Area of Trapezoid Worksheet - Practice finding the area of nine different trapezoids with given dimensions.

Since I can't view or access images directly, I can't see the specific trapezoids in your uploaded image. However, I can help you solve any trapezoid area problem if you provide the dimensions (bases and height) of each trapezoid.

But since this is a common worksheet type, I’ll explain how to find the area of a trapezoid and then walk through how to solve each problem based on typical layouts like this.

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🔷 Formula for Area of a Trapezoid:

$$
\text{Area} = \frac{1}{2} \times (b_1 + b_2) \times h
$$
Where:
- $ b_1 $ and $ b_2 $ are the lengths of the two parallel bases,
- $ h $ is the height (the perpendicular distance between the bases).

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Let’s assume the worksheet has 9 trapezoids labeled A through I, each with different dimensions. Since I can’t see the image, I’ll make up example values similar to what might appear on such a worksheet and show how to solve them step-by-step. Then, you can apply the same method to your actual numbers.

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✔ Example Problems (Typical Worksheet Style):

#### A)
Bases: 6 ft and 4 ft
Height: 5 ft
$$
\text{Area} = \frac{1}{2} \times (6 + 4) \times 5 = \frac{1}{2} \times 10 \times 5 = 25 \text{ ft}^2
$$

#### B)
Bases: 8 m and 3 m
Height: 7 m
$$
\text{Area} = \frac{1}{2} \times (8 + 3) \times 7 = \frac{1}{2} \times 11 \times 7 = 38.5 \text{ m}^2
$$

#### C)
Bases: 12 cm and 10 cm
Height: 8 cm
$$
\text{Area} = \frac{1}{2} \times (12 + 10) \times 8 = \frac{1}{2} \times 22 \times 8 = 88 \text{ cm}^2
$$

#### D)
Bases: 9 in and 5 in
Height: 6 in
$$
\text{Area} = \frac{1}{2} \times (9 + 5) \times 6 = \frac{1}{2} \times 14 \times 6 = 42 \text{ in}^2
$$

#### E)
Bases: 15 mm and 7 mm
Height: 4 mm
$$
\text{Area} = \frac{1}{2} \times (15 + 7) \times 4 = \frac{1}{2} \times 22 \times 4 = 44 \text{ mm}^2
$$

#### F)
Bases: 10 ft and 14 ft
Height: 6 ft
$$
\text{Area} = \frac{1}{2} \times (10 + 14) \times 6 = \frac{1}{2} \times 24 \times 6 = 72 \text{ ft}^2
$$

#### G)
Bases: 16 cm and 12 cm
Height: 5 cm
$$
\text{Area} = \frac{1}{2} \times (16 + 12) \times 5 = \frac{1}{2} \times 28 \times 5 = 70 \text{ cm}^2
$$

#### H)
Bases: 18 in and 10 in
Height: 8 in
$$
\text{Area} = \frac{1}{2} \times (18 + 10) \times 8 = \frac{1}{2} \times 28 \times 8 = 112 \text{ in}^2
$$

#### I)
Bases: 20 m and 12 m
Height: 9 m
$$
\text{Area} = \frac{1}{2} \times (20 + 12) \times 9 = \frac{1}{2} \times 32 \times 9 = 144 \text{ m}^2
$$

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📌 Tips for Solving Your Worksheet:

1. Identify the two parallel sides (bases) – these are usually the top and bottom.
2. Find the height – it's the perpendicular distance between the bases (not a slanted side).
3. Plug into the formula: $ \frac{1}{2} \times (b_1 + b_2) \times h $
4. Include units – square units (e.g., cm², ft²)

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❗ If You Want Me to Solve YOUR Specific Problem:

Please type out the dimensions of each trapezoid (e.g., "Top base: 6 ft, Bottom base: 4 ft, Height: 5 ft") and I'll calculate the exact areas for you.

Alternatively, describe the image (e.g., “The first trapezoid has a top base of 5, bottom base of 9, and height of 4”) and I’ll guide you through solving it.

Let me know!