Volume of Irregular Solids Worksheet interactive worksheet | Live ... - Free Printable

Problem Description:

The task is to find the volume of an eraser using the water displacement method. The image shows two graduated cylinders:

1. Left Cylinder: Contains water alone, with the water level marked.
2. Right Cylinder: Contains the same amount of water as the left cylinder, but with an eraser submerged in it, causing the water level to rise.

The formula provided is:
\[
V = V_f - V_i
\]
where:
- \( V \) is the volume of the eraser,
- \( V_f \) is the final volume (water level after submerging the eraser),
- \( V_i \) is the initial volume (water level before submerging the eraser).

Step-by-Step Solution:

#### 1. Identify the Initial Volume (\( V_i \)):
- The left cylinder shows the water level without the eraser.
- The water level is at the 5 mL mark.
- Therefore, \( V_i = 5 \, \text{mL} \).

#### 2. Identify the Final Volume (\( V_f \)):
- The right cylinder shows the water level with the eraser submerged.
- The water level is at the 15 mL mark.
- Therefore, \( V_f = 15 \, \text{mL} \).

#### 3. Calculate the Volume of the Eraser (\( V \)):
- Use the formula:
\[
V = V_f - V_i
\]
- Substitute the values:
\[
V = 15 \, \text{mL} - 5 \, \text{mL}
\]
- Simplify:
\[
V = 10 \, \text{mL}
\]

Final Answer:

\[
\boxed{10}
\]

Explanation:

The volume of the eraser is determined by the increase in the water level when the eraser is submerged. This increase represents the volume of water displaced by the eraser, which is equal to the volume of the eraser itself. In this case, the water level rose from 5 mL to 15 mL, indicating that the eraser displaced 10 mL of water. Thus, the volume of the eraser is 10 mL.