) in

Shape (d): Parallelogram

- Sides: 12 mm, 12 mm, 10 mm, 10 mm
- Perimeter = \( 12 + 12 + 10 + 10 = 44 \) mm

Shape (e): Trapezoid

- Sides: 4 km, 6 km, 2.5 km, 3 km
- Perimeter = \( 4 + 6 + 2.5 + 3 = 15.5 \) km

Shape (f): Hexagon

- Sides: 6 ft, 6 ft, 6 ft, 6 ft, 6 ft, 6 ft
- Perimeter = \( 6 + 6 + 6 + 6 + 6 + 6 = 36 \) ft

Shape (g): Triangle

- Sides: 7 m, 15 m, 10 m
- Perimeter = \( 7 + 15 + 10 = 32 \) m

Shape (h): Rectangle

- Sides: 11 in, 11 in, 9 in, 9 in
- Perimeter = \( 11 + 11 + 9 + 9 = 40 \) in

Shape (i): Hexagon

- Sides: 2 cm, 2 cm, 2 cm, 2 cm, 2 cm, 2 cm
- Perimeter = \( 2 + 2 + 2 + 2 + 2 + 2 = 12 \) cm

Final Answers:

\[
\boxed{
\begin{array}{ll}
\text{(a)} & 24 \text{ cm} \\
\text{(b)} & 36 \text{ m} \\
\text{(c)} & 38 \text{ in} \\
\text{(d)} & 44 \text{ mm} \\
\text{(e)} & 15.5 \text{ km} \\
\text{(f)} & 36 \text{ ft} \\
\text{(g)} & 32 \text{ m} \\
\text{(h)} & 40 \text{ in} \\
\text{(i)} & 12 \text{ cm} \\
\end{array}
}
\]

Each perimeter is calculated by summing the lengths of all the sides of the respective polygon. The units are included as specified in the problem.