Adding and Subtracting Time worksheet - Free Printable

Problem: Adding and Subtracting Hours and Minutes

The task involves adding and subtracting time in hours and minutes. Let's solve each part step by step.

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#### Part 1: Adding the Hours and Minutes

1. 2 h 15 min + 5 h 30 min =
- Add the hours: \( 2 + 5 = 7 \) hours
- Add the minutes: \( 15 + 30 = 45 \) minutes
- Result: \( 7 \text{ h } 45 \text{ min} \)

2. 1 h 45 min + 2 h 10 min =
- Add the hours: \( 1 + 2 = 3 \) hours
- Add the minutes: \( 45 + 10 = 55 \) minutes
- Result: \( 3 \text{ h } 55 \text{ min} \)

3. 3 h 40 min + 1 h 50 min =
- Add the hours: \( 3 + 1 = 4 \) hours
- Add the minutes: \( 40 + 50 = 90 \) minutes
- Since 90 minutes is more than 60, convert 90 minutes to 1 hour and 30 minutes:
- Add 1 hour to the total hours: \( 4 + 1 = 5 \) hours
- Remaining minutes: \( 30 \) minutes
- Result: \( 5 \text{ h } 30 \text{ min} \)

4. 5 h 40 min + 3 h 40 min =
- Add the hours: \( 5 + 3 = 8 \) hours
- Add the minutes: \( 40 + 40 = 80 \) minutes
- Since 80 minutes is more than 60, convert 80 minutes to 1 hour and 20 minutes:
- Add 1 hour to the total hours: \( 8 + 1 = 9 \) hours
- Remaining minutes: \( 20 \) minutes
- Result: \( 9 \text{ h } 20 \text{ min} \)

5. 6 h 15 min + 2 h 45 min =
- Add the hours: \( 6 + 2 = 8 \) hours
- Add the minutes: \( 15 + 45 = 60 \) minutes
- Since 60 minutes is exactly 1 hour, add 1 hour to the total hours:
- Total hours: \( 8 + 1 = 9 \) hours
- Remaining minutes: \( 0 \) minutes
- Result: \( 9 \text{ h } 0 \text{ min} \)

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#### Part 2: Subtracting the Hours and Minutes

1. 12 h 15 min - 4 h 30 min =
- Subtract the hours: \( 12 - 4 = 8 \) hours
- Subtract the minutes: \( 15 - 30 \)
- Since 15 minutes is less than 30 minutes, borrow 1 hour from the hours:
- Convert 1 hour to 60 minutes: \( 8 \text{ h } 75 \text{ min} \)
- Now subtract: \( 75 - 30 = 45 \) minutes
- Remaining hours: \( 8 - 1 = 7 \) hours
- Result: \( 7 \text{ h } 45 \text{ min} \)

2. 11 h 45 min - 2 h 10 min =
- Subtract the hours: \( 11 - 2 = 9 \) hours
- Subtract the minutes: \( 45 - 10 = 35 \) minutes
- Result: \( 9 \text{ h } 35 \text{ min} \)

3. 8 h 40 min - 3 h 50 min =
- Subtract the hours: \( 8 - 3 = 5 \) hours
- Subtract the minutes: \( 40 - 50 \)
- Since 40 minutes is less than 50 minutes, borrow 1 hour from the hours:
- Convert 1 hour to 60 minutes: \( 7 \text{ h } 100 \text{ min} \)
- Now subtract: \( 100 - 50 = 50 \) minutes
- Remaining hours: \( 7 \) hours
- Result: \( 7 \text{ h } 50 \text{ min} \)

4. 9 h 10 min - 5 h 30 min =
- Subtract the hours: \( 9 - 5 = 4 \) hours
- Subtract the minutes: \( 10 - 30 \)
- Since 10 minutes is less than 30 minutes, borrow 1 hour from the hours:
- Convert 1 hour to 60 minutes: \( 8 \text{ h } 70 \text{ min} \)
- Now subtract: \( 70 - 30 = 40 \) minutes
- Remaining hours: \( 8 \) hours
- Result: \( 8 \text{ h } 40 \text{ min} \)

5. 7 h 15 min + 1 h 45 min =
- This is an addition problem, not subtraction. Let's solve it as addition:
- Add the hours: \( 7 + 1 = 8 \) hours
- Add the minutes: \( 15 + 45 = 60 \) minutes
- Since 60 minutes is exactly 1 hour, add 1 hour to the total hours:
- Total hours: \( 8 + 1 = 9 \) hours
- Remaining minutes: \( 0 \) minutes
- Result: \( 9 \text{ h } 0 \text{ min} \)

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Final Answers:

#### Adding:
1. \( 7 \text{ h } 45 \text{ min} \)
2. \( 3 \text{ h } 55 \text{ min} \)
3. \( 5 \text{ h } 30 \text{ min} \)
4. \( 9 \text{ h } 20 \text{ min} \)
5. \( 9 \text{ h } 0 \text{ min} \)

#### Subtracting:
1. \( 7 \text{ h } 45 \text{ min} \)
2. \( 9 \text{ h } 35 \text{ min} \)
3. \( 7 \text{ h } 50 \text{ min} \)
4. \( 8 \text{ h } 40 \text{ min} \)
5. \( 9 \text{ h } 0 \text{ min} \)

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Boxed Final Answer:
\[
\boxed{
\begin{array}{ll}
\text{Adding:} & 1. \, 7 \text{ h } 45 \text{ min}, \, 2. \, 3 \text{ h } 55 \text{ min}, \, 3. \, 5 \text{ h } 30 \text{ min}, \, 4. \, 9 \text{ h } 20 \text{ min}, \, 5. \, 9 \text{ h } 0 \text{ min} \\
\text{Subtracting:} & 1. \, 7 \text{ h } 45 \text{ min}, \, 2. \, 9 \text{ h } 35 \text{ min}, \, 3. \, 7 \text{ h } 50 \text{ min}, \, 4. \, 8 \text{ h } 40 \text{ min}, \, 5. \, 9 \text{ h } 0 \text{ min}
\end{array}
}
\]