Find the value of "x" in each triangle using angle sum properties and algebra.
A worksheet with 12 geometry problems asking to find the value of "x" in various triangles, including angles in degrees and algebraic expressions.
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Step-by-step solution for: triangle sum and exterior angle theorem. find the x please help i ...
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Show Answer Key & Explanations
Step-by-step solution for: triangle sum and exterior angle theorem. find the x please help i ...
Let's solve each of these triangle angle problems step by step. The key concept we'll use is:
> The sum of the interior angles in any triangle is always 180°.
We’ll go through each problem one at a time.
---
Triangle with angles: 58°, 47°, and $ x^\circ $
$$
x = 180^\circ - 58^\circ - 47^\circ = 180 - 105 = 75^\circ
$$
✔ Answer: $ x = 75 $
---
Angles: $ x^\circ $, 96°, 21°
$$
x = 180 - 96 - 21 = 180 - 117 = 63^\circ
$$
✔ Answer: $ x = 63 $
---
Right triangle (has a right angle), so one angle is 90°, another is 31°, and the third is $ (3x - 1)^\circ $
Sum of angles:
$$
90 + 31 + (3x - 1) = 180 \\
120 + 3x - 1 = 180 \\
119 + 3x = 180 \\
3x = 61 \\
x = \frac{61}{3} \approx 20.33
$$
Wait — let’s double-check.
Actually, the angle labeled $ (3x - 1)^\circ $ is likely one of the non-right angles, and the other is 31°.
So:
$$
90 + 31 + (3x - 1) = 180 \\
120 + 3x - 1 = 180 \\
119 + 3x = 180 \\
3x = 61 \\
x = \frac{61}{3} \approx 20.33
$$
But this gives a fractional value. Let’s check if that makes sense.
Wait — perhaps the labeling is different? Let’s assume the triangle has a right angle (90°), one angle is 31°, and the third is $ (3x - 1)^\circ $. Then yes, it must be:
$$
(3x - 1) = 180 - 90 - 31 = 59^\circ \\
3x - 1 = 59 \\
3x = 60 \\
x = 20
$$
Ah! So $ x = 20 $, and $ 3x - 1 = 59^\circ $, which works.
✔ Answer: $ x = 20 $
---
Angles: $ x^\circ $, 21°, 34°
$$
x = 180 - 21 - 34 = 180 - 55 = 125^\circ
$$
✔ Answer: $ x = 125 $
---
Angles: $ (2x + 3)^\circ $, 100°, 51°
$$
(2x + 3) + 100 + 51 = 180 \\
2x + 154 = 180 \\
2x = 26 \\
x = 13
$$
✔ Answer: $ x = 13 $
---
Angles: $ x^\circ $, 60°, $ 2x^\circ $, and the third angle is 94°?
Wait — triangle has three angles. One is 94°, one is 60°, and the third is $ 2x^\circ $? But label says $ x^\circ $ and $ 2x^\circ $? Wait — look again.
It shows: one angle is 94°, one is 60°, and the third is $ 2x^\circ $. So:
$$
94 + 60 + 2x = 180 \\
154 + 2x = 180 \\
2x = 26 \\
x = 13
$$
✔ Answer: $ x = 13 $
---
Angles: 52°, 43°, $ x^\circ $
$$
x = 180 - 52 - 43 = 180 - 95 = 85^\circ
$$
✔ Answer: $ x = 85 $
---
Angles: $ x^\circ $, $ 3x^\circ $, $ 2x^\circ $
All three angles are expressed in terms of $ x $:
$$
x + 3x + 2x = 180 \\
6x = 180 \\
x = 30
$$
✔ Answer: $ x = 30 $
---
Right triangle (right angle shown), so one angle is 90°.
Other angles: $ (2x - 2)^\circ $, and $ (x + 5)^\circ $
So:
$$
90 + (2x - 2) + (x + 5) = 180 \\
90 + 2x - 2 + x + 5 = 180 \\
(90 - 2 + 5) + 3x = 180 \\
93 + 3x = 180 \\
3x = 87 \\
x = 29
$$
Check:
- $ 2x - 2 = 58 - 2 = 56^\circ $
- $ x + 5 = 34^\circ $
- $ 90 + 56 + 34 = 180 $ ✔
✔ Answer: $ x = 29 $
---
This is not a triangle — it looks like an angle formed by two lines extending from a point, but it's not a triangle. It appears to be a straight line or an external angle.
Wait — it shows two angles: 10° and 23°, and then $ x^\circ $ as the angle between them?
Wait — actually, it looks like a triangle with an exterior angle? Or maybe a straight line?
Looking closely: There’s a triangle-like shape, but it seems like three angles meeting at a point — no, more likely it's a triangle with two known angles on the base, and $ x $ is the top angle.
Wait — the diagram shows a triangle with two base angles: 10° and 23°, and $ x^\circ $ as the vertex angle?
Then:
$$
x = 180 - 10 - 23 = 147^\circ
$$
But wait — that would make the triangle very "flat", but mathematically possible.
Alternatively, could it be an exterior angle?
But based on standard interpretation: triangle with two angles given: 10° and 23°, and $ x $ is the third angle.
So:
$$
x = 180 - 10 - 23 = 147^\circ
$$
✔ Answer: $ x = 147 $
---
Equilateral triangle? All angles are $ x^\circ $, and there are three angles.
So:
$$
x + x + x = 180 \\
3x = 180 \\
x = 60
$$
✔ Answer: $ x = 60 $
---
Angles: $ (3x - 17)^\circ $, $ (x + 40)^\circ $, $ (2x - 5)^\circ $
Sum to 180°:
$$
(3x - 17) + (x + 40) + (2x - 5) = 180 \\
3x - 17 + x + 40 + 2x - 5 = 180 \\
(3x + x + 2x) + (-17 + 40 - 5) = 180 \\
6x + 18 = 180 \\
6x = 162 \\
x = 27
$$
Now verify:
- $ 3x - 17 = 81 - 17 = 64^\circ $
- $ x + 40 = 27 + 40 = 67^\circ $
- $ 2x - 5 = 54 - 5 = 49^\circ $
- Sum: $ 64 + 67 + 49 = 180 $ ✔
✔ Answer: $ x = 27 $
---
1) $ x = 75 $
2) $ x = 63 $
3) $ x = 20 $
4) $ x = 125 $
5) $ x = 13 $
6) $ x = 13 $
7) $ x = 85 $
8) $ x = 30 $
9) $ x = 29 $
10) $ x = 147 $
11) $ x = 60 $
12) $ x = 27 $
Let me know if you'd like a visual explanation or help with any specific one!
> The sum of the interior angles in any triangle is always 180°.
We’ll go through each problem one at a time.
---
1)
Triangle with angles: 58°, 47°, and $ x^\circ $
$$
x = 180^\circ - 58^\circ - 47^\circ = 180 - 105 = 75^\circ
$$
✔ Answer: $ x = 75 $
---
2)
Angles: $ x^\circ $, 96°, 21°
$$
x = 180 - 96 - 21 = 180 - 117 = 63^\circ
$$
✔ Answer: $ x = 63 $
---
3)
Right triangle (has a right angle), so one angle is 90°, another is 31°, and the third is $ (3x - 1)^\circ $
Sum of angles:
$$
90 + 31 + (3x - 1) = 180 \\
120 + 3x - 1 = 180 \\
119 + 3x = 180 \\
3x = 61 \\
x = \frac{61}{3} \approx 20.33
$$
Wait — let’s double-check.
Actually, the angle labeled $ (3x - 1)^\circ $ is likely one of the non-right angles, and the other is 31°.
So:
$$
90 + 31 + (3x - 1) = 180 \\
120 + 3x - 1 = 180 \\
119 + 3x = 180 \\
3x = 61 \\
x = \frac{61}{3} \approx 20.33
$$
But this gives a fractional value. Let’s check if that makes sense.
Wait — perhaps the labeling is different? Let’s assume the triangle has a right angle (90°), one angle is 31°, and the third is $ (3x - 1)^\circ $. Then yes, it must be:
$$
(3x - 1) = 180 - 90 - 31 = 59^\circ \\
3x - 1 = 59 \\
3x = 60 \\
x = 20
$$
Ah! So $ x = 20 $, and $ 3x - 1 = 59^\circ $, which works.
✔ Answer: $ x = 20 $
---
4)
Angles: $ x^\circ $, 21°, 34°
$$
x = 180 - 21 - 34 = 180 - 55 = 125^\circ
$$
✔ Answer: $ x = 125 $
---
5)
Angles: $ (2x + 3)^\circ $, 100°, 51°
$$
(2x + 3) + 100 + 51 = 180 \\
2x + 154 = 180 \\
2x = 26 \\
x = 13
$$
✔ Answer: $ x = 13 $
---
6)
Angles: $ x^\circ $, 60°, $ 2x^\circ $, and the third angle is 94°?
Wait — triangle has three angles. One is 94°, one is 60°, and the third is $ 2x^\circ $? But label says $ x^\circ $ and $ 2x^\circ $? Wait — look again.
It shows: one angle is 94°, one is 60°, and the third is $ 2x^\circ $. So:
$$
94 + 60 + 2x = 180 \\
154 + 2x = 180 \\
2x = 26 \\
x = 13
$$
✔ Answer: $ x = 13 $
---
7)
Angles: 52°, 43°, $ x^\circ $
$$
x = 180 - 52 - 43 = 180 - 95 = 85^\circ
$$
✔ Answer: $ x = 85 $
---
8)
Angles: $ x^\circ $, $ 3x^\circ $, $ 2x^\circ $
All three angles are expressed in terms of $ x $:
$$
x + 3x + 2x = 180 \\
6x = 180 \\
x = 30
$$
✔ Answer: $ x = 30 $
---
9)
Right triangle (right angle shown), so one angle is 90°.
Other angles: $ (2x - 2)^\circ $, and $ (x + 5)^\circ $
So:
$$
90 + (2x - 2) + (x + 5) = 180 \\
90 + 2x - 2 + x + 5 = 180 \\
(90 - 2 + 5) + 3x = 180 \\
93 + 3x = 180 \\
3x = 87 \\
x = 29
$$
Check:
- $ 2x - 2 = 58 - 2 = 56^\circ $
- $ x + 5 = 34^\circ $
- $ 90 + 56 + 34 = 180 $ ✔
✔ Answer: $ x = 29 $
---
10)
This is not a triangle — it looks like an angle formed by two lines extending from a point, but it's not a triangle. It appears to be a straight line or an external angle.
Wait — it shows two angles: 10° and 23°, and then $ x^\circ $ as the angle between them?
Wait — actually, it looks like a triangle with an exterior angle? Or maybe a straight line?
Looking closely: There’s a triangle-like shape, but it seems like three angles meeting at a point — no, more likely it's a triangle with two known angles on the base, and $ x $ is the top angle.
Wait — the diagram shows a triangle with two base angles: 10° and 23°, and $ x^\circ $ as the vertex angle?
Then:
$$
x = 180 - 10 - 23 = 147^\circ
$$
But wait — that would make the triangle very "flat", but mathematically possible.
Alternatively, could it be an exterior angle?
But based on standard interpretation: triangle with two angles given: 10° and 23°, and $ x $ is the third angle.
So:
$$
x = 180 - 10 - 23 = 147^\circ
$$
✔ Answer: $ x = 147 $
---
11)
Equilateral triangle? All angles are $ x^\circ $, and there are three angles.
So:
$$
x + x + x = 180 \\
3x = 180 \\
x = 60
$$
✔ Answer: $ x = 60 $
---
12)
Angles: $ (3x - 17)^\circ $, $ (x + 40)^\circ $, $ (2x - 5)^\circ $
Sum to 180°:
$$
(3x - 17) + (x + 40) + (2x - 5) = 180 \\
3x - 17 + x + 40 + 2x - 5 = 180 \\
(3x + x + 2x) + (-17 + 40 - 5) = 180 \\
6x + 18 = 180 \\
6x = 162 \\
x = 27
$$
Now verify:
- $ 3x - 17 = 81 - 17 = 64^\circ $
- $ x + 40 = 27 + 40 = 67^\circ $
- $ 2x - 5 = 54 - 5 = 49^\circ $
- Sum: $ 64 + 67 + 49 = 180 $ ✔
✔ Answer: $ x = 27 $
---
✔ Final Answers:
1) $ x = 75 $
2) $ x = 63 $
3) $ x = 20 $
4) $ x = 125 $
5) $ x = 13 $
6) $ x = 13 $
7) $ x = 85 $
8) $ x = 30 $
9) $ x = 29 $
10) $ x = 147 $
11) $ x = 60 $
12) $ x = 27 $
Let me know if you'd like a visual explanation or help with any specific one!
Parent Tip: Review the logic above to help your child master the concept of triangle sum and exterior angle theorem worksheet.