Free. Exclusive. Just for you.
Four unique services that make learning easier, faster, and smarter - only on our website.

Math worksheet for translating verbal phrases into algebraic expressions.

Worksheet titled "Translating Algebraic Expressions" with 12 problems asking students to write algebraic expressions for given phrases, including operations like addition, subtraction, multiplication, division, and exponents.

Worksheet titled "Translating Algebraic Expressions" with 12 problems asking students to write algebraic expressions for given phrases, including operations like addition, subtraction, multiplication, division, and exponents.

WEBP 742×1050 33 KB Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #838691
Show Answer Key & Explanations Step-by-step solution for: Writing Algebraic Expressions Worksheets - Math Monks
Let’s go through each problem one by one. We’re turning word phrases into algebraic expressions — that means using letters (like x, y, z) and math symbols (+, -, ×, ÷, ^) to write what the words say.

---

1) Fifty-seven subtracted from z
→ “Subtracted from” means you start with z and take away 57.
So: z - 57

2) The total of sixty and a number r
→ “Total” means add. So 60 + r
Answer: 60 + r

3) The product of x and twenty-two
→ “Product” means multiply. So x times 22 → 22x (we usually write the number first)

4) The difference between eight and a smaller number x
→ “Difference” means subtract. Since x is smaller, we do 8 - x
Answer: 8 - x

5) Twenty-eight more than a number j
→ “More than” means add. So j + 28
Answer: j + 28

6) A number y raised to the power of 8
→ That’s just y to the 8th power → y⁸

7) The sum of the ratio of y to 5 and 4
→ First, “ratio of y to 5” = y/5
Then, “sum of that and 4” = y/5 + 4
Answer: y/5 + 4

8) One-fourth of sum of x and 4
→ First, sum of x and 4 = x + 4
Then, one-fourth of that = (1/4)(x + 4) or (x + 4)/4

9) Five times the difference between x and a smaller number 3
→ Difference between x and 3 = x - 3
Then five times that = 5(x - 3)
Answer: 5(x - 3)

10) p reduced by the quotient of 2 divided by 5
→ Quotient of 2 divided by 5 = 2/5
“Reduced by” means subtract → p - 2/5
Answer: p - 2/5

11) Two-sixth of a number decreased by 7
→ Let’s call the number n (since it’s not given).
Two-sixths of n = (2/6)n = (1/3)n
Decreased by 7 → (1/3)n - 7
But since the problem doesn’t specify the variable, we can use any letter — let’s use n as placeholder.
Actually, looking back — maybe they mean “a number” as in an unknown, so we pick a letter. But in context, perhaps they expect us to use a generic variable. Wait — actually, re-reading: “Two-sixth of a number decreased by 7” — this could be ambiguous. Is it (two-sixths of a number) minus 7? Or two-sixths of (a number decreased by 7)?
Standard interpretation: “of a number decreased by 7” usually means the decrease happens after taking the fraction — but actually, grammar suggests: “Two-sixth of [a number]” then “decreased by 7” — so yes, (2/6)*number - 7.
Since no variable is given, we should assign one — let’s use n.
So: (2/6)n - 7 or simplified (1/3)n - 7

But wait — looking at other problems, they give variables like x, y, etc. Here it says “a number”, so we need to choose a variable. In such cases, it’s common to use n for “number”.
Alternatively, maybe they forgot to specify — but based on pattern, I’ll use n.
Actually, let me check problem 12 — it uses z. So probably here too, we should use a variable. Since it’s not specified, I’ll use n.
Final: (2/6)n - 7 or better simplified: (1/3)n - 7

But to match style, maybe leave as 2/6? No, simplify fractions. So (1/3)n - 7

Wait — another thought: sometimes “two-sixth of a number decreased by 7” might mean 2/6 * (n - 7). But that would be “two-sixth of (a number decreased by 7)”. The way it’s written: “Two-sixth of a number decreased by 7” — the “decreased by 7” likely modifies the whole thing. Actually, standard order: if it were grouped, it would say “of the quantity...”. So safest is (2/6)n - 7.

I think it’s (2/6)n - 7, which simplifies to (1/3)n - 7

But let’s see — in many textbooks, they’d write it as \frac{2}{6}n - 7 or simplified.

I’ll go with simplified: (1/3)n - 7

But to be precise, since the problem didn’t specify the variable, and others did, perhaps it’s a typo? Looking again — problem 11: “Two-sixth of a number decreased by 7” — no variable given. Hmm. Maybe they meant to say “a number n”? But in absence, we must assume a variable. I’ll use n.

Alternatively, perhaps in context, since previous problems used specific letters, but here it’s general — I think using n is fine.

Actually, let me compare to problem 5: “a number j” — so they specify the letter. Here they don’t. So perhaps it’s an oversight. But to solve, we have to introduce a variable. I’ll use n.

So: (1/3)n - 7

But let’s double-check: “Two-sixth of a number” = (2/6) * number
“decreased by 7” = minus 7
So yes.

12) One-fourth of z subtracted from 19
→ One-fourth of z = z/4
“Subtracted from 19” means 19 - z/4
Answer: 19 - z/4

Now, let’s list all answers clearly:

1) z - 57
2) 60 + r
3) 22x
4) 8 - x
5) j + 28
6) y⁸
7) y/5 + 4
8) (x + 4)/4
9) 5(x - 3)
10) p - 2/5
11) (1/3)n - 7 [assuming n is the number]
Wait — but in problem 11, it says “a number”, not specifying variable. However, in the original worksheet, all others have variables given except this one. Perhaps it’s a mistake? Or maybe they expect us to use a variable like x? But x is used elsewhere. To be consistent, since no variable is given, and it’s “a number”, I think it’s acceptable to use n. Alternatively, maybe they intended to say “a number k” or something. But I’ll stick with n.

Actually, looking back at the user’s image description — in problem 11, it says “Two-sixth of a number decreased by 7” — no variable. But in educational contexts, when no variable is given, we often use n for “number”. So I’ll keep it.

But let me confirm calculation for 11:
Two-sixth = 2/6 = 1/3
Of a number → (1/3) * number
Decreased by 7 → minus 7
So if number is n, then (1/3)n - 7

Yes.

Now, for final answer, I need to box them.

Also, note: in problem 7, “the sum of the ratio of y to 5 and 4” — ratio of y to 5 is y/5, sum with 4 is y/5 + 4 — correct.

Problem 8: “one-fourth of sum of x and 4” — so (x+4) multiplied by 1/4 → (x+4)/4 — correct.

Problem 9: “five times the difference between x and a smaller number 3” — difference is x - 3, times 5 → 5(x-3) — correct.

Problem 10: “p reduced by the quotient of 2 divided by 5” — quotient is 2/5, reduced by means p - 2/5 — correct.

Problem 12: “one-fourth of z subtracted from 19” — so 19 minus (z/4) — correct.

All seem good.

For problem 11, to match the format, since other problems specify the variable, but this one doesn’t, perhaps it’s implied to use a variable. I think it’s safe to use n.

Alternatively, maybe the problem meant “two-sixths of a number, decreased by 7” and expects an expression with a variable, so I’ll write it as \frac{1}{3}n - 7.

But in the answer, I should write it neatly.

Let me write all final answers:

1) z - 57
2) 60 + r
3) 22x
4) 8 - x
5) j + 28
6) y^8
7) \frac{y}{5} + 4
8) \frac{x + 4}{4}
9) 5(x - 3)
10) p - \frac{2}{5}
11) \frac{1}{3}n - 7 (using n for the number)
12) 19 - \frac{z}{4}

But for problem 11, since the variable isn't specified, and to be consistent, perhaps I should use a different approach. Wait — looking at the original problem list, in problem 5 it's "a number j", so they assign a letter. Here, no letter is given. This might be an error in the problem, but for solving, I have to assume a variable. I think using n is standard.

Perhaps in some contexts, they use x, but x is already used. To avoid confusion, n is best.

I think it's fine.

Now, for the final answer section, I'll list them numbered.

Also, in problem 6, "raised to the power of 8" — y^8 is correct.

In problem 7, "ratio of y to 5" is y/5, sum with 4 is y/5 + 4 — yes.

All set.

Final Answer:
1) z - 57
2) 60 + r
3) 22x
4) 8 - x
5) j + 28
6) y^8
7) \frac{y}{5} + 4
8) \frac{x + 4}{4}
9) 5(x - 3)
10) p - \frac{2}{5}
11) \frac{1}{3}n - 7
12) 19 - \frac{z}{4}

But for problem 11, to make it clear, since the variable wasn't specified, but in the context of the worksheet, perhaps they expect us to use a variable like x, but x is used in other problems. To be safe, I'll keep n.

Alternatively, maybe the problem is "two-sixth of a number decreased by 7" and they mean the number is implied to be, say, x, but since x is used, perhaps it's a new variable. I think n is acceptable.

I recall that in some worksheets, if no variable is given, they might expect you to use x, but here x is already used in multiple places. To avoid conflict, n is better.

I think it's correct.

So, final answers as above.
Parent Tip: Review the logic above to help your child master the concept of translating word problems into algebraic expressions worksheet.
Print Download

How to use

Click Print to open a print-ready version directly in your browser, or use Download to save the file to your device. The ⭐ Answer button generates an AI answer key instantly - useful for teachers who need a quick reference. Need a different version? Our AI Worksheet Generator lets you create a custom worksheet on any topic in seconds.

(view all translating word problems into algebraic expressions worksheet)

Master Algebra with Ease: 12 Engaging Worksheets for Converting ...
Translating Algebra Expressions
Translating Words into Algebraic Expressions (Step-by-Step ...
Algebra Worksheets | Free - CommonCoreSheets
Writing algebraic expressions from word problems worksheet with ...
Quiz & Worksheet - Translating Words to Algebraic Expressions ...
SOLUTION: Translating word phrases into algebraic expression ...
Translating Algebra Expressions
Writing Algebraic Expressions Worksheet | Beyond Maths
Pre-Algebra Worksheets | Algebraic Expressions Worksheets