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Math worksheet for calculating the surface area of cylinders with real-world examples.

A math worksheet titled "Surface Area of a Cylinder Sheet 3" with four problems involving calculating the surface area of various cylinders, including a hockey puck, cardboard tube, plant pot, and plastic pipe, each with given dimensions and a space for working out the solutions.

A math worksheet titled "Surface Area of a Cylinder Sheet 3" with four problems involving calculating the surface area of various cylinders, including a hockey puck, cardboard tube, plant pot, and plastic pipe, each with given dimensions and a space for working out the solutions.

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Show Answer Key & Explanations Step-by-step solution for: Surface Area of a Cylinder
Let's solve each problem step by step, calculating the surface area of each cylinder. We’ll use the formulas for surface area depending on whether the cylinder is closed (has both top and bottom) or open (missing one or both ends).

---

🔷 Formulas:



- Lateral Surface Area (side only) = $ 2\pi r h $
- Area of one circular base = $ \pi r^2 $
- Total Surface Area (closed cylinder) = $ 2\pi r h + 2\pi r^2 $
- Surface Area (open at one end) = $ 2\pi r h + \pi r^2 $
- Surface Area (open at both ends, like a pipe) = $ 2\pi r h $

> Remember:
> - Radius $ r = \frac{\text{diameter}}{2} $
> - Use $ \pi \approx 3.14 $

---

## Problem 1: Hockey Puck (Closed Cylinder)

Given:
- Diameter = 3 in → Radius $ r = \frac{3}{2} = 1.5 $ in
- Height $ h = 1 $ in

This is a closed cylinder (has top and bottom).

$$
\text{SA} = 2\pi r h + 2\pi r^2
= 2\pi(1.5)(1) + 2\pi(1.5)^2
= 3\pi + 2\pi(2.25)
= 3\pi + 4.5\pi
= 7.5\pi
$$

$$
7.5 \times 3.14 = 23.55 \approx \boxed{23.6} \text{ in}^2
$$

Answer: 23.6 in²

---

## Problem 2: Cardboard Tube (Closed Cylinder)

Given:
- Diameter = 4 cm → $ r = 2 $ cm
- Height = 12 cm

It's a closed tube, so both ends are present.

$$
\text{SA} = 2\pi r h + 2\pi r^2
= 2\pi(2)(12) + 2\pi(2)^2
= 48\pi + 8\pi
= 56\pi
$$

$$
56 \times 3.14 = 175.84 \approx \boxed{175.8} \text{ cm}^2
$$

Answer: 175.8 cm²

---

## Problem 3: Plant Pot (Open Top – No Lid)

Given:
- Diameter = 12 in → $ r = 6 $ in
- Height = 17 in

No lid → only one base and lateral surface.

$$
\text{SA} = 2\pi r h + \pi r^2
= 2\pi(6)(17) + \pi(6)^2
= 204\pi + 36\pi
= 240\pi
$$

$$
240 \times 3.14 = 753.6 \approx \boxed{753.6} \text{ in}^2
$$

Answer: 753.6 in²

---

## Problem 4: Plastic Pipe (Open at Both Ends)

Given:
- Diameter = 14 cm → $ r = 7 $ cm
- Length = 3 m = 300 cm (convert to same unit!)

Since it's a pipe, it has no ends → only lateral surface area.

$$
\text{SA} = 2\pi r h = 2\pi(7)(300) = 4200\pi
$$

$$
4200 \times 3.14 = 13,188 \approx \boxed{13,188.0} \text{ cm}^2
$$

Answer: 13,188.0 cm²

---

📝 Final Answers:



| Problem | Answer |
|--------|--------|
| 1) | 23.6 in² |
| 2) | 175.8 cm² |
| 3) | 753.6 in² |
| 4) | 13,188.0 cm² |

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