Let's solve each expression using the
Distributive Property, which states:
> $ a(b + c) = ab + ac $
We'll apply this property to simplify each expression. Let's go through them one by one.
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1) $-6(a + 8)$
Distribute $-6$ to both terms inside the parentheses:
$$
-6 \cdot a + (-6) \cdot 8 = -6a - 48
$$
✔ Answer: $-6a - 48$
---
2) $4(1 + 9x)$
Distribute $4$:
$$
4 \cdot 1 + 4 \cdot 9x = 4 + 36x
$$
✔ Answer: $4 + 36x$
---
3) $6(-5n + 7)$
Distribute $6$:
$$
6 \cdot (-5n) + 6 \cdot 7 = -30n + 42
$$
✔ Answer: $-30n + 42$
---
4) $(9m + 10) - 2$
Wait — this is
not a distributive problem in the same way. There’s no multiplication over addition here, just subtraction.
But we can interpret it as:
$$
(9m + 10) - 2 = 9m + 10 - 2 = 9m + 8
$$
✔ Answer: $9m + 8$
(Note: This doesn't involve distribution unless there was a typo and it was meant to be something like $-2(9m + 10)$, but as written, it's just simplifying.)
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5) $(-4 - 3n) - 8$
Again, no distribution needed — just combine like terms:
$$
-4 - 3n - 8 = -3n - 12
$$
✔ Answer: $-3n - 12$
---
6) $8(-b - 4)$
Distribute $8$:
$$
8 \cdot (-b) + 8 \cdot (-4) = -8b - 32
$$
✔ Answer: $-8b - 32$
---
7) $(1 - 7n) - 5$
Simplify by combining constants:
$$
1 - 7n - 5 = -7n - 4
$$
✔ Answer: $-7n - 4$
---
8) $-6(x + 4)$
Distribute $-6$:
$$
-6 \cdot x + (-6) \cdot 4 = -6x - 24
$$
✔ Answer: $-6x - 24$
---
9) $5(3n - 6)$
Distribute $5$:
$$
5 \cdot 3n + 5 \cdot (-6) = 15n - 30
$$
✔ Answer: $15n - 30$
---
10) $(-6p + 7) \cdot -4$
This means: $-4(-6p + 7)$
Distribute $-4$:
$$
-4 \cdot (-6p) + (-4) \cdot 7 = 24p - 28
$$
✔ Answer: $24p - 28$
---
11) $5(b - 1)$
Distribute $5$:
$$
5 \cdot b + 5 \cdot (-1) = 5b - 5
$$
✔ Answer: $5b - 5$
---
12) $(x + 9) - 5$
Combine like terms:
$$
x + 9 - 5 = x + 4
$$
✔ Answer: $x + 4$
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✔ Final Answers:
1) $-6a - 48$
2) $4 + 36x$
3) $-30n + 42$
4) $9m + 8$
5) $-3n - 12$
6) $-8b - 32$
7) $-7n - 4$
8) $-6x - 24$
9) $15n - 30$
10) $24p - 28$
11) $5b - 5$
12) $x + 4$
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Parent Tip: Review the logic above to help your child master the concept of using distributive property kuta software infinite algebra 1 answers.