Practice worksheet for calculating the area of trapezoids with nine problems.

To find the area of each trapezoid, we use the formula:

> Area = ½ × (base₁ + base₂) × height

Where:
- base₁ and base₂ are the two parallel sides (the top and bottom of the trapezoid)
- height is the perpendicular distance between those bases

We’ll go one by one.

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Problem 1:
Top = 4 cm, Bottom = 7 cm, Height = 4 cm
Area = ½ × (4 + 7) × 4 = ½ × 11 × 4 = 5.5 × 4 = 22 cm²

Problem 2:
Top = 11 yd, Bottom = 9 yd, Height = 3 yd
Area = ½ × (11 + 9) × 3 = ½ × 20 × 3 = 10 × 3 = 30 yd²

Problem 3:
Top = 2 ft, Bottom = 5 ft, Height = 3 ft
Area = ½ × (2 + 5) × 3 = ½ × 7 × 3 = 3.5 × 3 = 10.5 ft²

Problem 4:
Left side = 8 in, Right side = 3 in, Height (horizontal) = 6 in
→ This is a sideways trapezoid. The “bases” are the vertical sides: 8 in and 3 in. The height is the horizontal distance between them: 6 in.
Area = ½ × (8 + 3) × 6 = ½ × 11 × 6 = 5.5 × 6 = 33 in²

Problem 5:
Top = 10 m, Bottom = 15 m, Height = 3 m
Area = ½ × (10 + 15) × 3 = ½ × 25 × 3 = 12.5 × 3 = 37.5 m²

Problem 6:
Top = 7 cm, Bottom = 10 cm, Height = 6 cm
Area = ½ × (7 + 10) × 6 = ½ × 17 × 6 = 8.5 × 6 = 51 cm²

Problem 7:
Left = 8 ft, Right = 12 ft, Height (horizontal) = 10 ft
→ Again, sideways trapezoid. Bases are 8 ft and 12 ft, height is 10 ft.
Area = ½ × (8 + 12) × 10 = ½ × 20 × 10 = 10 × 10 = 100 ft²

Problem 8:
Top = 12 m, Bottom = 6 m, Height = 5 m
Area = ½ × (12 + 6) × 5 = ½ × 18 × 5 = 9 × 5 = 45 m²

Problem 9:
Left = 11 yd, Right = 9 yd, Height (horizontal) = 10 yd
→ Sideways trapezoid. Bases are 11 yd and 9 yd, height is 10 yd.
Area = ½ × (11 + 9) × 10 = ½ × 20 × 10 = 10 × 10 = 100 yd²

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Final Answer:
1. 22 cm²
2. 30 yd²
3. 10.5 ft²
4. 33 in²
5. 37.5 m²
6. 51 cm²
7. 100 ft²
8. 45 m²
9. 100 yd²