Practice worksheet for calculating the volume of triangular prisms with given dimensions.

To solve the problem of finding the volume of each triangular prism, we need to use the formula for the volume of a triangular prism:

\[
\text{Volume} = \text{Base Area} \times \text{Height}
\]

The base area of a triangular prism is given by the formula for the area of a triangle:

\[
\text{Base Area} = \frac{1}{2} \times \text{base} \times \text{height of the triangle}
\]

Let's solve each problem step by step.

---

Problem 1:

- Dimensions: Base of triangle = 10 in, Height of triangle = 14 in, Length of prism = 19 in
- Base Area:
\[
\text{Base Area} = \frac{1}{2} \times 10 \times 14 = 70 \text{ in}^2
\]
- Volume:
\[
\text{Volume} = \text{Base Area} \times \text{Length} = 70 \times 19 = 1330 \text{ in}^3
\]

Answer: \( \boxed{1330} \)

---

Problem 2:

- Dimensions: Base of triangle = 5 ft, Height of triangle = 17 ft, Length of prism = 18 ft
- Base Area:
\[
\text{Base Area} = \frac{1}{2} \times 5 \times 17 = 42.5 \text{ ft}^2
\]
- Volume:
\[
\text{Volume} = \text{Base Area} \times \text{Length} = 42.5 \times 18 = 765 \text{ ft}^3
\]

Answer: \( \boxed{765} \)

---

Problem 3:

- Dimensions: Base of triangle = 9 yd, Height of triangle = 6 yd, Length of prism = 11 yd
- Base Area:
\[
\text{Base Area} = \frac{1}{2} \times 9 \times 6 = 27 \text{ yd}^2
\]
- Volume:
\[
\text{Volume} = \text{Base Area} \times \text{Length} = 27 \times 11 = 297 \text{ yd}^3
\]

Answer: \( \boxed{297} \)

---

Problem 4:

- Dimensions: Base of triangle = 7 ft, Height of triangle = 5 ft, Length of prism = 9 ft
- Base Area:
\[
\text{Base Area} = \frac{1}{2} \times 7 \times 5 = 17.5 \text{ ft}^2
\]
- Volume:
\[
\text{Volume} = \text{Base Area} \times \text{Length} = 17.5 \times 9 = 157.5 \text{ ft}^3
\]

Answer: \( \boxed{157.5} \)

---

Problem 5:

- Dimensions: Base of triangle = 10 yd, Height of triangle = 7 yd, Length of prism = 12 yd
- Base Area:
\[
\text{Base Area} = \frac{1}{2} \times 10 \times 7 = 35 \text{ yd}^2
\]
- Volume:
\[
\text{Volume} = \text{Base Area} \times \text{Length} = 35 \times 12 = 420 \text{ yd}^3
\]

Answer: \( \boxed{420} \)

---

Problem 6:

- Dimensions: Base of triangle = 5 in, Height of triangle = 8 in, Length of prism = 11 in
- Base Area:
\[
\text{Base Area} = \frac{1}{2} \times 5 \times 8 = 20 \text{ in}^2
\]
- Volume:
\[
\text{Volume} = \text{Base Area} \times \text{Length} = 20 \times 11 = 220 \text{ in}^3
\]

Answer: \( \boxed{220} \)

---

Problem 7:

- Dimensions: Base of triangle = 19 yd, Height of triangle = 8 yd, Length of prism = 4 yd
- Base Area:
\[
\text{Base Area} = \frac{1}{2} \times 19 \times 8 = 76 \text{ yd}^2
\]
- Volume:
\[
\text{Volume} = \text{Base Area} \times \text{Length} = 76 \times 4 = 304 \text{ yd}^3
\]

Answer: \( \boxed{304} \)

---

Problem 8:

- Dimensions: Base of triangle = 14 in, Height of triangle = 12 in, Length of prism = 11 in
- Base Area:
\[
\text{Base Area} = \frac{1}{2} \times 14 \times 12 = 84 \text{ in}^2
\]
- Volume:
\[
\text{Volume} = \text{Base Area} \times \text{Length} = 84 \times 11 = 924 \text{ in}^3
\]

Answer: \( \boxed{924} \)

---

Problem 9:

- Dimensions: Base of triangle = 36 ft, Height of triangle = 40 ft, Length of prism = 30 ft
- Base Area:
\[
\text{Base Area} = \frac{1}{2} \times 36 \times 40 = 720 \text{ ft}^2
\]
- Volume:
\[
\text{Volume} = \text{Base Area} \times \text{Length} = 720 \times 30 = 21600 \text{ ft}^3
\]

Answer: \( \boxed{21600} \)

---

Final Answers:

1. \( \boxed{1330} \)
2. \( \boxed{765} \)
3. \( \boxed{297} \)
4. \( \boxed{157.5} \)
5. \( \boxed{420} \)
6. \( \boxed{220} \)
7. \( \boxed{304} \)
8. \( \boxed{924} \)
9. \( \boxed{21600} \)