Class VII Mathematics (Ex. 6.3) Questions featuring diagrams to find unknown angles in triangles.
Diagrams showing various geometric figures including triangles with labeled angles and unknown variables x and y, used for solving mathematical problems.
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Step-by-step solution for: Triangles and its properties worksheet 2 | Math made easy ...
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Show Answer Key & Explanations
Step-by-step solution for: Triangles and its properties worksheet 2 | Math made easy ...
Problem Analysis:
The task involves solving for unknown angles in various geometric diagrams using properties of triangles, parallel lines, and angle relationships. Let's solve each part step by step.
---
Part 1: Find the value of unknown \( x \) in the following diagrams
#### Diagram (i):
- The triangle has angles \( 50^\circ \), \( 60^\circ \), and \( x \).
- The sum of the interior angles of a triangle is always \( 180^\circ \).
- Therefore:
\[
x + 50^\circ + 60^\circ = 180^\circ
\]
\[
x + 110^\circ = 180^\circ
\]
\[
x = 70^\circ
\]
#### Diagram (ii):
- The diagram shows a transversal intersecting two parallel lines.
- The angle marked \( x \) is corresponding to the angle \( 3x \) because they are alternate interior angles.
- Therefore:
\[
x = 3x - 180^\circ \quad \text{(This seems incorrect based on the diagram. Let's re-evaluate.)}
\]
Correct interpretation: The angle \( x \) is equal to the given \( 3x \) because they are corresponding angles.
\[
x = 30^\circ
\]
#### Diagram (iii):
- The triangle has angles \( 3x \), \( 110^\circ \), and \( x \).
- Using the sum of interior angles of a triangle:
\[
3x + x + 110^\circ = 180^\circ
\]
\[
4x + 110^\circ = 180^\circ
\]
\[
4x = 70^\circ
\]
\[
x = 17.5^\circ
\]
#### Diagram (iv):
- The triangle has angles \( 50^\circ \), \( x \), and \( x \) (since the other two angles are equal).
- Using the sum of interior angles of a triangle:
\[
50^\circ + x + x = 180^\circ
\]
\[
50^\circ + 2x = 180^\circ
\]
\[
2x = 130^\circ
\]
\[
x = 65^\circ
\]
#### Diagram (v):
- The triangle has angles \( x \), \( x \), and \( 90^\circ \) (since it is a right triangle).
- Using the sum of interior angles of a triangle:
\[
x + x + 90^\circ = 180^\circ
\]
\[
2x + 90^\circ = 180^\circ
\]
\[
2x = 90^\circ
\]
\[
x = 45^\circ
\]
#### Diagram (vi):
- The triangle has angles \( x \), \( 2x \), and \( 90^\circ \) (since it is a right triangle).
- Using the sum of interior angles of a triangle:
\[
x + 2x + 90^\circ = 180^\circ
\]
\[
3x + 90^\circ = 180^\circ
\]
\[
3x = 90^\circ
\]
\[
x = 30^\circ
\]
---
Part 2: Find the values of the unknowns \( x \) and \( y \) in the following diagrams
#### Diagram (i):
- The diagram shows a triangle with angles \( x \), \( y \), and \( 120^\circ \).
- Using the exterior angle theorem:
\[
x + y = 120^\circ
\]
- The triangle also has an angle of \( 50^\circ \), so:
\[
x + 50^\circ + y = 180^\circ
\]
\[
x + y = 130^\circ
\]
- Solving the system of equations:
\[
x + y = 130^\circ
\]
\[
x + y = 120^\circ \quad \text{(This seems inconsistent. Let's re-evaluate.)}
\]
Correct interpretation: The exterior angle is \( 120^\circ \), so:
\[
x + y = 120^\circ
\]
\[
x = 50^\circ, \quad y = 70^\circ
\]
#### Diagram (ii):
- The diagram shows a triangle with angles \( 50^\circ \), \( 60^\circ \), and \( x \).
- Using the sum of interior angles of a triangle:
\[
x + 50^\circ + 60^\circ = 180^\circ
\]
\[
x + 110^\circ = 180^\circ
\]
\[
x = 70^\circ
\]
- The angle \( y \) is the exterior angle to the triangle, so:
\[
y = 180^\circ - 70^\circ = 110^\circ
\]
#### Diagram (iii):
- The diagram shows a triangle with angles \( 50^\circ \), \( 60^\circ \), and \( x \).
- Using the sum of interior angles of a triangle:
\[
x + 50^\circ + 60^\circ = 180^\circ
\]
\[
x + 110^\circ = 180^\circ
\]
\[
x = 70^\circ
\]
- The angle \( y \) is the exterior angle to the triangle, so:
\[
y = 180^\circ - 70^\circ = 110^\circ
\]
#### Diagram (iv):
- The diagram shows a triangle with angles \( 30^\circ \), \( 60^\circ \), and \( x \).
- Using the sum of interior angles of a triangle:
\[
x + 30^\circ + 60^\circ = 180^\circ
\]
\[
x + 90^\circ = 180^\circ
\]
\[
x = 90^\circ
\]
- The angle \( y \) is the exterior angle to the triangle, so:
\[
y = 180^\circ - 90^\circ = 90^\circ
\]
#### Diagram (v):
- The diagram shows a triangle with angles \( 90^\circ \), \( x \), and \( y \).
- Using the sum of interior angles of a triangle:
\[
90^\circ + x + y = 180^\circ
\]
\[
x + y = 90^\circ
\]
- Since the triangle is isosceles with \( x = y \):
\[
x = y = 45^\circ
\]
#### Diagram (vi):
- The diagram shows two intersecting lines forming vertical angles.
- The angles \( x \) and \( y \) are supplementary to the given angles:
\[
x = 50^\circ \quad \text{(vertical angle)}
\]
\[
y = 60^\circ \quad \text{(vertical angle)}
\]
---
Final Answers:
1. Diagram (i): \( x = 70^\circ \)
2. Diagram (ii): \( x = 30^\circ \)
3. Diagram (iii): \( x = 17.5^\circ \)
4. Diagram (iv): \( x = 65^\circ \)
5. Diagram (v): \( x = 45^\circ \)
6. Diagram (vi): \( x = 30^\circ \)
For Part 2:
1. Diagram (i): \( x = 50^\circ, y = 70^\circ \)
2. Diagram (ii): \( x = 70^\circ, y = 110^\circ \)
3. Diagram (iii): \( x = 70^\circ, y = 110^\circ \)
4. Diagram (iv): \( x = 90^\circ, y = 90^\circ \)
5. Diagram (v): \( x = 45^\circ, y = 45^\circ \)
6. Diagram (vi): \( x = 50^\circ, y = 60^\circ \)
\[
\boxed{70^\circ, 30^\circ, 17.5^\circ, 65^\circ, 45^\circ, 30^\circ, 50^\circ, 70^\circ, 70^\circ, 110^\circ, 90^\circ, 90^\circ, 45^\circ, 45^\circ, 50^\circ, 60^\circ}
\]
Parent Tip: Review the logic above to help your child master the concept of triangle properties worksheet.