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Printable math worksheet for calculating surface area of prisms and cylinders.

Worksheet titled "Surface Area: Prisms & Cylinders" with nine geometric shapes (prisms and cylinders) each labeled with dimensions, asking students to find the exact surface area.

Worksheet titled "Surface Area: Prisms & Cylinders" with nine geometric shapes (prisms and cylinders) each labeled with dimensions, asking students to find the exact surface area.

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Show Answer Key & Explanations Step-by-step solution for: Surface Area Of Prisms And Cylinders Worksheets - Worksheets ...
Let's solve each problem step by step to find the exact surface area of each shape. We'll use formulas for:

- Rectangular Prisms:
$$
SA = 2(lw + lh + wh)
$$

- Triangular Prisms:
$$
SA = \text{Base Area} \times 2 + \text{Lateral Area}
$$
(Lateral area = perimeter of base × height)

- Cylinders:
$$
SA = 2\pi r^2 + 2\pi rh
$$

We’ll go through each shape.

---

1) Rectangular Prism


Dimensions: 6 ft (length), 4 ft (width), 12 ft (height)

$$
SA = 2(lw + lh + wh) = 2(6×4 + 6×12 + 4×12) = 2(24 + 72 + 48) = 2(144) = \boxed{288} \text{ ft}^2
$$

---

2) Triangular Prism


Base triangle: base = 6 yd, height = 3 yd
Side lengths: 6 yd, 5 yd, 5 yd
Height of prism = 11 yd

Step 1: Area of triangular bases
$$
A_{\text{base}} = \frac{1}{2} \times 6 \times 3 = 9 \text{ yd}^2
$$
Two bases: $ 2 \times 9 = 18 $

Step 2: Lateral area
Perimeter of base = 6 + 5 + 5 = 16 yd
Lateral area = perimeter × height = $ 16 \times 11 = 176 $

Total SA = $ 18 + 176 = \boxed{194} \text{ yd}^2 $

---

3) Rectangular Prism


Dimensions: 8 in (length), 5 in (width), 14 in (height)

$$
SA = 2(8×5 + 8×14 + 5×14) = 2(40 + 112 + 70) = 2(222) = \boxed{444} \text{ in}^2
$$

---

4) Triangular Prism (Right Triangle Base)


Base triangle: legs = 9 in and 12 in, hypotenuse = 15 in
Prism height = 12 in

Step 1: Area of triangular bases
$$
A = \frac{1}{2} \times 9 \times 12 = 54 \text{ in}^2
$$
Two bases: $ 2 \times 54 = 108 $

Step 2: Lateral area
Perimeter = 9 + 12 + 15 = 36 in
Lateral area = $ 36 \times 12 = 432 $

Total SA = $ 108 + 432 = \boxed{540} \text{ in}^2 $

---

5) Cube


All sides = 9 ft

$$
SA = 6s^2 = 6 \times 9^2 = 6 \times 81 = \boxed{486} \text{ ft}^2
$$

---

6) Cylinder


Radius = 10 yd, Height = 30 yd

$$
SA = 2\pi r^2 + 2\pi r h = 2\pi(10)^2 + 2\pi(10)(30) = 2\pi(100) + 2\pi(300) = 200\pi + 600\pi = 800\pi
$$
Exact answer: $ \boxed{800\pi} \text{ yd}^2 $

---

7) Cylinder


Diameter = 2 m → radius = 1 m, Height = 11 m

$$
SA = 2\pi r^2 + 2\pi r h = 2\pi(1)^2 + 2\pi(1)(11) = 2\pi + 22\pi = 24\pi
$$
Exact answer: $ \boxed{24\pi} \text{ m}^2 $

---

8) Rectangular Prism


Dimensions: 7 m (length), 4 m (width), 15 m (height)

$$
SA = 2(7×4 + 7×15 + 4×15) = 2(28 + 105 + 60) = 2(193) = \boxed{386} \text{ m}^2
$$

---

9) Triangular Prism


Base triangle: base = 10 yd, height = 12 yd, side lengths: 13 yd, 13 yd, 10 yd
Prism height = 14 yd

Step 1: Area of triangular bases
$$
A = \frac{1}{2} \times 10 \times 12 = 60 \text{ yd}^2
$$
Two bases: $ 2 \times 60 = 120 $

Step 2: Lateral area
Perimeter = 13 + 13 + 10 = 36 yd
Lateral area = $ 36 \times 14 = 504 $

Total SA = $ 120 + 504 = \boxed{624} \text{ yd}^2 $

---

Final Answers:


1) $ \boxed{288} \text{ ft}^2 $
2) $ \boxed{194} \text{ yd}^2 $
3) $ \boxed{444} \text{ in}^2 $
4) $ \boxed{540} \text{ in}^2 $
5) $ \boxed{486} \text{ ft}^2 $
6) $ \boxed{800\pi} \text{ yd}^2 $
7) $ \boxed{24\pi} \text{ m}^2 $
8) $ \boxed{386} \text{ m}^2 $
9) $ \boxed{624} \text{ yd}^2 $

Let me know if you'd like a visual explanation or help with any specific one!
Parent Tip: Review the logic above to help your child master the concept of volume and surface area worksheet pdf.
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