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Volume Of Pyramids Cones And Spheres Worksheet Fun And, 50% OFF - Free Printable

Volume Of Pyramids Cones And Spheres Worksheet Fun And, 50% OFF

Educational worksheet: Volume Of Pyramids Cones And Spheres Worksheet Fun And, 50% OFF. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Volume Of Pyramids Cones And Spheres Worksheet Fun And, 50% OFF
Of course! Let's solve each problem step by step. The worksheet asks for the volume of various pyramids and cones. The general formulas are:

- Volume of a Pyramid:
\[ V = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]

- Volume of a Cone:
\[ V = \frac{1}{3} \pi r^2 h \]
(where \( r \) is the radius, and \( h \) is the height)

---

Problem 1: Square Pyramid


- Base side = 25
- Height = 10

Base Area = \( 25 \times 25 = 625 \)

\[
V = \frac{1}{3} \times 625 \times 10 = \frac{6250}{3}
\]

Answer: \(\boxed{\dfrac{6250}{3}}\)

---

Problem 2: Cone


- Radius = 11
- Height = 21

\[
V = \frac{1}{3} \pi (11)^2 (21) = \frac{1}{3} \pi (121)(21)
\]

\[
= \frac{1}{3} \pi (2541) = 847\pi
\]

Answer: \(\boxed{847\pi}\)

---

Problem 3: Rectangular Pyramid


- Base dimensions: 32 × 14
- Height = 60

Base Area = \( 32 \times 14 = 448 \)

\[
V = \frac{1}{3} \times 448 \times 60 = \frac{26880}{3} = 8960
\]

Answer: \(\boxed{8960}\)

---

Problem 4: Square Pyramid


- Base side = 5 m
- Height = 4 m

Base Area = \( 5 \times 5 = 25 \)

\[
V = \frac{1}{3} \times 25 \times 4 = \frac{100}{3}
\]

Answer: \(\boxed{\dfrac{100}{3}}\)

---

Problem 5: Cone


- Diameter = 4 mm → Radius = 2 mm
- Height = 8 mm

\[
V = \frac{1}{3} \pi (2)^2 (8) = \frac{1}{3} \pi (4)(8) = \frac{32}{3} \pi
\]

Answer: \(\boxed{\dfrac{32\pi}{3}}\)

---

Problem 6: Cone


- Radius = 9 in
- Height = 15 in

\[
V = \frac{1}{3} \pi (9)^2 (15) = \frac{1}{3} \pi (81)(15) = \frac{1}{3} \pi (1215) = 405\pi
\]

Answer: \(\boxed{405\pi}\)

---

Problem 7: Square-based Pyramid


- Side = 9 in
- Height = 12 in

Base Area = \( 9 \times 9 = 81 \)

\[
V = \frac{1}{3} \times 81 \times 12 = \frac{972}{3} = 324
\]

Answer: \(\boxed{324}\)

---

Problem 8: Cone


- Radius = 8 cm
- Height = 15 cm

\[
V = \frac{1}{3} \pi (8)^2 (15) = \frac{1}{3} \pi (64)(15) = \frac{1}{3} \pi (960) = 320\pi
\]

Answer: \(\boxed{320\pi}\)

---

Problem 9: Triangular Pyramid


- Base Area = 15 m²
- Height = 20 m

\[
V = \frac{1}{3} \times 15 \times 20 = \frac{300}{3} = 100
\]

Answer: \(\boxed{100}\)

---

## Final Answers Summary:

1. \(\boxed{\dfrac{6250}{3}}\)
2. \(\boxed{847\pi}\)
3. \(\boxed{8960}\)
4. \(\boxed{\dfrac{100}{3}}\)
5. \(\boxed{\dfrac{32\pi}{3}}\)
6. \(\boxed{405\pi}\)
7. \(\boxed{324}\)
8. \(\boxed{320\pi}\)
9. \(\boxed{100}\)

All answers are exact as requested. Let me know if you need any step explained further!
Parent Tip: Review the logic above to help your child master the concept of volume of pyramid worksheet.
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