Visual representation of solution concentration differences in three beakers.

Explanation:
Let’s break this down step by step.

We are given three beakers (A, B, and C) with different amounts of solute (dots) and solvent (liquid volume). The question is about concentration, which is defined as:

> Concentration = amount of solute / volume of solution

So, the more solute per unit volume, the higher the concentration.

Let’s estimate the number of dots (solute particles) and the liquid volume in each beaker.

- Beaker A:
- Dots: Count them — there are 6 dots.
- Volume: The liquid fills about half the beaker (let’s say 50 mL for simplicity, but relative comparison matters more).

- Beaker B:
- Dots: There are 3 dots.
- Volume: Liquid fills about the same height as A — also ~50 mL.

- Beaker C:
- Dots: There are 6 dots (same as A).
- Volume: Liquid fills only about a quarter of the beaker — let’s say ~25 mL.

Now compute relative concentrations:

- A: 6 dots / 50 mL = 0.12 dots/mL
- B: 3 dots / 50 mL = 0.06 dots/mL
- C: 6 dots / 25 mL = 0.24 dots/mL

So:
- C has the highest concentration (0.24),
- A is next (0.12),
- B is lowest (0.06).

Therefore:
- Beaker C > Beaker A > Beaker B in concentration.

The question likely asks: *Which beaker has the highest concentration?* Or to rank them.

Since the task says “Fill in the blanks” and shows three beakers with labels A, B, C, and the instruction says “Circle the beaker with the greatest concentration”, the correct answer is C.

Double-check: Even without exact volumes, visually:
- A and C have same number of dots, but C has less liquid → C is more concentrated.
- B has fewer dots than A, same volume → B is less concentrated than A.

Yes, C is highest.

Final Answer:
C