Free. Exclusive. Just for you.
Four unique services that make learning easier, faster, and smarter - only on our website.

Surface area calculation worksheet for cylinders with varying dimensions and units.

Worksheet with nine cylinders, each labeled with dimensions in various units (cm, m, mm), asking to find surface area using Pi = 3.14 and rounding to the nearest tenth.

Worksheet with nine cylinders, each labeled with dimensions in various units (cm, m, mm), asking to find surface area using Pi = 3.14 and rounding to the nearest tenth.

JPG 1000×1291 75 KB Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #600233
Show Answer Key & Explanations Step-by-step solution for: Surface Area of Cylinders worksheet
Let’s solve each cylinder’s surface area step by step.

The formula for the surface area (SA) of a cylinder is:

SA = 2πr² + 2πrh

Where:
- r = radius
- h = height
- π = 3.14 (as instructed)

We’ll calculate each one carefully, rounding to the nearest tenth at the end.

---

Cylinder 1: radius = 20 cm, height = 42 cm

SA = 2 × 3.14 × (20)² + 2 × 3.14 × 20 × 42
= 2 × 3.14 × 400 + 2 × 3.14 × 840
= 6.28 × 400 + 6.28 × 840
= 2512 + 5275.2
= 7787.2 cm²

---

Cylinder 2: radius = 9 m, height = 7 m

SA = 2 × 3.14 × (9)² + 2 × 3.14 × 9 × 7
= 2 × 3.14 × 81 + 2 × 3.14 × 63
= 6.28 × 81 + 6.28 × 63
= 508.68 + 395.64
= 904.3 m²

---

Cylinder 3: radius = 21 mm, height = 76 mm

SA = 2 × 3.14 × (21)² + 2 × 3.14 × 21 × 76
= 2 × 3.14 × 441 + 2 × 3.14 × 1596
= 6.28 × 441 + 6.28 × 1596
= 2769.48 + 10022.88
= 12792.4 mm²

---

Cylinder 4: radius = 2 m, height = 2 m

SA = 2 × 3.14 × (2)² + 2 × 3.14 × 2 × 2
= 2 × 3.14 × 4 + 2 × 3.14 × 4
= 6.28 × 4 + 6.28 × 4
= 25.12 + 25.12
= 50.2 m²

---

Cylinder 5: radius = 11 cm, height = 17 cm

SA = 2 × 3.14 × (11)² + 2 × 3.14 × 11 × 17
= 2 × 3.14 × 121 + 2 × 3.14 × 187
= 6.28 × 121 + 6.28 × 187
= 759.88 + 1174.36
= 1934.2 cm²

---

Cylinder 6: radius = 3 cm, height = 4 cm

SA = 2 × 3.14 × (3)² + 2 × 3.14 × 3 × 4
= 2 × 3.14 × 9 + 2 × 3.14 × 12
= 6.28 × 9 + 6.28 × 12
= 56.52 + 75.36
= 131.9 cm²

---

Cylinder 7: radius = 42 cm, height = 20 cm

SA = 2 × 3.14 × (42)² + 2 × 3.14 × 42 × 20
= 2 × 3.14 × 1764 + 2 × 3.14 × 840
= 6.28 × 1764 + 6.28 × 840
= 11077.92 + 5275.2
= 16353.1 cm²

---

Cylinder 8: radius = 0.18 m, height = 0.6 m

SA = 2 × 3.14 × (0.18)² + 2 × 3.14 × 0.18 × 0.6
= 2 × 3.14 × 0.0324 + 2 × 3.14 × 0.108
= 6.28 × 0.0324 + 6.28 × 0.108
= 0.203472 + 0.67824
= 0.881712 → rounded to 0.9 m²

Wait — let me double-check that calculation.

0.18² = 0.0324
2 × 3.14 × 0.0324 = 6.28 × 0.0324 = let's compute:

6.28 × 0.03 = 0.1884
6.28 × 0.0024 = 0.015072
Total = 0.203472 ✔️

Now lateral part: 2 × 3.14 × 0.18 × 0.6 = 6.28 × 0.108

6.28 × 0.1 = 0.628
6.28 × 0.008 = 0.05024
Total = 0.67824 ✔️

Sum: 0.203472 + 0.67824 = 0.881712 → rounds to 0.9 m²

But wait — 0.881712 rounded to nearest tenth is 0.9? Yes, because hundredths digit is 8 ≥ 5.

Actually, 0.881712 → tenths place is 8, hundredths is 8 → so yes, round up → 0.9

BUT — let me check if I should keep more precision or if I made an error.

Alternatively, maybe it’s better to write as:

SA = 2πr(r + h) = 2 × 3.14 × 0.18 × (0.18 + 0.6) = 6.28 × 0.18 × 0.78

First: 0.18 × 0.78 = 0.1404
Then: 6.28 × 0.1404 = ?

6 × 0.1404 = 0.8424
0.28 × 0.1404 ≈ 0.039312
Total ≈ 0.881712 → same as before → 0.9 m²

Okay, correct.

---

Cylinder 9: radius = 26 mm, height = 32 mm

SA = 2 × 3.14 × (26)² + 2 × 3.14 × 26 × 32
= 2 × 3.14 × 676 + 2 × 3.14 × 832
= 6.28 × 676 + 6.28 × 832
Compute each:

6.28 × 676:
6 × 676 = 4056
0.28 × 676 = 189.28
Total = 4245.28

6.28 × 832:
6 × 832 = 4992
0.28 × 832 = 232.96
Total = 5224.96

Sum: 4245.28 + 5224.96 = 9470.2 mm²

Wait — let me verify with direct multiplication:

6.28 × 676:

Breakdown:
676 × 6 = 4056
676 × 0.28 = 676 × 0.2 = 135.2; 676 × 0.08 = 54.08 → total 189.28
So 4056 + 189.28 = 4245.28 ✔️

6.28 × 832:

832 × 6 = 4992
832 × 0.28 = 832 × 0.2 = 166.4; 832 × 0.08 = 66.56 → total 232.96
4992 + 232.96 = 5224.96 ✔️

Sum: 4245.28 + 5224.96 = 9470.24 → rounds to 9470.2 mm²

Yes.

---

Final Answers:

Cylinder 1: 7787.2 cm²
Cylinder 2: 904.3 m²
Cylinder 3: 12792.4 mm²
Cylinder 4: 50.2 m²
Cylinder 5: 1934.2 cm²
Cylinder 6: 131.9 cm²
Cylinder 7: 16353.1 cm²
Cylinder 8: 0.9 m²
Cylinder 9: 9470.2 mm²

──────────────────────────────────────

Final Answer:
7787.2, 904.3, 12792.4, 50.2, 1934.2, 131.9, 16353.1, 0.9, 9470.2
Parent Tip: Review the logic above to help your child master the concept of volume and surface area of cylinders worksheet.
Print Download

How to use

Click Print to open a print-ready version directly in your browser, or use Download to save the file to your device. The ⭐ Answer button generates an AI answer key instantly - useful for teachers who need a quick reference. Need a different version? Our AI Worksheet Generator lets you create a custom worksheet on any topic in seconds.

(view all volume and surface area of cylinders worksheet)

Surface Area of a Cylinder - GCSE Maths - Steps, Examples & Worksheet
Volume of a Cylinder | Twinkl Teaching Wiki & Resources
Calculating Surface Area and Volume of Cylinders (A)
Surface Area and Volume of Cylinders worksheet - Issaquah Connect
Volume and Surface Area of Cones and Spheres Worksheet | PDF ...
Surface area of cylinder worksheet pdf | lingdapaca1985s Ownd
Surface Area of Cylinders Worksheets
Surface Area and Volume of Prism and Cylinder worksheet | Live ...
50+ Volume of a Cylinder worksheets on Quizizz | Free & Printable
Solid figures, volume and surface area worksheets pdf