Regents Earth Science World Time Zones Worksheet with a world map and time calculation questions.

I'll solve this world time zones worksheet step by step.

First, let me identify the longitude of each location from the map:
- Location A: approximately 75°W (North America - Eastern US/Canada)
- Location B: approximately 0° (Prime Meridian - Europe/Africa)
- Location C: approximately 90°E (Asia)
- Location D: approximately 135°E (Eastern Asia/Japan area)
- Location E: approximately 60°W (South America)
- Location F: approximately 150°E (Australia)
- Location G: approximately 15°E (Africa/Europe)
- Location H: approximately 150°W (Pacific Ocean)

Key rule: 15 degrees of longitude = 1 hour time difference
- Going east → time increases (gets later)
- Going west → time decreases (gets earlier)

Question 1: If it is 9:00 a.m. in location A (75°W), what time is it in other locations?

Location A is at 75°W and the time is 9:00 a.m.

Location E (60°W):
- Difference from A: 75°W to 60°W = 15° eastward
- Time difference: 15° ÷ 15° per hour = 1 hour
- Since E is east of A, time is later: 9:00 a.m. + 1 hour = 10:00 a.m.

Location B (0°):
- Difference from A: 75°W to 0° = 75° eastward
- Time difference: 75° ÷ 15° per hour = 5 hours
- Since B is east of A, time is later: 9:00 a.m. + 5 hours = 2:00 p.m.

Location C (90°E):
- Difference from A: 75°W to 90°E = 75° + 90° = 165° eastward
- Time difference: 165° ÷ 15° per hour = 11 hours
- Since C is east of A, time is later: 9:00 a.m. + 11 hours = 8:00 p.m.

Location G (15°E):
- Difference from A: 75°W to 15°E = 75° + 15° = 90° eastward
- Time difference: 90° ÷ 15° per hour = 6 hours
- Since G is east of A, time is later: 9:00 a.m. + 6 hours = 3:00 p.m.

Question 2: If the time in location F (150°E) is 6:30 p.m., what time is it in other locations?

Location F is at 150°E and the time is 6:30 p.m. (18:30)

Location C (90°E):
- Difference from F: 150°E to 90°E = 60° westward
- Time difference: 60° ÷ 15° per hour = 4 hours
- Since C is west of F, time is earlier: 6:30 p.m. - 4 hours = 2:30 p.m.

Location E (60°W):
- Difference from F: 150°E to 60°W = 150° + 60° = 210° westward
- Time difference: 210° ÷ 15° per hour = 14 hours
- Since E is west of F, time is earlier: 6:30 p.m. - 14 hours = 4:30 a.m.

Location H (150°W):
- Difference from F: 150°E to 150°W = going across the date line
- From 150°E to 180° = 30°, then from 180° to 150°W = 30°, total = 60° eastward OR
- Alternative: 150°E to 150°W westward = 150° + 150° = 300°, but that's more than 180°
- Better approach: The shortest distance is 60° going east (crossing the date line)
- Actually, let me recalculate: From 150°E going west to 150°W: we go 150°E → 180° (30°) → 150°W (another 30°) = 60° total westward
- Wait, that's not right. Let me think again:
- From 150°E to 150°W: if we go west, we cross through 180°. Distance = (180-150) + (180-150) = 30 + 30 = 60°? No...
- Actually: 150°E to 150°W going west = 150°E → 0° → 150°W = 150° + 150° = 300°
- Going east: 150°E → 180° → 150°W = 30° + 30° = 60°
- So the shorter path is 60° eastward
- Time difference: 60° ÷ 15° per hour = 4 hours
- Since H is east of F (via the shorter route crossing the date line), time is later: 6:30 p.m. + 4 hours = 10:30 p.m.

Hmm, but I need to be careful about the date line. Let me reconsider:
- When crossing the International Date Line from west to east (150°E to 150°W going east), you lose a day
- But for time calculation purposes on the same day, we just calculate the time difference
- Actually, for this worksheet, they're probably just asking for the time on the clock, not worrying about the date

Let me verify with another approach for H:
- F is at 150°E, H is at 150°W
- These are on opposite sides of the globe
- Total degrees apart = 360° - (150° + 150°) = 60° via the shorter route
- Or we can say they're 300° apart going the long way
- Using the shorter route: 60° ÷ 15° = 4 hours difference
- From 150°E going east to 150°W crosses the date line, so H would be 4 hours ahead BUT one day behind
- For the time on the clock: 6:30 p.m. + 4 hours = 10:30 p.m.

Actually, I realize I should double-check my understanding. Let me reconsider H:
- If F (150°E) is at 6:30 p.m.
- H (150°W) is on the other side
- Going from 150°E to 150°W eastward crosses the date line
- The time zone difference is 4 hours (60° 15°)
- But when you cross the date line eastward, you subtract a day
- So if it's Tuesday 6:30 p.m. at F, it would be Monday 10:30 p.m. at H
- But since the question just asks for the time (not the date), the answer is 10:30 p.m.

Wait, I need to reconsider this more carefully. Let me use a different reference point.

If F (150°E) is 6:30 p.m.:
- UTC (0°) would be: 150°E is 10 hours ahead of UTC (150÷15=10), so UTC = 6:30 p.m. - 10 hours = 8:30 a.m.
- H (150°W) is 10 hours behind UTC (150÷15=10), so H = 8:30 a.m. - 10 hours = 10:30 p.m. (previous day)

So H = 10:30 p.m. (but on the previous day)

For this worksheet, they likely just want the clock time: 10:30 p.m.

Location D (135°E):
- Difference from F: 150°E to 135°E = 15° westward
- Time difference: 15° ÷ 15° per hour = 1 hour
- Since D is west of F, time is earlier: 6:30 p.m. - 1 hour = 5:30 p.m.

Final Answer:

Question 1: (If it is 9:00 a.m. in location A)
- E: 10:00 a.m.
- B: 2:00 p.m.
- C: 8:00 p.m.
- G: 3:00 p.m.

Question 2: (If it is 6:30 p.m. in location F)
- C: 2:30 p.m.
- E: 4:30 a.m.
- H: 10:30 p.m.
- D: 5:30 p.m.