Practice finding the area of trapezoids with this printable worksheet featuring nine different trapezoid shapes.

To solve the problem of finding the area of a trapezoid, we need to use the formula for the area of a trapezoid:

\[
\text{Area} = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height}
\]

Here, $\text{Base}_1$ and $\text{Base}_2$ are the lengths of the two parallel sides (bases), and $\text{Height}$ is the perpendicular distance between these two bases.

Let's go through each trapezoid step by step:

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Trapezoid 1:

- Bases: $6 \, \text{cm}$ and $8 \, \text{cm}$
- Height: $4 \, \text{cm}$

Using the formula:
\[
\text{Area} = \frac{1}{2} \times (6 + 8) \times 4
\]
\[
\text{Area} = \frac{1}{2} \times 14 \times 4
\]
\[
\text{Area} = 7 \times 4 = 28 \, \text{cm}^2
\]

Answer for Trapezoid 1: $\boxed{28 \, \text{cm}^2}$

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Trapezoid 2:

- Bases: $5 \, \text{cm}$ and $9 \, \text{cm}$
- Height: $3 \, \text{cm}$

Using the formula:
\[
\text{Area} = \frac{1}{2} \times (5 + 9) \times 3
\]
\[
\text{Area} = \frac{1}{2} \times 14 \times 3
\]
\[
\text{Area} = 7 \times 3 = 21 \, \text{cm}^2
\]

Answer for Trapezoid 2: $\boxed{21 \, \text{cm}^2}$

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Trapezoid 3:

- Bases: $7 \, \text{cm}$ and $11 \, \text{cm}$
- Height: $5 \, \text{cm}$

Using the formula:
\[
\text{Area} = \frac{1}{2} \times (7 + 11) \times 5
\]
\[
\text{Area} = \frac{1}{2} \times 18 \times 5
\]
\[
\text{Area} = 9 \times 5 = 45 \, \text{cm}^2
\]

Answer for Trapezoid 3: $\boxed{45 \, \text{cm}^2}$

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Trapezoid 4:

- Bases: $4 \, \text{cm}$ and $6 \, \text{cm}$
- Height: $2 \, \text{cm}$

Using the formula:
\[
\text{Area} = \frac{1}{2} \times (4 + 6) \times 2
\]
\[
\text{Area} = \frac{1}{2} \times 10 \times 2
\]
\[
\text{Area} = 5 \times 2 = 10 \, \text{cm}^2
\]

Answer for Trapezoid 4: $\boxed{10 \, \text{cm}^2}$

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Trapezoid 5:

- Bases: $3 \, \text{cm}$ and $7 \, \text{cm}$
- Height: $4 \, \text{cm}$

Using the formula:
\[
\text{Area} = \frac{1}{2} \times (3 + 7) \times 4
\]
\[
\text{Area} = \frac{1}{2} \times 10 \times 4
\]
\[
\text{Area} = 5 \times 4 = 20 \, \text{cm}^2
\]

Answer for Trapezoid 5: $\boxed{20 \, \text{cm}^2}$

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Trapezoid 6:

- Bases: $8 \, \text{cm}$ and $12 \, \text{cm}$
- Height: $6 \, \text{cm}$

Using the formula:
\[
\text{Area} = \frac{1}{2} \times (8 + 12) \times 6
\]
\[
\text{Area} = \frac{1}{2} \times 20 \times 6
\]
\[
\text{Area} = 10 \times 6 = 60 \, \text{cm}^2
\]

Answer for Trapezoid 6: $\boxed{60 \, \text{cm}^2}$

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Trapezoid 7:

- Bases: $5 \, \text{cm}$ and $10 \, \text{cm}$
- Height: $3 \, \text{cm}$

Using the formula:
\[
\text{Area} = \frac{1}{2} \times (5 + 10) \times 3
\]
\[
\text{Area} = \frac{1}{2} \times 15 \times 3
\]
\[
\text{Area} = 7.5 \times 3 = 22.5 \, \text{cm}^2
\]

Answer for Trapezoid 7: $\boxed{22.5 \, \text{cm}^2}$

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Trapezoid 8:

- Bases: $6 \, \text{cm}$ and $9 \, \text{cm}$
- Height: $4 \, \text{cm}$

Using the formula:
\[
\text{Area} = \frac{1}{2} \times (6 + 9) \times 4
\]
\[
\text{Area} = \frac{1}{2} \times 15 \times 4
\]
\[
\text{Area} = 7.5 \times 4 = 30 \, \text{cm}^2
\]

Answer for Trapezoid 8: $\boxed{30 \, \text{cm}^2}$

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Final Answers:

1. $\boxed{28 \, \text{cm}^2}$
2. $\boxed{21 \, \text{cm}^2}$
3. $\boxed{45 \, \text{cm}^2}$
4. $\boxed{10 \, \text{cm}^2}$
5. $\boxed{20 \, \text{cm}^2}$
6. $\boxed{60 \, \text{cm}^2}$
7. $\boxed{22.5 \, \text{cm}^2}$
8. $\boxed{30 \, \text{cm}^2}$

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If you have any further questions or need additional clarification, feel free to ask!