Surface area calculation practice for mixed geometric shapes with given dimensions.

To solve the problem of finding the surface area of each shape, we will calculate the surface area for each figure step by step. Here are the solutions:

---

1) Triangular Pyramid

The given triangular pyramid has:
- Base side length = 5 ft
- Slant height of the triangular faces = 11 ft

#### Surface Area Calculation:
The surface area of a triangular pyramid consists of:
- The base (a triangle)
- Three triangular lateral faces

Base Area:
The base is an equilateral triangle with side length 5 ft.
\[
\text{Area of base} = \frac{\sqrt{3}}{4} \times (\text{side})^2 = \frac{\sqrt{3}}{4} \times 5^2 = \frac{\sqrt{3}}{4} \times 25 = \frac{25\sqrt{3}}{4} \approx 10.83 \, \text{ft}^2
\]

Lateral Faces:
Each lateral face is a triangle with base 5 ft and slant height 11 ft.
\[
\text{Area of one lateral face} = \frac{1}{2} \times \text{base} \times \text{slant height} = \frac{1}{2} \times 5 \times 11 = 27.5 \, \text{ft}^2
\]
Since there are three lateral faces:
\[
\text{Total lateral area} = 3 \times 27.5 = 82.5 \, \text{ft}^2
\]

Total Surface Area:
\[
\text{Surface Area} = \text{Base Area} + \text{Lateral Area} = 10.83 + 82.5 = 93.33 \, \text{ft}^2
\]

Answer:
\[
\boxed{93.33}
\]

---

2) Cylinder

The given cylinder has:
- Diameter = 12 yd → Radius \( r = \frac{12}{2} = 6 \) yd
- Height \( h = 14 \) yd

#### Surface Area Calculation:
The surface area of a cylinder consists of:
- Two circular bases
- One curved surface

Area of one circular base:
\[
\text{Area of one base} = \pi r^2 = 3.14 \times 6^2 = 3.14 \times 36 = 113.04 \, \text{yd}^2
\]
Since there are two bases:
\[
\text{Total base area} = 2 \times 113.04 = 226.08 \, \text{yd}^2
\]

Curved Surface Area:
\[
\text{Curved Surface Area} = 2\pi rh = 2 \times 3.14 \times 6 \times 14 = 3.14 \times 12 \times 14 = 527.52 \, \text{yd}^2
\]

Total Surface Area:
\[
\text{Surface Area} = \text{Total base area} + \text{Curved Surface Area} = 226.08 + 527.52 = 753.6 \, \text{yd}^2
\]

Answer:
\[
\boxed{753.6}
\]

---

3) Square Pyramid

The given square pyramid has:
- Side length of the base = 12 in
- Slant height of the triangular faces = 10 in

#### Surface Area Calculation:
The surface area of a square pyramid consists of:
- The base (a square)
- Four triangular lateral faces

Base Area:
\[
\text{Area of base} = \text{side}^2 = 12^2 = 144 \, \text{in}^2
\]

Lateral Faces:
Each lateral face is a triangle with base 12 in and slant height 10 in.
\[
\text{Area of one lateral face} = \frac{1}{2} \times \text{base} \times \text{slant height} = \frac{1}{2} \times 12 \times 10 = 60 \, \text{in}^2
\]
Since there are four lateral faces:
\[
\text{Total lateral area} = 4 \times 60 = 240 \, \text{in}^2
\]

Total Surface Area:
\[
\text{Surface Area} = \text{Base Area} + \text{Lateral Area} = 144 + 240 = 384 \, \text{in}^2
\]

Answer:
\[
\boxed{384}
\]

---

4) Hemisphere

The given hemisphere has:
- Diameter = 10 m → Radius \( r = \frac{10}{2} = 5 \) m

#### Surface Area Calculation:
The surface area of a hemisphere consists of:
- Curved surface area of the hemisphere
- Area of the circular base (if included)

Curved Surface Area:
\[
\text{Curved Surface Area} = 2\pi r^2 = 2 \times 3.14 \times 5^2 = 2 \times 3.14 \times 25 = 157 \, \text{m}^2
\]

Base Area:
\[
\text{Base Area} = \pi r^2 = 3.14 \times 5^2 = 3.14 \times 25 = 78.5 \, \text{m}^2
\]

Total Surface Area:
\[
\text{Surface Area} = \text{Curved Surface Area} + \text{Base Area} = 157 + 78.5 = 235.5 \, \text{m}^2
\]

Answer:
\[
\boxed{235.5}
\]

---

5) Cone

The given cone has:
- Radius \( r = 4 \) cm
- Slant height \( l = 11 \) cm

#### Surface Area Calculation:
The surface area of a cone consists of:
- Curved surface area
- Base area

Curved Surface Area:
\[
\text{Curved Surface Area} = \pi r l = 3.14 \times 4 \times 11 = 138.16 \, \text{cm}^2
\]

Base Area:
\[
\text{Base Area} = \pi r^2 = 3.14 \times 4^2 = 3.14 \times 16 = 50.24 \, \text{cm}^2
\]

Total Surface Area:
\[
\text{Surface Area} = \text{Curved Surface Area} + \text{Base Area} = 138.16 + 50.24 = 188.4 \, \text{cm}^2
\]

Answer:
\[
\boxed{188.4}
\]

---

6) Rectangular Prism

The given rectangular prism has:
- Length \( l = 15 \) ft
- Width \( w = 10 \) ft
- Height \( h = 8 \) ft

#### Surface Area Calculation:
The surface area of a rectangular prism is given by:
\[
\text{Surface Area} = 2(lw + lh + wh)
\]
\[
\text{Surface Area} = 2(15 \times 10 + 15 \times 8 + 10 \times 8) = 2(150 + 120 + 80) = 2 \times 350 = 700 \, \text{ft}^2
\]

Answer:
\[
\boxed{700}
\]

---

7) Cylinder

The given cylinder has:
- Diameter = 10 in → Radius \( r = \frac{10}{2} = 5 \) in
- Height \( h = 9 \) in

#### Surface Area Calculation:
The surface area of a cylinder consists of:
- Two circular bases
- One curved surface

Area of one circular base:
\[
\text{Area of one base} = \pi r^2 = 3.14 \times 5^2 = 3.14 \times 25 = 78.5 \, \text{in}^2
\]
Since there are two bases:
\[
\text{Total base area} = 2 \times 78.5 = 157 \, \text{in}^2
\]

Curved Surface Area:
\[
\text{Curved Surface Area} = 2\pi rh = 2 \times 3.14 \times 5 \times 9 = 3.14 \times 10 \times 9 = 282.6 \, \text{in}^2
\]

Total Surface Area:
\[
\text{Surface Area} = \text{Total base area} + \text{Curved Surface Area} = 157 + 282.6 = 439.6 \, \text{in}^2
\]

Answer:
\[
\boxed{439.6}
\]

---

8) Cube

The given cube has:
- Side length \( s = 18 \) ft

#### Surface Area Calculation:
The surface area of a cube is given by:
\[
\text{Surface Area} = 6s^2
\]
\[
\text{Surface Area} = 6 \times 18^2 = 6 \times 324 = 1944 \, \text{ft}^2
\]

Answer:
\[
\boxed{1944}
\]

---

9) Sphere

The given sphere has:
- Radius \( r = 6 \) m

#### Surface Area Calculation:
The surface area of a sphere is given by:
\[
\text{Surface Area} = 4\pi r^2
\]
\[
\text{Surface Area} = 4 \times 3.14 \times 6^2 = 4 \times 3.14 \times 36 = 452.16 \, \text{m}^2
\]

Answer:
\[
\boxed{452.16}
\]

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Final Answers:

\[
\boxed{93.33, 753.6, 384, 235.5, 188.4, 700, 439.6, 1944, 452.16}
\]