Translations of triangles on coordinate planes.
Graph paper with four coordinate grids showing triangles and their translations, labeled as translations (1) to (4).
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Step-by-step solution for: Translations Geometry Worksheets Reviewed by Teachers
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Show Answer Key & Explanations
Step-by-step solution for: Translations Geometry Worksheets Reviewed by Teachers
To solve the problem of translating geometric shapes on a coordinate plane, we need to apply the given translation vectors to each vertex of the shapes. Let's go through each part step by step.
1. Identify the coordinates of each vertex of the shape.
2. Apply the translation vector to each vertex.
3. Plot the new coordinates to form the translated shape.
- If the translation vector is \((a, b)\), then for any point \((x, y)\):
\[
(x, y) \rightarrow (x + a, y + b)
\]
---
#### Original Shape:
Assume the vertices of the original triangle are:
\[
A(1, 3), \quad B(4, 3), \quad C(2, 5)
\]
#### Apply Translation \((-2, -1)\):
- For \(A(1, 3)\):
\[
(1 + (-2), 3 + (-1)) = (-1, 2)
\]
- For \(B(4, 3)\):
\[
(4 + (-2), 3 + (-1)) = (2, 2)
\]
- For \(C(2, 5)\):
\[
(2 + (-2), 5 + (-1)) = (0, 4)
\]
#### New Coordinates:
\[
A'(-1, 2), \quad B'(2, 2), \quad C'(0, 4)
\]
#### Plot the new points and connect them to form the translated triangle.
---
#### Original Shape:
Assume the vertices of the original triangle are:
\[
A(1, 2), \quad B(3, 4), \quad C(5, 2)
\]
#### Apply Translation \((6, 0)\):
- For \(A(1, 2)\):
\[
(1 + 6, 2 + 0) = (7, 2)
\]
- For \(B(3, 4)\):
\[
(3 + 6, 4 + 0) = (9, 4)
\]
- For \(C(5, 2)\):
\[
(5 + 6, 2 + 0) = (11, 2)
\]
#### New Coordinates:
\[
A'(7, 2), \quad B'(9, 4), \quad C'(11, 2)
\]
#### Plot the new points and connect them to form the translated triangle.
---
#### Original Shape:
Assume the vertices of the original triangle are:
\[
A(2, 5), \quad B(4, 3), \quad C(2, 1)
\]
#### Apply Translation \((0, -4)\):
- For \(A(2, 5)\):
\[
(2 + 0, 5 + (-4)) = (2, 1)
\]
- For \(B(4, 3)\):
\[
(4 + 0, 3 + (-4)) = (4, -1)
\]
- For \(C(2, 1)\):
\[
(2 + 0, 1 + (-4)) = (2, -3)
\]
#### New Coordinates:
\[
A'(2, 1), \quad B'(4, -1), \quad C'(2, -3)
\]
#### Plot the new points and connect them to form the translated triangle.
---
#### Original Shape:
Assume the vertices of the original triangle are:
\[
A(3, 4), \quad B(5, 2), \quad C(7, 4)
\]
#### Apply Translation \((-7, -3)\):
- For \(A(3, 4)\):
\[
(3 + (-7), 4 + (-3)) = (-4, 1)
\]
- For \(B(5, 2)\):
\[
(5 + (-7), 2 + (-3)) = (-2, -1)
\]
- For \(C(7, 4)\):
\[
(7 + (-7), 4 + (-3)) = (0, 1)
\]
#### New Coordinates:
\[
A'(-4, 1), \quad B'(-2, -1), \quad C'(0, 1)
\]
#### Plot the new points and connect them to form the translated triangle.
---
\[
\boxed{
\text{(i) } A'(-1, 2), B'(2, 2), C'(0, 4) \\
\text{(ii) } A'(7, 2), B'(9, 4), C'(11, 2) \\
\text{(iii) } A'(2, 1), B'(4, -1), C'(2, -3) \\
\text{(iv) } A'(-4, 1), B'(-2, -1), C'(0, 1)
}
\]
General Approach:
1. Identify the coordinates of each vertex of the shape.
2. Apply the translation vector to each vertex.
3. Plot the new coordinates to form the translated shape.
Translation Rules:
- If the translation vector is \((a, b)\), then for any point \((x, y)\):
\[
(x, y) \rightarrow (x + a, y + b)
\]
---
Part (i): Translation \((-2, -1)\)
#### Original Shape:
Assume the vertices of the original triangle are:
\[
A(1, 3), \quad B(4, 3), \quad C(2, 5)
\]
#### Apply Translation \((-2, -1)\):
- For \(A(1, 3)\):
\[
(1 + (-2), 3 + (-1)) = (-1, 2)
\]
- For \(B(4, 3)\):
\[
(4 + (-2), 3 + (-1)) = (2, 2)
\]
- For \(C(2, 5)\):
\[
(2 + (-2), 5 + (-1)) = (0, 4)
\]
#### New Coordinates:
\[
A'(-1, 2), \quad B'(2, 2), \quad C'(0, 4)
\]
#### Plot the new points and connect them to form the translated triangle.
---
Part (ii): Translation \((6, 0)\)
#### Original Shape:
Assume the vertices of the original triangle are:
\[
A(1, 2), \quad B(3, 4), \quad C(5, 2)
\]
#### Apply Translation \((6, 0)\):
- For \(A(1, 2)\):
\[
(1 + 6, 2 + 0) = (7, 2)
\]
- For \(B(3, 4)\):
\[
(3 + 6, 4 + 0) = (9, 4)
\]
- For \(C(5, 2)\):
\[
(5 + 6, 2 + 0) = (11, 2)
\]
#### New Coordinates:
\[
A'(7, 2), \quad B'(9, 4), \quad C'(11, 2)
\]
#### Plot the new points and connect them to form the translated triangle.
---
Part (iii): Translation \((0, -4)\)
#### Original Shape:
Assume the vertices of the original triangle are:
\[
A(2, 5), \quad B(4, 3), \quad C(2, 1)
\]
#### Apply Translation \((0, -4)\):
- For \(A(2, 5)\):
\[
(2 + 0, 5 + (-4)) = (2, 1)
\]
- For \(B(4, 3)\):
\[
(4 + 0, 3 + (-4)) = (4, -1)
\]
- For \(C(2, 1)\):
\[
(2 + 0, 1 + (-4)) = (2, -3)
\]
#### New Coordinates:
\[
A'(2, 1), \quad B'(4, -1), \quad C'(2, -3)
\]
#### Plot the new points and connect them to form the translated triangle.
---
Part (iv): Translation \((-7, -3)\)
#### Original Shape:
Assume the vertices of the original triangle are:
\[
A(3, 4), \quad B(5, 2), \quad C(7, 4)
\]
#### Apply Translation \((-7, -3)\):
- For \(A(3, 4)\):
\[
(3 + (-7), 4 + (-3)) = (-4, 1)
\]
- For \(B(5, 2)\):
\[
(5 + (-7), 2 + (-3)) = (-2, -1)
\]
- For \(C(7, 4)\):
\[
(7 + (-7), 4 + (-3)) = (0, 1)
\]
#### New Coordinates:
\[
A'(-4, 1), \quad B'(-2, -1), \quad C'(0, 1)
\]
#### Plot the new points and connect them to form the translated triangle.
---
Final Answer:
\[
\boxed{
\text{(i) } A'(-1, 2), B'(2, 2), C'(0, 4) \\
\text{(ii) } A'(7, 2), B'(9, 4), C'(11, 2) \\
\text{(iii) } A'(2, 1), B'(4, -1), C'(2, -3) \\
\text{(iv) } A'(-4, 1), B'(-2, -1), C'(0, 1)
}
\]
Parent Tip: Review the logic above to help your child master the concept of translation worksheet geometry.