49 Balancing Chemical Equations Worksheets [with Answers] - Free Printable
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Step-by-step solution for: 49 Balancing Chemical Equations Worksheets [with Answers]
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Show Answer Key & Explanations
Step-by-step solution for: 49 Balancing Chemical Equations Worksheets [with Answers]
Let’s go through each equation one by one and balance them. We’ll make sure the number of atoms of each element is the same on both sides of the arrow.
We’ll start with #1 and work our way down to #20. I’ll write the balanced coefficients in order for each reaction.
---
1) Li₃PO₄ + NaOH → LiOH + Na₃PO₄
Left: Li=3, P=1, O=4+1=5, Na=1, H=1
Right: Li=1, O=1+4=5, H=1, Na=3, P=1
To balance Na: put 3 in front of NaOH → now Na=3 left
Then Li: left has 3, right has 1 → put 3 in front of LiOH
Now check:
Left: Li=3, P=1, O=4+3=7, Na=3, H=3
Right: Li=3, O=3+4=7, H=3, Na=3, P=1 → Balanced!
✔ 1, 3, 3, 1
---
2) MgF₂ + Li₂CO₃ → MgCO₃ + LiF
Left: Mg=1, F=2, Li=2, C=1, O=3
Right: Mg=1, C=1, O=3, Li=1, F=1
Need 2 LiF on right → Li=2, F=2
Everything else already matches.
✔ 1, 1, 1, 2
---
3) P₄ + O₂ → P₂O₃
Left: P=4, O=2
Right: P=2, O=3
Make P equal: put 2 in front of P₂O₃ → P=4, O=6
Now O: need 3 O₂ on left → O=6
✔ 1, 3, 2
---
4) RbNO₃ + MgF₂ → Mg(NO₃)₂ + RbF
Left: Rb=1, N=1, O=3, Mg=1, F=2
Right: Mg=1, N=2, O=6, Rb=1, F=1
Need 2 RbNO₃ on left → Rb=2, N=2, O=6
Then need 2 RbF on right → Rb=2, F=2
MgF₂ already gives F=2 → good
✔ 2, 1, 1, 2
---
5) AgNO₃ + Cu → Cu(NO₃)₂ + Ag
Left: Ag=1, N=1, O=3, Cu=1
Right: Cu=1, N=2, O=6, Ag=1
Need 2 AgNO₃ on left → Ag=2, N=2, O=6
Then need 2 Ag on right
✔ 2, 1, 1, 2
---
6) CF₄ + Br₂ → CBr₄ + F₂
Left: C=1, F=4, Br=2
Right: C=1, Br=4, F=2
Need 2 Br₂ on left → Br=4
Need 2 F₂ on right → F=4
✔ 1, 2, 1, 2
---
7) HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
Left: H=1, C=1, N=1, Cu=1, S=1, O=4
Right: H=2, S=1, O=4, Cu=1, C=2, N=2
Need 2 HCN on left → H=2, C=2, N=2
Everything else matches.
✔ 2, 1, 1, 1
---
8) GaF₃ + Cs → CsF + Ga
Left: Ga=1, F=3, Cs=1
Right: Cs=1, F=1, Ga=1
Need 3 CsF on right → Cs=3, F=3
So need 3 Cs on left
✔ 1, 3, 3, 1
---
9) SrS + PtF₂ → SrF₂ + PtS
All elements match as written.
✔ 1, 1, 1, 1
---
10) N₂ + H₂ → NH₃
Left: N=2, H=2
Right: N=1, H=3
Put 2 in front of NH₃ → N=2, H=6
Then need 3 H₂ on left → H=6
✔ 1, 3, 2
---
11) LiF + Br₂ → LiBr + F₂
Left: Li=1, F=1, Br=2
Right: Li=1, Br=1, F=2
Need 2 LiF on left → Li=2, F=2
Need 2 LiBr on right → Li=2, Br=2
Br₂ already gives Br=2 → good
✔ 2, 1, 2, 1
---
12) Pb(OH)₂ + HCl → H₂O + PbCl₂
Left: Pb=1, O=2, H=2+1=3, Cl=1
Right: H=2, O=1, Pb=1, Cl=2
Need 2 HCl on left → H=2+2=4, Cl=2
Then need 2 H₂O on right → H=4, O=2
✔ 1, 2, 2, 1
---
13) GaBr₃ + Na₂CO₃ → NaBr + Ga₂(CO₃)₃ (tough)
Left: Ga=1, Br=3, Na=2, C=1, O=3
Right: Na=1, Br=1, Ga=2, C=3, O=9
Start with Ga: need 2 GaBr₃ → Ga=2, Br=6
Then NaBr: need 6 → Na=6, Br=6
Na₂CO₃: need 3 → Na=6, C=3, O=9
Ga₂(CO₃)₃: already has Ga=2, C=3, O=9 → perfect
✔ 2, 3, 6, 1
---
14) CH₄ + O₂ → CO₂ + H₂O
Left: C=1, H=4, O=2
Right: C=1, O=2+1=3, H=2
Need 2 H₂O → H=4, O=2+2=4? Wait: CO₂ has 2 O, 2 H₂O has 2 O → total 4 O
So need 2 O₂ on left → O=4
✔ 1, 2, 1, 2
---
15) Li₃PO₄ + CaCl₂ → LiCl + Ca₃(PO)₂ (also tough)
Left: Li=3, P=1, O=4, Ca=1, Cl=2
Right: Li=1, Cl=1, Ca=3, P=2, O=8
Start with Ca: need 3 CaCl₂ → Ca=3, Cl=6
Then LiCl: need 6 → Li=6, Cl=6
Li₃PO₄: need 2 → Li=6, P=2, O=8
Ca₃(PO)₂: already has Ca=3, P=2, O=8 → good
✔ 2, 3, 6, 1
---
16) Na + Cl₂ → NaCl
Left: Na=1, Cl=2
Right: Na=1, Cl=1
Need 2 NaCl → Na=2, Cl=2
So need 2 Na on left
✔ 2, 1, 2
---
17) Ga + HCl → H₂ + GaCl₃ (last tough one)
Left: Ga=1, H=1, Cl=1
Right: H=2, Ga=1, Cl=3
Need 3 HCl → H=3, Cl=3
But H₂ needs even H → so double everything:
Try 2 Ga + 6 HCl → 3 H₂ + 2 GaCl₃
Check:
Left: Ga=2, H=6, Cl=6
Right: H=6, Ga=2, Cl=6 → good
✔ 2, 6, 3, 2
---
18) N₂ + F₂ → NF₃
Left: N=2, F=2
Right: N=1, F=3
Need 2 NF₃ → N=2, F=6
Then need 3 F₂ → F=6
✔ 1, 3, 2
---
19) SO₂ + Li₂Se → SSe₂ + Li₂O
Left: S=1, O=2, Li=2, Se=1
Right: S=1, Se=2, Li=2, O=1
Need 2 Li₂O → O=2, Li=4
Then need 2 Li₂Se → Li=4, Se=2
SSe₂ already has Se=2 → good
Wait — let's recheck:
If we do:
SO₂ + 2 Li₂Se → SSe₂ + 2 Li₂O
Left: S=1, O=2, Li=4, Se=2
Right: S=1, Se=2, Li=4, O=2 → yes!
✔ 1, 2, 1, 2
---
20) NH₃ + H₂SO₄ → (NH₄)₂SO₄
Left: N=1, H=3+2=5, S=1, O=4
Right: N=2, H=8, S=1, O=4
Need 2 NH₃ → N=2, H=6
Plus H₂SO₄ → H=2 → total H=8 → perfect
✔ 2, 1, 1
---
Final Answer:
1) 1, 3, 3, 1
2) 1, 1, 1, 2
3) 1, 3, 2
4) 2, 1, 1, 2
5) 2, 1, 1, 2
6) 1, 2, 1, 2
7) 2, 1, 1, 1
8) 1, 3, 3, 1
9) 1, 1, 1, 1
10) 1, 3, 2
11) 2, 1, 2, 1
12) 1, 2, 2, 1
13) 2, 3, 6, 1
14) 1, 2, 1, 2
15) 2, 3, 6, 1
16) 2, 1, 2
17) 2, 6, 3, 2
18) 1, 3, 2
19) 1, 2, 1, 2
20) 2, 1, 1
We’ll start with #1 and work our way down to #20. I’ll write the balanced coefficients in order for each reaction.
---
1) Li₃PO₄ + NaOH → LiOH + Na₃PO₄
Left: Li=3, P=1, O=4+1=5, Na=1, H=1
Right: Li=1, O=1+4=5, H=1, Na=3, P=1
To balance Na: put 3 in front of NaOH → now Na=3 left
Then Li: left has 3, right has 1 → put 3 in front of LiOH
Now check:
Left: Li=3, P=1, O=4+3=7, Na=3, H=3
Right: Li=3, O=3+4=7, H=3, Na=3, P=1 → Balanced!
✔ 1, 3, 3, 1
---
2) MgF₂ + Li₂CO₃ → MgCO₃ + LiF
Left: Mg=1, F=2, Li=2, C=1, O=3
Right: Mg=1, C=1, O=3, Li=1, F=1
Need 2 LiF on right → Li=2, F=2
Everything else already matches.
✔ 1, 1, 1, 2
---
3) P₄ + O₂ → P₂O₃
Left: P=4, O=2
Right: P=2, O=3
Make P equal: put 2 in front of P₂O₃ → P=4, O=6
Now O: need 3 O₂ on left → O=6
✔ 1, 3, 2
---
4) RbNO₃ + MgF₂ → Mg(NO₃)₂ + RbF
Left: Rb=1, N=1, O=3, Mg=1, F=2
Right: Mg=1, N=2, O=6, Rb=1, F=1
Need 2 RbNO₃ on left → Rb=2, N=2, O=6
Then need 2 RbF on right → Rb=2, F=2
MgF₂ already gives F=2 → good
✔ 2, 1, 1, 2
---
5) AgNO₃ + Cu → Cu(NO₃)₂ + Ag
Left: Ag=1, N=1, O=3, Cu=1
Right: Cu=1, N=2, O=6, Ag=1
Need 2 AgNO₃ on left → Ag=2, N=2, O=6
Then need 2 Ag on right
✔ 2, 1, 1, 2
---
6) CF₄ + Br₂ → CBr₄ + F₂
Left: C=1, F=4, Br=2
Right: C=1, Br=4, F=2
Need 2 Br₂ on left → Br=4
Need 2 F₂ on right → F=4
✔ 1, 2, 1, 2
---
7) HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
Left: H=1, C=1, N=1, Cu=1, S=1, O=4
Right: H=2, S=1, O=4, Cu=1, C=2, N=2
Need 2 HCN on left → H=2, C=2, N=2
Everything else matches.
✔ 2, 1, 1, 1
---
8) GaF₃ + Cs → CsF + Ga
Left: Ga=1, F=3, Cs=1
Right: Cs=1, F=1, Ga=1
Need 3 CsF on right → Cs=3, F=3
So need 3 Cs on left
✔ 1, 3, 3, 1
---
9) SrS + PtF₂ → SrF₂ + PtS
All elements match as written.
✔ 1, 1, 1, 1
---
10) N₂ + H₂ → NH₃
Left: N=2, H=2
Right: N=1, H=3
Put 2 in front of NH₃ → N=2, H=6
Then need 3 H₂ on left → H=6
✔ 1, 3, 2
---
11) LiF + Br₂ → LiBr + F₂
Left: Li=1, F=1, Br=2
Right: Li=1, Br=1, F=2
Need 2 LiF on left → Li=2, F=2
Need 2 LiBr on right → Li=2, Br=2
Br₂ already gives Br=2 → good
✔ 2, 1, 2, 1
---
12) Pb(OH)₂ + HCl → H₂O + PbCl₂
Left: Pb=1, O=2, H=2+1=3, Cl=1
Right: H=2, O=1, Pb=1, Cl=2
Need 2 HCl on left → H=2+2=4, Cl=2
Then need 2 H₂O on right → H=4, O=2
✔ 1, 2, 2, 1
---
13) GaBr₃ + Na₂CO₃ → NaBr + Ga₂(CO₃)₃ (tough)
Left: Ga=1, Br=3, Na=2, C=1, O=3
Right: Na=1, Br=1, Ga=2, C=3, O=9
Start with Ga: need 2 GaBr₃ → Ga=2, Br=6
Then NaBr: need 6 → Na=6, Br=6
Na₂CO₃: need 3 → Na=6, C=3, O=9
Ga₂(CO₃)₃: already has Ga=2, C=3, O=9 → perfect
✔ 2, 3, 6, 1
---
14) CH₄ + O₂ → CO₂ + H₂O
Left: C=1, H=4, O=2
Right: C=1, O=2+1=3, H=2
Need 2 H₂O → H=4, O=2+2=4? Wait: CO₂ has 2 O, 2 H₂O has 2 O → total 4 O
So need 2 O₂ on left → O=4
✔ 1, 2, 1, 2
---
15) Li₃PO₄ + CaCl₂ → LiCl + Ca₃(PO)₂ (also tough)
Left: Li=3, P=1, O=4, Ca=1, Cl=2
Right: Li=1, Cl=1, Ca=3, P=2, O=8
Start with Ca: need 3 CaCl₂ → Ca=3, Cl=6
Then LiCl: need 6 → Li=6, Cl=6
Li₃PO₄: need 2 → Li=6, P=2, O=8
Ca₃(PO)₂: already has Ca=3, P=2, O=8 → good
✔ 2, 3, 6, 1
---
16) Na + Cl₂ → NaCl
Left: Na=1, Cl=2
Right: Na=1, Cl=1
Need 2 NaCl → Na=2, Cl=2
So need 2 Na on left
✔ 2, 1, 2
---
17) Ga + HCl → H₂ + GaCl₃ (last tough one)
Left: Ga=1, H=1, Cl=1
Right: H=2, Ga=1, Cl=3
Need 3 HCl → H=3, Cl=3
But H₂ needs even H → so double everything:
Try 2 Ga + 6 HCl → 3 H₂ + 2 GaCl₃
Check:
Left: Ga=2, H=6, Cl=6
Right: H=6, Ga=2, Cl=6 → good
✔ 2, 6, 3, 2
---
18) N₂ + F₂ → NF₃
Left: N=2, F=2
Right: N=1, F=3
Need 2 NF₃ → N=2, F=6
Then need 3 F₂ → F=6
✔ 1, 3, 2
---
19) SO₂ + Li₂Se → SSe₂ + Li₂O
Left: S=1, O=2, Li=2, Se=1
Right: S=1, Se=2, Li=2, O=1
Need 2 Li₂O → O=2, Li=4
Then need 2 Li₂Se → Li=4, Se=2
SSe₂ already has Se=2 → good
Wait — let's recheck:
If we do:
SO₂ + 2 Li₂Se → SSe₂ + 2 Li₂O
Left: S=1, O=2, Li=4, Se=2
Right: S=1, Se=2, Li=4, O=2 → yes!
✔ 1, 2, 1, 2
---
20) NH₃ + H₂SO₄ → (NH₄)₂SO₄
Left: N=1, H=3+2=5, S=1, O=4
Right: N=2, H=8, S=1, O=4
Need 2 NH₃ → N=2, H=6
Plus H₂SO₄ → H=2 → total H=8 → perfect
✔ 2, 1, 1
---
Final Answer:
1) 1, 3, 3, 1
2) 1, 1, 1, 2
3) 1, 3, 2
4) 2, 1, 1, 2
5) 2, 1, 1, 2
6) 1, 2, 1, 2
7) 2, 1, 1, 1
8) 1, 3, 3, 1
9) 1, 1, 1, 1
10) 1, 3, 2
11) 2, 1, 2, 1
12) 1, 2, 2, 1
13) 2, 3, 6, 1
14) 1, 2, 1, 2
15) 2, 3, 6, 1
16) 2, 1, 2
17) 2, 6, 3, 2
18) 1, 3, 2
19) 1, 2, 1, 2
20) 2, 1, 1
Parent Tip: Review the logic above to help your child master the concept of understanding chemical equations worksheet.